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PHYSICAL CHEMISTRY, , Race, No., 01, , TOPIC NAME CONTENTS, SOME BASIC CONCEPT OF, , Page, No., 01, , CHEMISTRY (MOLE CONCEPT), 02, , ATOMIC STRUCTURE, , 03, , 03, , CHEMICAL EQUILIBRIUM, , 06, , 04, , IONIC EQUILIBRIUM, , 09, , 05, , THERMODYNAMICS &, , 12, , THERMOCHEMISTRY, 06, , REDOX REACTION, , 15, , 07, , STATE OF MATTER, , 17, , 08, , SOLID STATE, , 18, , 09, , CHEMICAL KINETICS, , 21, , 10, , SOLUTION & COLLIGATIVE, , 24, , PROPERTIES, 11, , ELECTROCHEMISTRY, , 27, , 12, , SURFACE CHEMISTRY, , 30

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SOME BASIC CONCEPT OF CHEMISTRY (MOLE CONCEPT), 1., , The volume of a gas at 0 0 C and 760 mm, pressure is 22.4 cc. The no. of molecules, present in this volume is, (1) 10–3 N A, (2) 10–4 N A, (3) 10–5 N A, (4) 10–2 N A, , 2., , 100 mL of PH3 when completely decomposed, produces phosphorus and hydrogen. The, change in volume of the gas is -, , 8., , 44g of a sample of organic compound on, complete combustion gives 88g CO2 and 36g, of H 2 O. The molecular formula of the, compound may be :(1) C4H6, (2) C2H6O, (3) C2H4O, (4) C3H6O, , 9., , Volume at N.T.P. of 0.22 g of CO2 is same as, that of, (1) 0.01 g of hydrogen, (2) 0.085 g of NH3, (3) 320 mg of gaseous SO2, (4) All the above, , 10., , Which of the following has maximum mass :(1) 0.1 gram atom of carbon, (2) 0.1 mol of ammonia, (3) 6.02 × 10 22 molecules of hydrogen, (4) 1120 cc of carbon dioxide at STP, , 11., , What mass of NaCl would be decomposed by, 98 g of H2SO4 if 120 g of NaHSO4 and 27.5, g of HCl are produced in a reaction. Assuming, that law of mass conservation is true :, (1) 4.95 g (2) 49.5 g (3) 0.495 g (4) 495 g, , 12., , Equal mass of oxgyen, hydrogen and methane, are taken in a container in identical conditions., What is the ratio of their moles :(1) 1 : 16 : 1, (2) 1 : 16 : 2, (3) 8 : 1 : 8, (4) 16 : 1 : 8, , 13., , When 40 cc of slightly moist hydrogen chloride, gas is mixed with 20 cc of ammonia gas the, final volume; of gas left at the same temperature, and pressure will be, NH3(g) + HCl(g), NH4 Cl(s), (1) 20 cc, (2) 40 cc, (3) 60 cc, (4) 100 cc, , 14., , A metal oxide has the formula X2O3. It can be, reduced by hydrogen to give free metal and, water. 0.1596 g of metal oxide requires 6 mg, of hydrogen for complete reduction. The, atomic mass of metal in amu is :(1) 15.58 (2) 155.8 (3) 5.58 (4) 55.8, , P(s) + 3 H2(g), 2, (1) 50 mL increase, (2) 500 mL decrease, (3) 900 mL decrease (4) Does not changes, PH3(g), , 3., , 4., , 5., , The mass of a molecule of water :, (1) 30 × 10–24 kg, (2) 3 × 10–26 kg, –26, (3) 1.5 × 10 kg, (4) 2.5 × 10–27 kg, 19.7 kg of gold was recovered from a, smuggler. How many atoms of gold were, recovered ? (At. wt. of gold (Au) = 197), (1) 100, (2) 6.023 × 10 23, 24, (3) 6.023 × 10, (4) 6.023 × 10 25, Chlorine is prepared in the laboratory by, treating manganese dioxide (MnO 2 ) with, aqueous hydrochloric acid according to the, reaction, 4HCl(aq) + MnO2 (s), 2H2 O( ) + MnCl2 (aq) + Cl 2(g), How many gram of HCl react with 5.0 g of, manganese dioxide ? (At. wt. of Mn = 55), (1) 2.12 g, (2) 44.24 g, (3) 8.4 g, (4) 3.65 g, , 6., , An unknown amino acid has 0.032% sulphur, by wt. If each molecule has one S atom only,, 1 g. of amino acid has ........... molecules :(1) 6.02 × 1018, (2) 6.02 × 1019, (3) 6.02 × 1024, (4) 6.02 × 1023, , 7., , 446 g of PbO, 46 g of NO2 and 16 g of O2 are, allowed to react according to the equation :1, PbO + 2NO2 + O2, Pb(NO3)2, 2, The amount of Pb(NO3)2 that can be produced, is (At. wt. of Pb = 207) :(1) 331 g, (2) 662 g, (3) 165.5 g, (4) 132.5 g, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 1

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TARGET : PRE-MEDICAL 2021, 15., , One atom of an element 'X' weighs 6.664 × 10–23, g. The number of gram atoms in 40 kg of it is, (1) 10, (2) 100, (3) 10000 (4) 1000, , 16., , In the reaction, 4A + 2B + 3C, A4B2C3, what, will be the number of moles of product formed,, starting from 1 mol of A, 0.6 mol of B and, 0.72 mol of C :(1) 0.25 (2) 0.3, (3) 0.24 (4) 2.32, , 17., , If Ca3(PO4)2 and H3PO3 contain same number, of 'P' atom then the ratio of oxygen atoms in, these compounds respectively is :(1) 8/3, (2) 2/3, (3) 3, (4) 4/3, , 18., , The molecular weight of compounds, (a) Na2 SO 4, (b) Na3PO4.12H2 O, (c) Ca3(PO4 )2 resepctively are X, Y and Z., The correct set of equivalent weight will be :(1), , X Y Z, , ,, 2 3 6, , (3) X,, , (2), , Y Z, ,, 3 3, , 21., , HCOOH(aq), H2O( ) + CO(g), H2C2O4(aq), H2O( ) + CO(g) + CO2(g), The mixture of HCOOH and H 2 C 2 O 4 is, decomposed as above. The gas produced is, collected and on treating with KOH solution,, 1, the volume of the gas decreases by, th., 6, Calculate the molar ratio of HCOOH and, H2C2O4 in the original mixture., (1) 1 : 4 (2) 4 : 1 (3) 2 : 1 (4) 1 : 2, , 22., , A gaseous alkane was burnt with oxygen. The, volume of O2 for complete combustion and that, of CO2 formed are in the ratio of 7 : 4. The, molecular formula of alkane is :(1) CH4 (2) C2H6 (3) C3H8 (4) C4H10, , 23., , Two oxides of a metal contain 22.22% and 30%, oxygen by mass respectively. If the formula, of the first oxide is MO, then the formula of, the second oxide is :(1) MO, (2) MO2 (3) M2O3 (4) M2O, , X, Z, , Y,, 2, 3, , (4) X, Y, Z, , 19., , Calcium carbide produces acetylene on, reaction with water. Ethylene can be obtained, by reduction of C2H2. Polythene is produced, by polymerization of C 2 H 4. Calculate the, theoretical yield of polythene per kilogram of, CaC2 :(1) 0.6457 kg, (2) 0.4375 kg, (3) 0.5113 kg, (4) 0.3948 kg, , 20., , In a compound A containing carbon, hydrogen, and oxygen, the % of hydrogen is one sixth, that of carbon which is 1.5 times that of oxygen., What is the simplest formula for the, compound:(1) C2H4O2, (2) C2H4O, (3) C2H6O, (4) CH4O, , PHYSICAL CHEMISTRY, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 1, , 1, , 2, , 4, , 3, , 1, , 3, , 3, , 4, , 4, , 2, , 2, , 1, , 4, , 4, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 4, , 1, , 2, , 2, , 2, , 2, , 3, , Que. 16, Ans, 2, , 3, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , ATOMIC STRUCTURE, 1., , 2., , 3., , 4., , Energy required for the process is :, He+(g), He+2 (g) + e–, The ionisation energy for the H-atom in the, ground state is 2.18 × 10–18 J atom–1, (1) 9.12 × 10–18 J, (2) 8.72 × 10–18 J, (3) 4.72 × 10–20 J, (4) 7.82 × 10–16 J, The difference between n th and (n + 1)th Bohr, orbits' radii of H atom is equal to its (n – 1)th, Bohr orbit's radius. The value of n is :(1) 1, (2) 2, (3) 3, (4) 4, When an electron of mass 6m and charge 6e, moves with a velocity of 7v about the nuclear, charge Ze in a circular orbit of radius 'r'. The, potential energy of the electron will be :(1), , Ze 2, r, , (2), , Ze 2, r, , (3), , 6Ze 2, r, , (4), , 2 2 me 4 Z 2, n2h2, , 6., , 7., , E, , h, m, , (2), , m, h, , (3), , h, P, , (4), , h, 2(KE), , 10., , Which oribital notation does not have spherical, node :(1) n = 2, = 0, (2) n = 3, = 1, (3) n = 3, = 0, (4) n = 1, = 0, , 11., , The difference in angular momentum, associated with the electron in two successive, orbits of hydrogen atom is :(1), , (3), , 12., , (3), , 13., , h, , (2), , h, 2, , h, 2, , (4) (n–1), , h, 2, , If uncertainties in the measurement of position, and momentum are equal, uncertainty in the, measurement of velocity., (1), , The number of photons emitted in 10 hours by, a 60 W sodium lamp ( = 5893 Å) will be :(1) 1.6 × 1024, (2) 3.2 × 1024, (3) 6.4 × 1024, (4) 8 × 1023, The distance between 3 rd and 2 nd orbit of, hydrogen atom :(1) 2.646 × 10–8 cm, (2) 2.116 × 10–8 cm, (3) 1.058 × 10–8 cm, (4) 0.529 × 10–8 cm, , (1), , Hydrogen atoms are excited to n = 4 state, in, the spectrum of emitted radiation, number of, lines in the ultravoilet and visible regions are, respectively :(1) 3, 1, (2) 1, 3, (3) 2, 3 (4) 3, 2, , (4) 1 : 3 3, , A single electron in an ion has ionisation, energy equal to 217.6 eV. What is the total, number of neutrons present in that ion is :(1) 2, (2) 4, (3) 5, (4) 9, , How fast is an electron moving if it has a, wavelength equal to the distance it travels in, one second ?, , 9., , Be+3 and a proton are accelerated by the same, potential, their de-Broglie wavelengths have, the ratio :, (Assume mass of proton = mass of neutron), (1) 1 : 2, (2) 1 : 4, (3) 1 : 1, , 5., , 8., , 1, m, , h, , h, , (2), , 1, 2m, , h, , (4) None of these, , Find out the number of waves made by a Bohr, electron in one complete revolution in its fourth, orbit., (1) 3, (2) 4, (3) 2, (4) 1, , Your Target is to secure Good Rank in Pre-Medical 2021, , 3

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , 14., , If a 1.00 g body is travelling along the x-axis, at 100 cm s –1 within 1 cm s –1 , what is the, theoretical uncertainty in its position (in meter), (1) 5.25 × 10–30, (2) 6 × 10–10, (3) 10 × 10–8, (4) 6.42 × 10 –28, , 21., , A hydrogen atom in an excited state is ionised, by the absorption of radiation with a photon, energy of 1 eV. What is the minimum value of, n for excited state of the atom :(1) 1, (2) 2, (3) 3, (4) 4, , 15., , The ratio of the energy of the electron in ground, state of hydrogen to the electron in first excited, state of Be3+ is :(1) 1 : 4, (2) 1 : 8, (3) 1 : 16, (4) 16 : 1, , 22., , 16., , The amount of energy required to remove, electron from a Li+2 ion in its ground state is, how many times greater than the amount of, energy needed to remove the electron from an, H atom in its ground state ?, (1) 9, (2) 6, (3) 4, (4) 5, , Which of the following statements is correct :(1) (n–1)d subshell has lower energy than ns, subshell, (2) (n–1)d subshell has higher energy than ns, subshell, (3) (n+1)d subshell has lower energy than nf, subshell, (4) nf subshell has lower energy than (n + 2), s subshell, , 23., , Which of the following statements regarding an, orbital is correct :(1) An orbital is a definite trajectory around the, nucleus in which electron can move, (2) An orbital always has spherical trajectory, (3) It is the region around the nucleus where, there is 90% to 95% probability of finding, all electrons in an atom, (4) An orbitals is characterised by the three, distinct quantum numbers n, and m, , 24., , Following transitions occuring in hydrogen, atoms (n 1 < n2 < n3 ), , 17., , What is the difference in wavelengths of the, 4th and 5 th lines of the Balmer series in the, spectrum of atomic hydrogen :(1) 131 Å, (2) 520 Å, (3) 390 Å, (4) 262 Å, , 18., , In a certain electronic transition in the, hydrogen atom from an initial state (i) to a final, state (f) the difference in the orbit radius, (ri – rf) is seven times the Bohr radius. Identify, the transition :(1) 4, 1, (2) 4, 2, (3) 4, 3, (4) 3, 1, , 19., , 20., , 4, , A tennis ball weighing 0.91 kg and an electron, travel with the same velocity of 102 m/sec. The, ratio of their de-Broglie wavelengths will be :(1) 1 : 10–26, (2) 10–26 : 1, (3) 1 : 10 –30, (4) 10–30 : 1, The circumference of the 4th Bohr orbit in, hydrogen atom is 5.32 nm. The de Broglie, wavelength of the electron revolving in this, orbit is :(1) 0.133 nm, (2) 13.3 nm, (3) 1.33 nm, (4) 133 nm, , n1 orbit, , 1, , n2 orbit, , n2 orbit, , 2, , n3 orbit, , n1 orbit, , 3, , n3 orbit, , Which of the following relation is not correct?, (1) 3 = 1 + 2, (2), , 3, , 1, , 2, , (3), , 3, , 1, , 2, , (4) E3 =, 25., , E1 + E2, , In Cr atom the number of electrons having, n + m = 3 are :(1) 5, (2) 6, (3) 7, (4) 8, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 26., , 27., , Two particles A and B are in motion,, wavelength related to particle A is 5 × 10–8 m., If the momentum of particle B is half of A then, what will be the wavelength of B :(1) 2.5 × 10–8 m, (2) 1.25 × 10–8 m, (3) 1 × 10–7 m, (4) 1 × 10–8 m, The value of (n2 + n1) and (n 22, , (1), , 32 R H, 9, , (2), , 9, (3) 32 R, H, , 30., , The magnetic moment (in Bohr magneton) of, Ni2+ in aqueous solution will be :(1) 2.84 (2) 4.90 (3) 0, (4) 1.73, , 31., , With what velocity must an electron travel so, that its momentum is equal to that of photon of, wavelength of = 5200Å ?, (1) 800 ms–1, (2) 1400 ms –1, (3) 400 ms–1, (4) 200 ms–1, , 32., , The angular momentum of an electron is a, Bohr's orbit of H atom is 4.2178 × 10–34 kg-m2/, sec. Calculate the wavelength of spectral line, emitted when electron falls from this level to next, lower level., (1) 1.8 × 10–4 cm, (2) 2.8 × 10–5 cm, (3) 4.6 × 10–4 cm, (4) 2.2 × 10–6 cm, , 33., , A stationary He + ion emitted a photon, corresponding to the first line of the Lyman, series. That photon liberated a photo electron, from a stationary H atom in ground state. What, is the velocity of photo electron ?, RH = 109678 cm–1, (1) 9.1 × 108 cm sec–1, (2) 5.1 × 108 cm sec–1, (3) 6.1 × 108 cm sec–1, (4) 3.1 × 108 cm sec–1, , n12 ) for He ion, , in atomic spectrum are 4 and 8 respectively., The wavelength of emmited photon on, transition of electron from n2 to n1 is :-, , 9 RH, 32, , 32, (4) 9 R, H, , 28., , If the ionization energy of He+ is 19.6×10–18 J, atom –1 , then calculate the energy of first, stationary state of Li2+., (1) – 1.1 × 10–17 J/atom, (2) – 1.1 × 10–18 J/atom, (3) – 4.41 × 10 –17 J/atom, (4) – 4.41 × 10 –18 J/atom, , 29., , Which of the following outer electronic, configurations will cause the achievement of, the highest oxidation state by an atom ?, (1) (n–1)d 10 ns 2, (2) (n–1)d5 ns 1, (3) (n–1)d2 ns 2, (4) (n–1)d8 ns 2, , PHYSICAL CHEMISTRY, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 2, , 4, , 3, , 4, , 3, , 3, , 1, , 1, , 4, , 4, , 2, , 2, , 2, , 1, , 1, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans., , 1, , 1, , 3, , 4, , 3, , 4, , 2, , 4, , 1, , 3, , 3, , 3, , 3, , 2, , 1, , Que., , 31, , 32, , 33, , Ans., , 2, , 1, , 4, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 5

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , CHEMICAL EQUILIBRIUM, , 2., , 3., , 4., , For the reaction, PCl5, PCl3 + Cl2, Initial moles are, a, b, c, If is the degree of dissociation and P is the total, pressure, then the partial pressure of PCl3 is :(1), , b a, a b c a, , P atm., , (2), , a a, a b c a, , P atm., , (3), , a(1 ), a b c a, , P atm., , (4), , a b c a, b a, , P atm., , When sulphur is heated at 800 K, there exists, on equilibrium S 8 (g), 4S 2(g). The initial, pressure of 1 atm. falls by 20% at equilibrium., Find the value of KP for the referred reaction, (1) 0.512 atm3, (2) 2.50 atm3, (3) 1.20 atm3, (4) 3.24 atm3, , Reaction N2O3, NO + NO2 was studied by, –1, taking 2 mol L of N 2 O 3 initially. At, equilibrium degree of dissociation of N2O3 was, found to be 10%. What is the ratio of, equilibrium concentration of [N2O3], [NO] and, [NO2] :, (1) 19 : 1 : 1, (2) 9 : 1 : 1, (3) 1 : 1 : 9, (4) 18 : 1 : 1, , 8., , The equilibrium constant for reaction, H2(g) + CO2(g), H2O(g) + CO(g) is 1·8 at, 1000°C. If one mole of H2 and 1·0 mole of, CO2 are placed in a one litre flask. The final, equilibrium concentration of CO at 1000°C will, be, , e, , 18, , 9., , A, , (1, , (4), , 2), , 2), , The equilibrium constant for the esterification, reaction of acetic acid and ethyl alcohol at, 100°C is 4. What percentage of alcohol has, been esterified ?, (1) 45% (2) 20% (3) 54% (4) 66%, , 10., , In which case the degree of dissociation cannot, be determined by measuring vapour density :, (1) PCl5, (2) N2O4, , PCl3 + Cl2, 2NO2, , (3) 2SO3, 2SO2 + O2, (4) N2 + O2, 2NO, 6, , F, , G, Time, , In the following equilibrium :–, I. A + 2B, C ; K1, II. C + D, , 6., , C, , I. Reaction quotient has maximum value at, point A, II. Reaction proceeds left to right at a point, when [N2 O4] = [NO2 ] = 0.1M, III. Kc = Q when point D or F is reached, (1) I, II, (2) II, III (3) I, III (4) I, II, III, , 2, (1, , E, , D, , B, , (2) 0.5, , 1, , (2) 0·386 M, (4) 0·688 M, , N2O4, 2NO2, Kc = 4. This reversible reaction, is studied graphically as shown in the given, figure. Select the correct statements out of I, II, and III, , The equilibrium constant at a certain temp. for, the reaction A2 + B2, 2AB is 2. Calculate the, degree of dissociation of either A2 or B2 :, , (3), , j, , 1 34 :-, , (1) 0·573 M, (3) 0·290 M, , NaHCO3 decomposes as :, 2NaHCO3(s), Na2CO3(s) + CO2(g) + H2O(g), The equilibrium pressure is 1.04 atm. The K P, for the reaction is :, (1) 0.2704 (2) 2.704 (3) 27.04 (4) 270.4, , (1) 0.2, , 5., , 7., , Concentration, , 1., , III. 6B + D, , 3A ; K2, 2C ; K3 hence :-, , (1) 3K1 × K2 = K3, (2) K13 × K22 = K3, (3) 3K1 × K22 = K3, (4) K13 × K2 = K3, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 11., , S2– ions in alkaline solution react with solid, sulphur to form polyvalent S 2– ions. The, equilibrium constant for the formation of S22–, and S32– from S and S2– ions are 1.7 and 5.3, respectively. Equilibrium constant for the, formation of S32– from S22– :(1) 1.33, (2) 3.11, (3) 4.21, (4) 1.63, , 12., , Consider the following reactions (in gaseous, phase) in equilibrium with equilibrium, concentrations 0.1 M of every species :(I) 2SO2 + O2, (II) N2 + 3H2, (III) N2 O4, , 15., , The equilibrium constant for the reaction, H2(g) + S (s), H2S(g) ; is 18.5 at 925 K and, 9.25 at 1000 K respectively. The enthalpy of, the reaction will be :, (1) – 68000.05 J mol–1 (2) –71080.57 J mol–1, (3) – 80071.75 J mol–1 (4) 57080.75 J mol–1, , 16., , 0.5 mole of H2(g) and 1 mole of HI (g) (but no I2), are added to a 1.0 L vessel and allowed to reach, equilibrium according to the following, reaction : H2 + I2, 2HI(g)., If x is the equilibrium concentration of I2(g). the, correct equilibrium constant expression is :, , 2SO3 ;, 2NH3 ;, 2NO2 ;, , (IV) 4NO + 6H2 O, , (1), , 4NH3 + 5O2, , Extent of reaction will be in order :, (1) I = II, , PHYSICAL CHEMISTRY, , x(0.5 x), (1 2x)2, , (2), , x(2 x)2, (3), (0.5 x), , III = IV, , (2 x)2, (0.5 x)2, , (1 2x)2, (4), (0.5 x)x, , (2) I = II = III < IV, (3) III < I = IV < II, , 17., , The preparation of SO3(g) by reaction, , (4) IV < III < I < II, SO2(g) +, , 14., , 2NOBr(g), 2NO(g) + Br 2 (g). If nitrosyl, bromide (NOBr) is 40% dissociated at certain, temp. and a total pressure of 0.30 atm. Kp for, the reaction 2NO(g) + Br2(g), 2NOBr(g) is, (1) 45, (2) 25, (3) 0.022, (4) 0.25, , 3, 2, , Mole %, , 18., , 80, , A, , 60, 40, , B, , 20, , The value of equilibruium constant is :, (1) 2, (2) 0.67, (3) 0.75, (4) 1.25, , 1, , The conversion of ozone into oxygen is, exothermic. Under what conditions is ozone, the most stable ?, 2O3 (g), , Time, , E, , is an exothermic reaction., 50, T, If the preparation follows 40, T, the following temperature- 30, T, 20, pressure relationship for its 10, 1 2 3 4, % yield, then for, Pressure (atm), temperatures T1, T2 and T3., The correct option is : (1) T3 > T2 > T1 (2) T1 > T2 > T3, (3) T1 = T2 = T3, (4) Nothing could be predicted about, temperature through given information., , Consider the reaction : A(g), B(g)., One mole of A(g) is placed in a 1.0 L flask and, the reaction is allowed to reach to equilibirum., A graph of the mole percent of A(g) and B(g), versus time is shown below :, 100, , SO3(g), , % yield, , 13., , 1, O (g), 2 2, , (1), (2), (3), (4), , At, At, At, At, , 3O2 (g), , low pressure and low temperature, high pressure and high temperature, high pressure and low temperature, low pressure and high temperature, , Your Target is to secure Good Rank in Pre-Medical 2021, , 7

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TARGET : PRE-MEDICAL 2021, 19., , A mixture of N2 and O2 has a concentration of, 0.25 moles/litre at 273 K. If the mole fraction, of nitrogen is 0.59, find the partial pressure of, nitrogen and oxygen :(1) 3.3, 2.3, , (2) 4.3, 2.3, , (3) 5.3, 4.3, , (4) 2.3, 3.3, , 20., , PHYSICAL CHEMISTRY, , 3.2 g of O2 gas and 0.2 g H2 gas are placed in, a 1.12 L flask at 0°C. Then find out total, pressure of gas mixture :, (1) 9 atm (2) 1 atm (3) 5 atm (4) 4 atm, , ANSWER KEY, , 8, , Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 1, , 1, , 1, , 3, , 4, , 4, , 2, , 1, , 2, , 4, , 2, , 3, , 1, , 2, , 2, , Que., , 16, , 17, , 18, , 19, , 20, , Ans., , 4, , 2, , 2, , 1, , 4, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , IONIC EQUILIBRIUM, 1., , 2., , 3., , pH of 0.01 M ammonium cyanide solution is, 7.02. If 5 litres of water is added to this solution,, the pH becomes :, (1) > 7.02, (2) < 7.02, (3) It is difficult to predict, (4) 7.02, pOH = 7 – 0.5 pKa + 0.5 pKb, is true for which, pair of cation and anion :, (1) C6H5NH3+, CH3COO–, (2) Na+, CN–, (3) Al+3, Cl –, (4) NH4+, NO3–, , (3), , 5., , 6., , 7., , E, , Which of the following solution will have pH, close to 1.0 ?, (1) 100 mL. of, , M, M, HCl + 100 mL of, NaOH, 10, 10, , (2) 55 mL. of, , M, M, HCl + 45 mL of, NaOH, 10, 10, , (3) 10 mL. of, , M, M, HCl + 90 mL of, NaOH, 10, 10, , (4) 75 mL. of, , M, M, HCl + 25 mL of, NaOH, 5, 5, , Expression to evaluate solubility for Hg2Cl2 is, (1), , 4., , 8., , K sp, , 1/ 5, , (2) K sp, , 108, K sp, , 1/ 3, , (4), , 4, , K sp, , 1/ 2, , w, M, , (3) 10 5, , w, M, , 10., , Saccharin (K a = 2 × 10 –12) is a weak acid, represented by the formula Hsac. 4 × 10–4 mole, amount of saccharin is dissolved in 200 cm 3, water of pH = 3. Assuming no change in, volume. Calculate the concentration of Sac –, ions in the resulting solution :, (1) 2 × 10–12, (2) 3 × 10–12, (3) 4 × 10–12, (4) 5 × 10–12, , 11., , The amino acid glycine exists predominantly, in the form NH3+CH2COO– its conjugate base, and conjugate acid will be respectively :, (1) NH2CH2COO–, NH3+CH2COOH, (2) NH2CH2COOH, NH2CH2COO–, (3) NH3+CH2COOH, NH2CH2COO–, (4) None, , 12., , Urine normally has a pH of 6. If a patient, eliminates 1.3 litre of urine per day. How many, moles of H+ ions does he urinate ?, (1) 1.3 × 10–3, (2) 1.3 × 10–4, (3) 1.3 × 10–7, (4) 1.3 × 10–6, , 16, , 5, , (2) 10 7, 5, , (4) 10 3, , 5, , w, M, w, M, , 5, , HX is a weak acid (Ka = 10–5). It forms a salt, NaX (0.1 M) on reacting with caustic soda. The, degree of hydrolysis of NaX is :, (1) 0.01%, (2) 0.0001%, (3) 0.1%, (4) 0.5%, CH3COOH + H2O, In the above process,, acid is :, (1) H2O, (3) CH3COOH, , Which of the following will act as a buffer :, (a) NaCl + NaOH, (b) Borax + boric acid, (c) NaH2PO4 + Na2HPO4, (d) NH4Cl + NH4OH, (1) b, c and d, (2) b and c, (3) a, c and d, (4) b and d, , 1/ 4, , If the solubility of calcium phosphate, (molecular weight M) in water at 25°C is, w g per 100 mL, its solubility product at 25°C, is approximately :, (1) 10 9, , 9., , CH3COO– + H3O+, conjugate base of strong, (2) CH3COO–, (4) H3O+, , The pH of a solution is 13. What is the number, of H+ ions in 1 mL of the solution ?, (1) 6.02 × 1023, (2) 6.02 × 1013, 7, (3) 6.02 × 10, (4) 6.02 × 1010, , Your Target is to secure Good Rank in Pre-Medical 2021, , 9

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TARGET : PRE-MEDICAL 2021, 13., , 14., , Consider the following :, A. Sodium acetate, B. Acetic acid + Sodium acetate, C. Acetic acid, The pH of their equimolar aqueous solutions, will be such that :, (1) C < B < A, (2) B < A < C, (3) A < B < C, (4) C < A < B, Water contains dissolved CO2, its reaction with, water is represented as :, CO2 + 2H2O, H3O+ + HCO3–, KC for the reaction is 3.8 × 10–7 and pH = 6., , 17., , A certain acidic indicator has pH = 5.48., 75% of the indicator exists in its ionised from., Calculate Ka of the indicator., (1) 1 × 10–5, (2) 2 × 10–5, (3) 1 × 10–3, (4) 4 × 10–5, , 20., , The conjugated base of (CH3)2N H2 is :2, , (2) (CH3)2 N H, (4) (CH3)NH2, , (1) CH 3NH2, (3) (CH3)2NH, , Nicotinic acid (Ka = 10–5) is represented by the, formula HNiC. Calculate percent dissociation, in a solution which contains 0.1 mol of nicotinic, acid per 2 litre of solution :, (1) 1.4% (2) 1.6% (3) 2.4% (4) 3.4%, , Two sparingly soluble salts AX and BX2 have, their solubility product constants equal. Which, of the following is incorrect ?, (1) Solubility of AX is less than solubility of BX2, (2)If S1 and S2 are molar solubility of AX and, BX2 then S1 = 2(S 2 )2/3, (3)If X is a conjugate base of a weak acid, addition of HNO3 will increase solubility of, both AX and BX2, (4)Increasing the temperature, increases the, solubility of both AX and BX2, , 22., , Calculate the pH at equivalence point when a, solution of 0.1 M CH3COOH is titrated with a, solution of 0.1 M KOH., (Ka of CH3COOH = 2 × 10–5), (1) 5.3, (2) 7.3, (3) 10.7, (4) None of these, , What is the % dissociation of 0.01N NH4OH in, its buffer solution containing 0.01N NH4Cl :(Kb of NH4OH = 2 × 10–5 ), (1) 0.2%, (2) 2 × 10–3 %, (3) 2 × 10–5, (4) 5 × 10–3 %, , 23., , Acetyl salicylic acid called aspirin (shown in, figure) is a pain killer with pKa = 4. If two, tablets each of 0.09 g mass containing aspirin, are dissolved in 100 mL solution. Its pH will, be, , On the addition of a solution containing CrO 24, ions to the solution of Ba2+, Sr2+ and Ca2+ ions,, the precipitate obtained first will be of :(1) CaCrO4, (2) SrCrO4, (3) BaCrO4, (4) A mixture of all three, , 24., , Silver ions are added to a solution with, , (1) 3.8 × 10–1, (3) 6.0, , 16., , 19., , 21., , What is the value of, , 15., , PHYSICAL CHEMISTRY, , [HCO 3– ], ?, [CO 2 ], (2) 3.8 × 10–13, (4) 3.8, , [Br–] = [Cl–] = [ CO32– ] = [ AsO34 ] = 0.1M., , OCOCH3, , Which compound will precipitate with lowest, [Ag+] ?, , COOH, , (1) AgBr(Ksp = 5 × 10–13), (1) 0.5, 18., , (2) 1.0, , (3) 1.8, , (4) 3, , Calculate the solubility of silver phosphate, (Ag3PO4) in 0.1 M AgNO3, (Ksp of Ag3PO4 = 1.1 × 10–16) :-, , 10, , (2) AgCl(Ksp = 1.8 × 10–10), , (1) 1 × 10–8 M, , (2) 4 × 10–15 M, , (3) 1.1 × 10–15 M, , (4) 1.1 × 10–13 M, , (3) Ag2CO3(Ksp = 8.1 × 10–12), (4) Ag3AsO 4(Ksp = 1 × 10–22), 25., , Find the pH of, 25 mL, 0.5 M, NaOH solution, (1) 1.82, (2), , a solution obtained by mixing, HCl solution, 10 mL, 0.5 M, and 15 mL of water :0.48, (3) 0.82, (4) 12.1, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 26., , At 25°C, Ksp for PbBr2 is equal to 8 × 10–5. If, , 30., , How many mole of HCN will be required to, prepare one litre buffer solution of pH = 10.4, using 0.01 mol NaCN ?, (Given Ka(HCN) = 4 × 10–10), (1) 2 × 10–2 mol, (2) 1 × 10–3 mol, (3) 4 × 10–4 mol, (4) 9 × 10–3 mol, , 31., , The pH of two equimolar weak acids are 3 and, 5 respectively. Their relative strength is :(1) 3 : 5, (2) 5 : 3, (3) 100 : 1, (4) 1 : 100, , 32., , 400 mL of 0.1 M KCN and 200 mL of 0.1 M, HCl are mixed at 25°C. Determine the pH of, the mixture. (pKa for HCN = 6), (1) 8, (2) 4, (3) 6, (4) 2, , 33., , How many gram of H2SO4 should be removed, from 1 L of its aqueous solution of pH = 2 to, increase its pH upto 3., (1) 49 g, (2) 9.8 g, (3) 0.49 g, (4) 0.441 g, , 34., , 4 L of 0.1 M NaCl is added to 1 L of 0.25 M, CH 3COONa at 25°C. Determine [OH – ] in, the mixture if K b for CH 3COO – at 25°C is, 5 × 10–10., (1) 5 × 10–6 M, (2) 2.5 × 10–10 M, –6, (3) 2.5 × 10 M, (4) 2 × 10–6 M, , 35., , The solubility of Pb(OH) 2 in water is, 5 × 10–6 M. Calculate the solubility of Pb(OH)2, in a buffer solution of pH = 8 at 25°C., (1) 2.5 × 10–4 M, (2) 5 × 10–16 M, –4, (3) 5 × 10 M, (4) 2.5 × 10–16 M, , the salt is 80% dissociated, what is the solubility, of PbBr2 in mol L–1 ?, , 27., , 1/ 3, , (1), , 10–4, 1.6 1.6, , 1/ 3, , (3), , 10 –4, 0.8 0.8, , 1/ 3, , (2), , 10–5, 1.6 1.6, , 1/ 2, , (4), , 10–5, 1.6 1.6, , The pH of 0.5 M NaCN solution is, (Ka of HCN = 5 × 10–10), , 28., , (1) 11.5, , (2) 2.5, , (3) 12.5, , (4) 1.5, , PHYSICAL CHEMISTRY, , The species present in solution when CO2 is, dissolved in water :(1) CO2, H2CO3, HCO3–, CO3–2, (2) H2CO3, CO3–2, (3) CO3–2, HCO3–, (4) CO2, H2CO3, , 29., , What is the maximum concentration of, equimolar solutions of FeSO4 and Na2S so that, when mixed in equal volumes, there is no, precipitation of FeS?, (Ksp of FeS = 6.25 × 10–18), (1) 5 × 10–9 M, , (2) 5 × 10–8 M, , (3) 5 × 10–18 M, , (4) 5 × 10–9 M, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 4, , 1, , 3, , 2, , 1, , 1, , 3, , 4, , 1, , 3, , 1, , 4, , 1, , 1, , 1, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans., , 4, , 4, , 4, , 1, , 3, , 2, , 1, , 3, , 1, , 3, , 1, , 1, , 1, , 1, , 2, , Que., , 31, , 32, , 33, , 34, , 35, , Ans., , 3, , 3, , 4, , 1, , 3, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 11

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TARGET : PRE-MEDICAL 2021, 14., , 15., , 16., , 17., , 18., , E, , Consider the following statements :, I. Change in state function between two states, is a definite quantity and does not depend, on path., II. Intensive properties can't be algebraically, added or subtracted., III. Ratio of two extensive properties result into, a parameter that depends on amount of, substance., IV. Molar heat capacity is an intensive, property., The correct order of true / false of the above, statements is, (1) F T F T, (2) F F F T, (3) T T F T, (4) T T T F, Consider the following statements :I., G is negative for a physical process, H2O(l) H2O(s) at – 20°C., II. Molar entropy of vapourisation of ice is, negative., III. In adiabatic free expansion, heat involved, is zero and therefore entropy change will, be zero., IV. At absolute zero temperature, entropy of a, pure perfectly crystalline substance is zero., The correct order of true / false of the above, statements is, (1) T T T T, (2) T F T T, (3) F F F T, (4) T F F T, ( H – E) is maximum at a given temperature, in case of :(1) PCl5(g), PCl3(g) + Cl2(g), (2) CaCO3(s), CaO3(s) + CO2(g), (3) NH4HS(s), NH3(g) + H2S(g), (4) N2(g) + O2(g), 2NO(g), , 19., , Temperature of 1 mol of a gas is increased by, 1ºC at constant pressure. The magnitude of, work done is :(1) R, , (2) 2 R, , (3), , R, 2, , (4) 3 R, , 20., , Sign of G for the melting of ice is negative at, (1) 265 K, (2) 270 K, (3) 271 K, (4) 274 K, , 21., , When one mole of an ideal gas is compressed, to half its initial volume and simultaneously, heated to twice its initial temperature, the, change in entropy ( S) is :(1) CV ln 2, (2) CP ln 2, (3) R ln 2, (4) (Cv – R) ln 2, , 22., , What are the signs of the entropy charge, (+ or –) in the following :I : A liquid crystallises into a solid, II : Temperature of a crystalline solid is raised, from 0 K to 115 K, III : 2NaHCO3(s), Na2CO3(s)+CO2(g)+H2O(g), IV : H2(g), 2H(g), I II III IV, I II III IV, (1) – +, +, + (2) – –, –, +, (3) – –, –, + (4) + –, –, –, , 23., , Consider following reactions :I : N2 + O2, 2NO, II : 2CO + O2, 2CO2, III : 2H2O + O2, 2H2O2, IV : PCl3 + Cl2 PCl5, , Which has the highest entropy per mol of the, substance :(1) H2 at 25ºC and 1 atm, (2) H2 at STP, (3) H2 at 100 K and 1 atm, (4) H2 at 0 K and 1 atm, One mol of NaCl(s) on melting absorbed, 30.5 kJ of heat and its entropy is increased by, 28.8 J K–1. What is the melting point of sodium, chloride :(1) 750 K (2) 1059 K (3) 1332 K (4) 786 K, , PHYSICAL CHEMISTRY, , H=, H=, H=, H=, , x1, x2, x3, x4, , H, 2, (2) IV, (4) I, , In which case(s), Hf =, (1) I, II, III, (3) II, III, 24., , Calorific value of H2 is – 143 kJ g–1, Hence,, , Hof of H2O is :(1) – 143 kJ mol–1, (3) + 143 kJ mol–1, , Your Target is to secure Good Rank in Pre-Medical 2021, , (2) – 286 kJ mol–1, (4) + 286 kJ mol–1, 13

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TARGET : PRE-MEDICAL 2021, 25., , Heat of combustion of CH4 at 25ºC and 1 atm, constant pressure is – 210 kcal mol–1, CH4(g) + 2O2(g), , 28., , CO2(g) + 2H2O(l), , (1) –210 kCal mol, , (3) –208.8 kCal mol, , (2) –198 kCal mol, –1, , The enthalpy change for which of the following, processes represents the enthalpy of formation, of AgCl :(1) Ag+ (aq) + Cl– (aq), , Hence, heat of combustion at constant volume, is :–1, , (3) Ag(s) +, , –1, , In the following reaction, involving, neutralisation of HF (a weak acid) with NaOH, (a strong base)., HF(aq) + NaOH(aq), , 29., , NaF(aq) + H2O(l), Hº = – 68.6 kJ mol–1, , This values is much higher than the heat of, neutralisation of strong acid with strong base, (= – 57.3 kJ mol–1). This is due to :, , Au(s) + AgCl(s), , 1, Cl2(g), 2, , (4) AgCl(s), 26., , AgCl(s), , (2) Ag(s) + AuCl(s), , –1, , (4) –211.2 kCal mol, , PHYSICAL CHEMISTRY, , AgCl(s), , 1, Cl (s), 2 2, , Ag(s) +, , In the reactions, I : H2, , 2H,, , II : H2 +, , 1, O, 2 2, , H = 436 kJ, H2O,, , H = – 241.81 kJ, , III : 2H + 1 O2, H2O,, H=?, 2, H2O can be formed either by II or III. Ratio of, enthalpy change in III to II is :-, , (1) In aqueous solution, HF behaves as a strong, acid, , (1) 2.8, , (2) 0.36, , (3) 1.2, , (4) 0.82, , –, , (2) There is hydration of F ion in aqueous, solution, and the process is exothermic, , 30., , (3) Both (a) and (b), (4) Can't be predicted, 27., , In a closed container of 1.0 litre capacity 2 mole, of CO and 1 mole of O2 gases at 500 K and 70, atm react to form 2 mole of CO 2 gas. The, pressure decreases to 40 atm at 500 K due to, the following reaction :, 2CO + O2, , 2CO2;, , 5 moles of a gas (assuming ideal) expand, adiabatically and reversibly by doing work of, 250 R and undergo the decrease in temperature, of 20°C. The gas is :(1) He, , 31., , H = – 560 kJ, , Calculate U for the reaction at 500 K., 1 litre-atm = 0.1 kJ. All the above gases show, significant deviations from ideal gas behaviour., , (2) CO, , (3) NH3, , (4) CO2, , In a galvanic cell 1 mol electrons move from, anode to cathode at 500 K causing the potential, difference of 20V. What is Suniverse during the, phenomenon ?, (1) –2460 JK–1, , (2) –3860 JK–1, , (3) +2460 JK–1, , (4) +3860 JK–1, , (1) –557 kJ (2) –590 kJ (3) +557 kJ (4) +590 J, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 3, , 1, , 4, , 1, , 1, , 4, , 1, , 3, , 3, , 3, , 4, , 3, , 1, , 3, , 4, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans., , 3, , 1, , 2, , 1, , 4, , 4, , 1, , 4, , 2, , 3, , 2, , 1, , 3, , 1, , 2, , Que., , 31, , Ans., , 4, , 14, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , REDOX REACTION, 1., , When ferrous oxalate is titrated against, 2–, 2–, K2Cr2O7, meq. of Fe2+, C2O4 and Cr2O7 in the, redox reaction are X, Y and Z respectively,, then:(1) X = Y, (2) X + Y = Z, (3) X + 2Y = Z, (4) 2X + 6Y = 6Z, , 2., , Match incorrect equivalent mass of reactant in, following column ? (M = molar mass of, reactant):Column-I, Column-II, (1) FeS2, , Fe3+ + SO3, , M, 15, , (2) P2H4, , P 4H2 + PH3, , 5M, 6, , (3) 2Mn+7, , Mn2+ + Mn+6, , (4) Ba(MnO 4)2, , H, , Mn2+, , M, 3, M, 5, , 3., , What mass of MnO2 is reduced by 35 mL of, 0.16 N oxalic acid in acidic solution ? The, skeleton equation is :MnO2 + H+ + H2C2 O4, CO2 + H2 O + Mn2+, (1) 8.7 g (2) 0.24 g (3) 0.84 g (4) 43.5 g, , 4., , How many gram of KMnO4 are contained in, 4 litre of 0.05 N solution. The KMnO4 is to be, used as an oxidant in acidic medium ?, (1) 1.58 g, (2) 15.8 g, (3) 6.32 g, (4) 31.6 g, , 5., , 6., , A compound contains element X,Y,Z with, oxidation no. +3, +5 and –2 respectively. What, will be possible formula of compound, containing above element., (1) XYZ, (2) Y2 (XZ3) 2, (3) X3 (YZ4) 3, (4) X3 (Y4 Z) 2, Which of the following can only acts as, oxidising agent?, (1) KMnO4, (3) H2 O 2, , E, , (2) K2 MnO4, (4) SO2, , 7., , How many mole of FeSO4, H2C2O4 and FeC2O4, are oxidised separately by one mole of KMnO4, in acidic medium respectively :(1) 5 ; 5/2 ; 5/3, (2) 2/5 ; 2 ; 5, (3) 5/3 ; 3/5 ; 2/5, (4) 3/5 ; 2 ; 5, , 8., , Which of the following reagent can act as, reducing agent with SO2 :(1) F 2, (2) KMnO4, (3) HNO3, (4) H2 S, , 9., , Which of the following is not a, disproportionation reaction :(1) P4 + NaOH, NaH2PO2 + PH3, (2) BaC2 + N2, Ba(CN)2, (3) Hg2I2, HgI2 + Hg, –, –, ClO(aq), (4) Cl 2 (g) + 2OH–(aq), + Cl(aq), + H2 O, , 10., , Which of the, Compound, (a) AlF3, (b) P4O10, (c) HClO4, (d) S4O62–, (a), (1) P, (2) S, (3) S, (4) P, , 11., , When BrO 3 – ion reacts with Br – in acidic, medium, Br2 is liberated. The equivalent weight, of Br2 in this reaction is :(1), , 12., , 5M, 8, , (2), , following is correctly match:–, Oxidation number, (P) +2.5, (Q) +7, (R) +5, (S) +3, (b), (c), (d), Q, R, S, R, Q, P, R, P, Q, Q, S, R, , 5M, 3, , (3), , 3M, 5, , (4), , 4M, 6, , An element 'A' in a compound ABD has, oxidation number –n. It is oxidised by, Cr2 O72– in acidic medium. In the experiment, 1.68 × 10–3 moles of K2Cr 2 O7 were used for, 3.36 × 10–3 moles of ABD. The new oxidation, number of A after oxidation is :(1) 3, (2) 3 – n, (3) n – 3, (4) + n, , Your Target is to secure Good Rank in Pre-Medical 2021, , 15

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , STATE OF MATTER, 1., , 20 L of SO2 gas in diffused in 120 sec. Then find, out the volume of O2 gas to diffuse in 60 sec., (1) 14.14 L, (2) 12.12 L, (3) 18.18 L, (4) 20 L, , 2., , An unknown gas, X, has rate of diffusion, measured to be 0.88 times that of PH3 at the, same conditions of T and P. The gas will be :(1) C2H6 (2) CO, (3) NO2 (4) N2O, , 3., , 8., , X mL of H2 gas effuses through a hole in a, container in 5 seconds. The time taken for the, effusion of the same volume of gas specified, below under identical condition is :(1) 10 seconds, helium, (2) 20 seconds, oxygen, (3) 25 seconds, carbon monoxide, (4) 55 seconds, carbon dioxide, , 9., , Select the gas which can be liquefied :(1) Gas obeying P(V–b) = RT, (2) Gas obeying PV = RT, , Under what conditions will a pure sample of, ideal gas not only exhibit a pressure of 1 atm,, but also a concentration of 2 moles per litre :(1) At STP, (2) When V = 22.4 litres, (3) When R has no units, (4) At 6.1 K, , a, [V b] RT, V2, (4) Gas obeying rigidly Maxwell velocity, distribution curves, , (3) Gas obeying, , 10., 4., , The compressibility factor (z) of an ideal gas is :, (1) 0, (2), (3) –1, (4) 1, , The critical volume of a gas is 0.072L mol–1., The radius of gas molecule will be :, 1/ 3, , (1), 5., , 6., , 7., , Gas A diffuses 5 times faster than gas B. Then, find out the ratio of density of A and B :, (1) 25 : 1 (2) 5 : 1 (3) 1 : 25 (4) 5 : 1, The compression factor (compressibility factor), for one mole of a van der Waal's gas at 0°C, and 100 atmosphere pressure is found to be, 0.5. Assuming that the volume of a gas, molecule is negligible, calculate the van der, Waals' constant 'a'., (1) 1.253 L2mol–2atm (2) 2.501 L2mol–2atm, (3) 3.753 L2mol–2atm (4) 4.210 L2mol–2atm, , P, , (3), , 4, , 10, , 23, , cm, , (2), , 4, 3, , 1/ 3, , 10, , 23, , 1/ 3, , 3, 4, , 10, , 23, , cm, 1/ 3, , cm (4), , 2, , 10, , 23, , cm, , 11., , The critical temperature and critical density of, CO2 are 27°C and 0.45 g cm –3 respectively., The van der Waal's constant 'a' is :(1) 0.22 L2 atm mol–2 (2) 1.23 L2 atm mol–2, (3) 2.71 L2 atm mol–2 (4) 3.15 L2 atm mol–2, , 12., , For H 2 and He, the approximation of the, vander Waal's equation at any pressure (P > 0), is:-, , A mixture of CH4 and HBr, in a vessel are, allowed to effuse out through a small hole at, the constant temperature. What is the mole, fraction of CH4, if the initial rates of effusion, are the same for both gases (atomic weight of, Br = 80) :(1) 0.31 (2) 0.44 (3) 0.69 (4) 0.16, , (1), , P, , a, V RT (2) PV = RT, V2, , (3) PV – Pb = RT, , (4) PV = Pb – RT, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , Ans., , 1, , 4, , 4, , 4, , 3, , 1, , 3, , 2, , 3, , 3, , 3, , 3, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 17

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SOLID STATE, 1., , Lithium crystallizes as body centered cubic, crystals. If the length of the side of unit cell is, 350 pm, the atomic radius of lithium is :(1) 303.1 pm, (2) 606.2 pm, (3) 151.5 pm, (4) 123.7 pm, , 2., , Each edge of a cubic unit cell is 400 pm. If, atomic weight of the element is 120 and it's, density is 6.25 g/cm3. The crystal lattice is :, (use NA = 6 × 1023), (1) primitive, (2) body centered, (3) face centered, (4) end centered, , 3., , An element crystallizes in a face centered cubic, lattice crystal and the edge of the unit cell is, 0.559 nm. The density is 3.19 g/cm3. What is, the atomic weight ?, (1) 87.6, (2) 79.9, (3) 85.5, (4) 83.9, , 7., , A certain sample of cuprus sulphide is found, to have composition Cu 1.8 S, because of, presence of some Cu2+ ions in the lattice. What, is the mole % of Cu2+ in crystal ?, (1) 99.8%, (2) 11.11%, (3) 88.88%, (4) None of these, , 8., , When heated above 916ºC, iron changes its, bcc crystalline form to fcc without the change, in the radius of atom. The ratio of density of, the crystal before heating and after heating is :, (1) 1.069 (2) 0.918 (3) 0.725 (4) 1.231, , 9., , Ferrous oxide has a cubic structure and edge, length of the unit cell is 5.0 Å. Assuming the, density of ferrous oxide to be 3.84 g/cm3, the, number of Fe2+ and O2– ions present in each, unit cell be : (use NA = 6 × 1023) :(1) 4 Fe2+ and 4 O2–, (2) 2 Fe2+ and 2 O2–, , 4., , 5., , 6., , 18, , An element X (Atomic weight. = 80 g/mol), having fcc structure, calculate number of unit, cells in 8 gm of X :, (1) 0.4 × NA, (2) 0.1 × NA, (3) 4 × NA, (4) None of these, In the spinel structure, oxides ions are cubicalclosest packed whereas 1/8th of tetrahedral, voids are occupied by A2+ cation and 1/2 of, octahedral voids are occupied by B3+ cations., The general formula of the compound having, spinel structure is :, (1) A2B2O4, (2) AB2O4, (3) A2B4O2, (4) A4B2O2, In sodium chloride crystal, the number of next, nearest neighbours of each Na+ ions is :(1) 8 Cl– ions, (2) 12 Na+ ions, (3) 12 Cl– ions, (4) 24 Cl– ions, , (3) 1 Fe2+ and 1 O2–, (4) 3 Fe2+ and 4 O2–, 10., , An element X (atomic weight = 24 g/mol), forms a face centered cubic lattice. If the edge, length of the lattice is 4 × 10–8 cm and the, observed density is 2.40 × 103 kg/m3, then the, percentage occupancy of lattice points by, element X is : (Use NA = 6 × 1023) :, (1) 96, (2) 98, (3) 99.9, (4) None of these, , 11., , In fcc lattice, A, B, C, D atoms are arranged at, corner, face centre, octahedral void and, tetrahedral void respectively, then the body, diagonal contains :(1) 2A, C, 2D, (2) 2A, 2B, 2C, (3) 2A, 2B, 2D, (4) 2A, 2D, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 12., , 13., , 14., , A crystal is made of particles X, Y and Z. X, forms fcc packing. Y occupies all the octahedral, voids of X and Z occupies all the tetrahedral, voids. If all the particles along one body, diagonal are removed then the formula of the, crystal would be :(1) XYZ, (2) X2YZ2, (3) X8Y4Z5, (4) X5Y4Z8, CdO has NaCl structures with density 8.27 gcm–3., If the ionic radius of O2– is 1.24 Å, determine, ionic radius of Cd2+ (moler mass of CdO = 128), (1) 1.5 Å, (2) 1.01 Å, (3) 1.9 Å, (4) 1.7 Å, , An ionic compound AB has fluorite type, structures. If the radius of B– is 200 pm, then, the radius of A+ would be :(1) 82.8 pm, (2) 146.4 pm, (3) 40 pm, (4) 45 pm, , 16., , Calculate the number of atoms in a cubic unit, cell having one atom on each corner and two, atoms at each body diagonal :(1) 8, (2) 9, (3) 6, (4) 3, , B, A, , The formula of solid is :(1) ABC (2) AB2C2 (3) A2BC (4) AB8C2, 20., , In a face centred cubic arrangement of A and, B atoms, atoms of A are at the corner of the, unit cell and atoms of B are at the face centres., One of the A atom is missing from one corner, in unit cell. The simplest formula of compound, is :(1) A7B3 (2) AB3, (3) A7B24 (4) A7/8B3, , 21., , In an ionic crystal A forms cubical close, packing and B atoms are present at every, tetrahedral voids. If any sample of crystal, contain 'N' number of B atoms then number of, A atoms in that sample is :N, (1) N, (2), (3) 2 N, (4) 2N, 2, , 22., , In certain solid, the oxide ions are arranged in, 1, ccp. Cations A occupy, of the tetrahedral, 6, voids and cations B occupy one third of the, octahedral voids. The probable formula of the, compound is :-, , Find out formula of compound having spheres, A, B and C. A is present at each element of, ccp, B occupies 50% of octahedral voids and, C occupies 50% of tetrahedral voids :(1) AB3C (2) A2BC4 (3) AB4C (4) A2BC2, 23., , 18., , E, , In corrundum, the oxide ions form the, hexagonal close packing and aluminuum ions, occupy two third of the octahedral voids. What, is the emprical formula of corrundum :(1) Al6O4 (2) Al2O3 (3) AlO2 (4) Al2O, , A solid ABC has A, B and C arranged as below., C, , Dopping of KCl crystals with CdCl2 results in, (1) Schottyky defect, (2) Frenkel defect, (3) Substitutional cation vacancy, (4) Formation of F-centres, , 15., , 17., , 19., , PHYSICAL CHEMISTRY, , (1) ABO3, , (2) AB2O3, , (3) A2BO3, , (4) A2B2O3, , A mineral having formula AB2 crystallises in, the cubic close packed lattice, with the A atoms, occupying the lattice points of CCP. Hence, coordination number of A and B atoms are :(1) 4, 8, , (2) 4, 4, , (3) 8, 8, , (4) 8, 4, , Your Target is to secure Good Rank in Pre-Medical 2021, , 19

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TARGET : PRE-MEDICAL 2021, 24., , Number of formula units in unit cell of MgO, (rock salt type), ZnS (zinc blende) respectively, (1) 4, 3, , 25., , 27., , (3) 4, 4, , (4) 4, 3, , An element crystallises in a 'bcc' lattice. Nearest, neighbours and next nearest neighbours of the, elements are respectively :(1) 8, 8, , 26., , (2) 4, 3, , 28., , (2) 8, 6, , (3) 6, 8, , PHYSICAL CHEMISTRY, , A solid AB crystallises in NaCl structure. The, anion B– form fcc lattice, while the cation A+, occupy all the octahedral holes. If all the, particles as shown in the figure are removed,, then the formula of solid becomes :-, , (4) 6, 6, , Number of unit cells in 10 g NaCl :(1), , 10 N A, 58.5, , (2), , 2.5, NA, 58.5, , (3), , 5.6, NA, 58.5, , (4), , 5.6, NA, 58.5, , (1) AB, , (2) A5B7, , (3) A7B5, , (4) AB2, , In the cubic crystal of CsCl (d = 3.97 g cm–3), the eight corners are occupied by Cl– with a, Cs+ at the centre and vice-versa. What is the, radius ratio of the two ions ? (Atomic mass of, Cs = 132.91 and Cl– = 35.45), (1) 0.16, , (2) 0.24, , (3) 0.73, , (4) 0.88, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 3, , 2, , 4, , 4, , 2, , 2, , 2, , 2, , 1, , 1, , 1, , 4, , 2, , 3, , 4, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , Ans., , 2, , 4, , 2, , 1, , 3, , 2, , 1, , 4, , 3, , 2, , 2, , 3, , 1, , 20, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , CHEMICAL KINETICS, 1., , 2., , 3., , In gaseous reaction it is important for the, understanding of the upper atmosphere H 2O, and O react bimolecularly to form two OH, radicals. H for this reaction is 72 kJ at 500 K, and Ea is 77 kJ, then Ea for the bimolecular, recombination of two OH radicals to form H2O, and O is :(1) 3 kJ, (2) 4 kJ, (3) 5 kJ, (4) 7 kJ, Half lives and initial concentration of a first, order and zero order reactions are same. Then, the ratio of the initial rates of the first order, reaction to that of zero order reaction is :(1) 1/0.693, (2) 2 × 0.693, (3) 2/0.693, (4) 6.93, , 6., , In the following first order reactions, K, , (1), , (2), , (3), , (4), , The reaction A(g) + 2B(g), C(g) + D(g) is, an elementary process. In an experiment, the, initial partial pressure of A & B are PA = 0.6, and PB = 0.8 atm. Calculate the ratio of rate of, reaction relative to initial rate when PC becomes, 0.2 atm., , K, , 1, 2, (A), Product, (B), Product,, the ratio K1/K2 if 90% of (A) has been reacted, in time ‘t’ while 99% of (B) has been reacted, in time 2t is :(1) 1, (2) 2, , (3) 1/2, , (4) 2, , (1), , 7., , 1 2log3, 2 log11 2log3, , 1, 4, , (2), , 1, 10, , (3), , 1, 6, , (4) 2, , In the following reaction, rate constant is, 1.2 × 10 –2 M s –1 A, B. What is, concentration of B after 10 min., if we start, with 10 M of A., (1) 2.8 M (2) 7.2 M (3) 8.2 M (4) 2.7 M, , 4., , For a reaction : A, Rate law is –, , Product, 8., , d[A], = K[A]0, dt, , The concentration of A left after time t when, t = 1/K is :(1), , 5., , [A]0, e, , (2) [A]0e, , (3), , [A]0, e, , 2, , (4), , 1, [A]0, , The following mechanism has been proposed, for the exothermic catalyzed complex reaction., A+B, , I AB, , k1, , AB + I, , k2, , P+A, , If k1 is much smaller than k2. The most suitable, qualitative plot of potential energy (P.E.) versus, reaction coordinate for the above reaction., E, , Two substances A (t 1/2 = 5 min) and B, (t1/2 = 15 min) follow first order kinetics are, taken in such a way that initially [A]= 4[B]., Calculate the time after which the concentration, of both the substance will be equal., (1) 15 min (2) 20 min (3) 10 min (4) 25 min, , 9., , Reaction A + B, , C + D follows following, , rate law : rate = k [A], , 1, 1, 2 [ B] 2 ., , Starting with, , initial conc. of 1 M of A and B each, what is, the time taken for concentration of A become, 0.25 M. Given : k = 2.303 × 10–3 sec–1., (1) 300 s, , (2) 600 s, , Your Target is to secure Good Rank in Pre-Medical 2021, , (3) 900 s, , (4) 1200 s, 21

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TARGET : PRE-MEDICAL 2021, 10., , 11., , A first order reaction is 50% completed in, 20 minutes at 27°C and in 5 min at 47°C. The, energy of activation of the reaction is, (1) 43.85 kJ/mol, , (2) 55.14 kJ/mol, , (3) 11.97 kJ/mol, , (4) 6.65 kJ/mol, , Under the same reaction conditions, initial, concentration is 1.386 mol dm–3 of a substance, becomes half in 40 seconds and 20 seconds, through first order and zero order kinetics,, respectively. Ratio, , k1, k0, , 15., , A solution of N 2 O 5 in CCl 4 yields by, decomposition at 45ºC, 5 mL of O2, 20 minutes, after the start of the experiment and 10 mL of, O2 after a very long time. The decomposition, obeys first order kinetics. What volume of O2, would have evolved, 40 minutes after the start, (1) 7.5 mL (2) 7.25 mL(3) 1.5 mL (4) 6 mL, , 16., , Two first-order reactions have half-lives in the, ratio 3 : 2. Calculate the ratio of time intervals, t1 : t2 , t1 is the time period for 25% completion, of the first reaction and t2 for 75% completion, of the second reaction :(1) 0.311 : 1, (2) 0.420 : 1, (3) 0.273 : 1, (4) 0.119 : 1, , 17., , A cetain reaction obeys the rate equation (in, , of the rate constants, , for first order (k1) and zero order (k0) of the, reactions is, , 12., , (1) 0.5 mol–1 dm3, , (2) 1.0 mol dm–3, , (3) 2.0 mol–1 dm3, , (4) 0.1 mol dm–3, , 1.0, , 0.75, , 0.40, , 0.10, , t(min.), , 0.0, , 0.05, , 0.12, , 0.18, , The order of the reaction is., (1) Zero (2) 1, (3) 2, 13., , 14., , 22, , the integrated form) C (1, , n), , C (10, , n), , = (n – 1), , kt where n is the order of the reation; C 0 the, initial concentration and C, the concentration, after time t. What is the unit of k for n = 3 :(1) sec–1, (2) litre mol–1 sec–1, (3) mol litre–1 sec–1, (4) litre2 mol–2 sec–1, , The concentration of R in the reaction R, P, was measured as a function of time and the, following data is obtained :, , [R] (molar), , PHYSICAL CHEMISTRY, , 18., , The half-life of a first order reaction is one hour., During what time interval will the concentration, , 7, of its initial value :8, (1) 6.32 minutes, (2) 17.4 minutes, (3) 23.2 minutes, (4) 11.6 minutes, , be reduced to, (4) 4, , Consider a chemical reaction involving, compounds A and B, which is found to be first, order in A and second order in B. At what rate, will the reaction occur in experiment 2 ?, Experiment Rate (Ms–1) Initial [A] Initial [B], 1, 0.10, 1.0 M, 0.20 M, 2, ?, 2.0 M, 0.60 M, –1, –1, (1) 1.8 M s, (2) 0.20 M s, –1, (3) 1.2 M s, (4) 0.36 M s–1, In a reaction carried out at 400 K, 0.0001% of, the total number of collisions are effective. The, energy of activation of the reaction is, (1) zero, (2) 7.37 k cal/mol, (3) 9.212 k cal/mol, (4) 11.05 k cal/mol, , 19., , The time elapsed between 33% and 67%, completion of a first order reaction is 30, minutes What is the time needed for 25%, completion :(1) 15.5 min, (2) 12.3 min, (3) 18.5 min, (4) 16.5 min, , 20., , At a certain temperature, the half-life periods, for the catalytic decomposition of NH3 were, found to be as follows :Pressue (mm Hg), 50, 100, 200, Half-life period (hrs.) 3.52, 1.76, 0.88, What will be the pressure when the half-life, perriod is 1.5 hours., (1) 117, (2) 206, (3) 89, (4) 160, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 21., , Kinetics of the reaction, A(g), 2B(g) + C(g), is followed by measuring the total pressure at, different times. It is given that :, Initial pressure of A = 0.5 atm., Total pressure of reaction mixture after 2 hours, = 0.7 atm., Rate constant of the reaction = 1 × 10–3 s–1, What is the rate of reaction, , 22., , PHYSICAL CHEMISTRY, , For N2 + 3H2, 2NH3 + 22 kcal, Ea (energy of, activation) is 70 kcal. Hence, Ea of, 2NH3, , N2 + 3H2 is :-, , (1) 92 kcal, , (2) 70 kcal, , (3) – 70 kcal, , (4) – 92 kcal, , d[A], when the, dt, , total pressure is 0.7 atm ?, (1) 2.0 × 10–4 atm s–1 (2) 4.0 × 10–4 atm s–1, (3) 5.0 × 10–4 atm s–1 (4) 7.0 × 10–4 atm s–1, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 3, , 2, , 1, , 1, , 1, , 3, , 2, , 1, , 2, , 2, , 1, , 1, , 1, , 4, , 1, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , Ans., , 1, , 4, , 4, , 2, , 1, , 2, , 1, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 23

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SOLUTION AND ITS COLLIGATIVE PROPERTIES, 1., , How many mili moles of sucrose should be, dissolved in 500 g of water so as to get a, solution which has a difference of 103.57ºC, between boiling point and freezing point of, solution :(Kf = 1.86 K kg mol–1, Kb = 0.52 K kg mol–1), , 2., , (1) 500 mili moles, , (2) 900 milli moles, , (3) 750 milli moles, , (4) 650 milli moles, , 5., , The Van't Hoff factor for BaCl 2 at 0.01M, concentration is 1.98. The percentage, dissociation of BaCl2 at this concentration is –, (1) 49, (2) 69, (3) 89, (4) 98, , 6., , An ideal mixture of liquids A and B with, 2 moles of A and 2 moles of B has a total, vapour pressure of 1 atm at a certain, temperature. Another mixture with 1 mole of, A and 3 moles of B has a vapour pressure, greater than 1 atm. But if 4 moles of C are added, to the second mixture, the vapour pressure, comes down to 1 atm. Vapour pressure of C,, PC0 = 0.8 atm. Calculate the vapour pressures, of pure A and pure B :(1) PA0 = 1.4 atm, PB0 = 0.7 atm, (2) PA0 = 1.2 atm, PB0 = 0.6 atm, (3) PA0 = 1.4 atm, PB0 = 0.6 atm, (4) PA0 = 0.6 atm, PB0 = 1.4 atm, , 7., , 6.8 g H2O2 is dissolved in 224 mL solution. This, solution will be labelled as :(1) 0.224 V (2) 20 V (3) 5 V, (4) 10 V, , 8., , The solubility of a gas in water at 300 K under, a pressure of 100 atmospheres is 4 × 10–3 kg L–1., Therefore, the mass of the gas in kg dissolved, in 250 mL of water under a pressure of 250 atm, and 300 K is :(1) 2.5 × 10–3, (2) 2.0 × 10–3, (3) 1.25 × 10–3, (4) 5.0 × 10–3, , 9., , Two solutions S 1, and S 2 containing, S1, S2, 0.1 M NaCl (aq), 0.1M, 0.05M, and 0.05 M BaCl 2, NaCl, BaCl, (aq) are separated, by semiperameable, membrane., Which among the following statement(s) is/are, correct ? (Assume complete dissociation of, both the electrolytes), (1) S1 and S2 are isotonic, (2) S1 is hypertonic while S2 is hypotonic, (3) S1 is hypotonic while S2 is hypertonic, (4) All the above, , 3.24 g of Hg(NO 3 ) 2 (molar mass = 324), dissolved in 1000 g of water constitutes a, solution having a freezing point of – 0.0558ºC, while 21.68 g of HgCl2 (molar mass = 271) in, 2000 g of water constitutes a solution with a, freezing point of – 0.0744ºC. The Kf for water, is 1.86 K kg mol–1. About the state of ionization, of these two solids in water it can be inferred, that :(1) Hg(NO3)2 and HgCl2 both are completely, ionized, (2) Hg(NO3)2 is fully ionized but HgCl2 is fully, unionized, (3) Hg(NO3)2 and HgCl2 both are completely, unionized, (4) Hg(NO3)2 is fully unionized but HgCl 2 is, fully ionized, , 3., , A solution of x moles of sucrose in 100 g of, water freezes at – 0.2ºC. Calculate the amount, of ice separate out when it is cooled upto –, 0.25°C :(1) 18 g, , 4., , (2) 20 g, , (3) 25 g, , (4) 23 g, , Which of the following has been arranged in, order of decreasing freezing point :(1) 0.05 M KNO3 > 0.04 M BaCl2 > 0.140 M, sucrose > 0.075 M CuSO4, (2) 0.04 M BaCl 2 > 0.140 M sucrose >, 0.075 M CuSO4 > 0.05 M KNO3, (3) 0.075 M CuSO 4 > 0.140 M sucrose >, 0.04 M BaCl2 > 0.05 M KNO3, (4) 0.075 M CuSO 4 > 0.05 M KNO 3 >, 0.140 M sucrose > 0.04 M BaCl2, , 24, , Your Target is to secure Good Rank in Pre-Medical 2021, , 2, , E

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , 10., , The molarity of a solution made by mixing 50, mL of conc. H 2 SO 4 (36 N) with 50 mL. of, water, is :, (1) 36 M (2) 18 M (3) 9 M, (4) 6M, , 17., , If two substances A and B have PA0 : PB0 = 1 : 2, and have mole fraction in solution 1 : 2 then, mole fraction of A in vapours, (1) 0.33, (2) 0.25, (3) 0.52 (4) 0.2, , 11., , Vapour pressure of CCl4 at 250C is 143 mm Hg., 0.5 g of a non-volatile solute (mol. wt. 65) is, dissolved in 100 mL of CCl4. Find the vapour, perssure of the solution., (Density of CCl4 = 1.58 g/cm3 ), (1) 141.93 mm, (2) 94.39 mm, (3) 199.34 mm, (4) 143.99 mm, , 18., , The mass of solute ‘A’ (mol mass = 40 g mol–1), that should be added to 180 g of pure water in, order to lower its vapour pressure to 4/5th of its, original value :(1) 187.5 g (2) 90 g, (3) 150 g (4) 100 g, , 19., , 150mL of C2H 5OH (density = 0.78 g/ml) is, diluted to one litre by adding water; molality, of the solution is –, (1) 2.54, (2) 11.7, (3) 2.99, (4) 29.9, , 20., , Consider the following vapour pressurecomposition graph, SP is equal to :-, , 12., , 13., , 14., , An aqueous solution of urea containing 18 g urea, in 1500 cm3 of solution has a density of 1.052 g/cm3., If the molecular mass of urea is 60, then the, molality of solution is :(1) 0.2, (2) 0.192 (3) 0.064 (4) 1.2, Which solution will have the highest boiling, point :(1)1% glucose in water(2) 1% sucrose in water, (3) 1% NaCl in water (4) 1% CaCl2 in water, , Vapour, pressure, , 0, , PBo, and limXB, XB, , (1) 138, 258, (3) 120, 138, , 0, , PAo, are :, XA, , The vapour pressure of a solution of a, non-volatile non-electrolyte (A) in a solvent (B), is 95 % of the vapour pressure of the solvent at, the same temperature. If MB = 0.3 MA, where, MB and MA are molecular weight of B and A, respectively, the weight ratio of the solvent and, solute are :(1) –0.17 (2) 5.7, (3) 0.2, (4) 4.0, , 16., , When 20 g of naphthoic acid (C 11 H 8 O 2 ) is, dissolved in 50g of benenze (Kf = 1.72 K kg mol–1),, then freezing point depression of 2K is, observed. The van't Haff factor (i) is :, (1) 0.5, (2) 1.0, (3) 2.0, (4) 3.0, , pB0, , PA, R, S, , 0.2 0.4 0.6 0.8, , 1, , mole fraction, , (1) PQ + RS, (3) SR + SQ, , (2) QR + RS, (4) PQ + QR, , 21., , pH of a 0.1 M monobasic acid is measured to, be 2. Its osmotic pressure at a given, temperature T K is :(1) 0.1 RT (2) 0.11 RT(3) 1.1 RT (4) 0.01 RT, , 22., , A solution containing 0.1 g of a non-voltatile, organic substance P(molecular mass 100) in, 100g of benzene raises the boiling point of, benzene by 0.2°C, while a solution containing, 0.1 g of another non-volatile substance Q in, the same amount of benzene raises the boiling, point of benzene by 0.4°C. What is the ratio, of molecular masses at P and Q ?, (1) 1 : 2 (2) 2 : 1, (3) 1 : 4, (4) 4 : 1, , 23., , What is the osmotic pressure of the solution, obtained by mixing 300 cm 3 of 0.6%, (mass-volume) solution of urea with 300 cm3, 3.42% solution of sucrose at 20°C ?, , (2) 258,138, (4) 138, 125, , 15., , pA0, PB, , At 40°C, the vapour pressure (in torr) of methyl, alcohol (A) and ethyl alcohol (B) solution is, represented by :P = 120 XA + 138; where XA is, mole fraction of methyl alchol. The value of lim, XA, , E, , essure, our pr P, p, a, v, l, Tota, Q, , (1) 5 atm, , (2) 5.2 atm (3) 2.4 atm (4) 4.5 atm, , Your Target is to secure Good Rank in Pre-Medical 2021, , 25

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TARGET : PRE-MEDICAL 2021, 24., , A solution of HCl containing 0.03659 g/mL and, another solution of acetic acid containing, 0.04509 g/mL, then which will have highest, normality(N) :, (1) NHCl, (2) NCH3COOH, (3) Both have same N (4) None of these, , (1) When XA = 1 then P = P°A, (2) When XB = 1 then P < P°A, (3) When XA = 1 then P < P°B, (4) Both (1) and (3), 28., , 25., , PHYSICAL CHEMISTRY, , Two solutions of a substance (non-electrolyte), are mixed in the following manner 480 mL of, 1.5M of first solution with 520 mL of 1.2 M of, second solution. The molarity of final solution is:(1) 1.20 M, (2) 1.50 M, (3) 1.344 M, (4) 2.70 M, , Variation of log (atm) v/s logC (C =, concentration of solute in g/L) is given following, log, A, , O, , 26., , Equal amounts (mass) of a solute are dissolved, in equal amounts of the solvents A and B. The, relative lowering of vapour pressure for the, solution A has twice that for the solution B. If, MA and MB are the molar masses of solvent A, and B respectively, then for dilute solution of, A and B with solute :-, , At 300K, for a solute of molar mass 300 g/mol,, OA = log (x × 10–2). What is the value of x ?, (1) 8.21, 29., , MB, 2, , (1) MA = MB, , (2) MA =, , (3) MA = 4MB, , (4) MA = 2MB, , logC, , (2) 0.0821 (3) 82.1, , (4) 0.821, , The degree of dissociation of Ca(NO3 )2 in a, dilute aqueous solution containing 7 g of salt, per 100 g of water at 100°C is 70%. Calculate, the vapour pressure of solution., (1) 746.27 mm of Hg (2) 550.21 mm of Hg, (3) 446.27 mm of Hg (4) 243.13 mm of Hg, , 27., , The following is a graph plotted between the, vapour pressures of two volatile liquids against, their respective mole fractions :-, , 30., , P°B, , P, , P°A, , XA = 1, XB = 0, , A 0.025 M solution of monobasic acid had a, freezing point of –0.06°C. Calculate K for the, acid. Kf for H2O=1.86°C molality –1 . Assume, molality equal to molarity., (1) 1.96 × 10–3, , (2) 3.96 × 10–3, , (3) 2.96 × 10–3, , (4) 5.8 × 10–3, , XA = 0, XB = 1, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 3, , 2, , 2, , 1, , 1, , 4, , 4, , 1, , 2, , 3, , 1, , 2, , 3, , 1, , 2, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans., , 1, , 4, , 4, , 3, , 3, , 2, , 2, , 3, , 1, , 3, , 4, , 4, , 1, , 1, , 3, , 26, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , ELECTROCHEMISTRY, 1., , A 250 mL sample of a 0.2 M Cr3+ is electrolysed, with a current of 96.5 amp; if the remaining, concentration of Cr3+ ion is 0.1 M, the duration, of electrolysis is : (Atomic wt. of Cr = 52), Assume volume of solution remains constant, during electrolysis :(1) 75 sec, (2) 150 sec, (3) 225 sec, (4) 25 sec, , 2., , Electrolysis of hot aqueous solution of NaCl, gives NaClO4, i.e., sodium perchlorate,, NaCl + 4H2O, NaClO4 + 4H2, How many faraday are required to obtain, 1000 g of sodium perchlorate :(1) 66, (2) 40.3 (3) 18.3 (4) 31.6, , 3., , For which of these oxidation/reduction pairs, will the reduction potential vary with pH :I. AmO22 / AmO2, III. Am4+ / Am2+, (1) I only, (3) I and II only, , 4., , 7., , The pressure of hydrogen gas is increased from, 1 atm to 100 atm. Keeping the H + (1M), constant, the voltage of the hydrogen half-cell, at 25ºC will be :(1) 0.059 V, (2) 0.59 V, (3) 0.0259 V, (4) – 0.0591 V, , 8., , Calculate the cell potential of the following, concentration cell :, Pt|Cl2(0.4 bar)| Cl– (0.1 M) | | Cl– (0.01 M)|, Cl2 (0.2 bar)|Pt, (1) 0.051 V, (2) – 0.051 V, (3) 0.102 V, (4) 0.0255 V, , 9., , For the cell reaction,, Mg(s) + 2Ag+ (aq), , II. AmO22 / Am 4, , E ocell is 3.17 V at 298 K. The value of Ecell, Gº, and Q at Ag+ and Mg2+ concentrations of 0.001, M and 0.02 M respectively are :(1) 3.04 V, – 605.8 kJ mol–1, 20000, (2) 3.04 V, 611.8 kJ mol–1, 20000, (3) 3.13 V, – 604 kJ mol–1, 20, (4) 3.04 V, – 611.8 kJ, 20000, , (2) II only, (4) I, II and III, , In the concentration cell,, Pt(H2) HA (0.1M ) HA (1M ) (H2) Pt, NaA (1M ) NaA (1M ), (pKa of HA = 4), Cell potential will be :(1) 0.03 V, (2) 0.06 V, (3) – 0.06 V, (4) – 0.03 V, , 5., , 0.32, , 0.26, , (3) 10 0.0295, 6., , E, , 10., , Consider the following four electrodes,, P = Cu2+ (0.0001 M) / Cu(s), Q = Cu2+ (0.1 M) / Cu(s), R = Cu2+ (0.01 M) / Cu(s), S = Cu2+ (0.001 M) / Cu(s), If the standard reduction potential of Cu2+ / Cu, is 0.34 V, the reduction potential in volt of the, above electrodes follow the order :(1) Q > R > S > P, (2) P > S > R > Q, (3) R > S > Q > P, (4) P > Q > R > S, , 11., , Which is correct about fuel cell :(1) Cell continuously run as long as fuels are, supplied, (2) These are more efficient and free from, pollution, (3) These are used to provide power and, drinking water to astronauts in space, programme, (4) All of these, , The emf of the cell, Zn | Zn2+ (0.01 M) || Fe2+ (0.001 M) | Fe, at 298 K is 0.2905 V then the value of, equilibrium constant for the cell reaction is :(1) e 0.0295, , Mg2+ (aq) + 2Ag(s),, , 0.32, , (2) 10 0.0295, 0.32, , (4) 10 0.0591, , Efficiency of the following cell is 84%., A(s) + B2+ (aq), A2+ (aq) + B(s);, H° = –285 kJ, Then the standard electrode potential of the cell, will be :(1) 1.20 V, (2) 2.40 V, (3) 1.10 V, (4) 1.24 V, , Your Target is to secure Good Rank in Pre-Medical 2021, , 27

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TARGET : PRE-MEDICAL 2021, 12., , The density of Cu is 8.94 g cm–3. The quantity, of electricity needed to plate an area 10 cm × 10, cm to a thickness of 10 –2 cm using CuSO 4, solution would be, (1) 13586 C, (2) 27172 C, (3) 40758 C, (4) 20348 C, , 13., , Salts of A (at wt. 7), B (at wt. 27) and C(at wt., 48) were electrolysed under identical, conditions using the same quantity of, electricity. It was found that when 2.1 g of A, was deposited, the weights of B and C, deposited were 2.7 g and 7.2 g. The valencies, of A, B and C are respectively :(1) 3, 1 and 2, (2) 1, 3 and 2, (3) 3, 1 and 3, (4) 2, 3 and 2, , 14., , 15., , 17., , Standard electrode potential of some half cell, reactions are given below (A) Sn+4 + 2e–, Sn2+ , E° = +0.15 V, +2, –, (B) 2Hg + 2e, Hg2+2 , E° = +0.92 V, (C) PbO 2 + 4H + + 2e –, Pb +2 + 2H 2 O,, E° = +1.45 V, for these which statement is correct –, (1) Pb+2 is more powerful reducing agent than, Sn+2, (2) Sn+4 is more powerful oxidising agent than, Pb+4, (3) Sn+2 is more powerful reducing agent than, Hg 2 +2, (4) Hg+2 is more powerful oxidising agent than, Pb+4, , 18., , The Eº in the given diagram is :-, , The electrical resistance of a column of, 0.05 mole/litre NaOH solution of diameter, 1 cm and length 50 cm is 5.55 × 10 3 ohm., Calculate its molar conductivity :(1) 229.6 Scm2 mol–1 (2) 119.5 Scm2 mol–1, (3) 190.2 Scm2 mol–1 (4) None of these, A cell in which the following reaction takes, place :Mg (s) +2Ag +(0.0001 M) Mg +2 (0.120 M) +, 2Ag(s), , PHYSICAL CHEMISTRY, , –, , ClO3, , 0.50 V, , 1.36 V –, 1, ClO 0.40 V, Cl, Cl, 2 2, 0.88 V, Eº, , (1) 0.5, , (2) 0.63, , (3) 0.7, , (4) 0.8, , 19., , If same quantity of electricity is passed through, CuCl and CuSO4, the ratio of the weights of, Cu deposited from CuSO4 and CuCl is :(1) 2 : 1 (2) 1 : 2 (3) 1 : 1 (4) 4 : 1, , 20., , The following cell has a potential of 0.55 V at, 25ºC, Pt (s) | H2 (1 atm) | H+ (? M) ||, Cl– (1 M) | Hg2 Cl2 (s) | Hg ( ), What is the pH of the solution in the anodic, , if Ecell = 3.17 volt then calculate Ecell, (1) 2.0 volt, (3) 3.50 volt, 16., , 28, , (2) 2.96 volt, (4) 3.17 volt, , An electrochemical cell is set up as follows', Pt(H2 1atm)/0.1 M HCl | | 0.1 M Acetic Acid/, (H2 1atm) Pt., E.M.F. of the cell will not be zero because :, (1) The pH of 0.1 M HCl and 0.1 M acetic acid, is not the same, (2) Acids used in the two compartments are, different, (3) EMF of a cell depends on the molarities of acids, used, (4) The temperature is constant, , chamber ? E ºCl, (1) 4.57, 21., , / Hg2 Cl2 / Hg, , = 0.28 V :-, , (2) 14.07 (3) 9.15, , (4) 7.15, , The k = 4.95 × 10–5 S cm –1 for a 0.00099 M, solution. Calculate the degree of dissociation, of acetic acid, if, 2, , M, , for acetic acid is, , –1, , 400 S cm mol :(1) 7, (2) 0.125 (3) 8, , Your Target is to secure Good Rank in Pre-Medical 2021, , (4) 10, E

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TARGET : PRE-MEDICAL 2021, 22., , 23., , 24., , Value of m for SrCl2, following data :, Conc. (mol/L), –1, cm2 mol–1), m(, (1) 270, (2) 260, , in water at 25º from the, 0.25, 260, (3) 250, , 27., , The ionization constant of a weak electrolyte, is 25 × 10–6 while the equivalent conductance, of its 0.01 M solution is 19.6 S cm2 eq-1. The, equivalent conductance of the electrolyte at, infinite dilution (in S cm2 eq–1) will be :(1) 250, (2) 196, (3) 392, (4) 384, , 28., , Three moles of electrons are passed through, three solutions in succession containing, AgNO3, CuSO4 and AuCl3, respectively. The, molar ratio of amounts of cations reduced at, cathode will be :(1) 1 : 2 : 3, (2) 2 : 1 : 3, (3) 3 : 2 : 1, (4) 6 : 3 : 2, , 29., , Given, limiting equivalent conductance of, BaCl2 = x1, H2SO4 = x2, HCl = x3, Specific conductance of the saturated BaSO 4, solution = y Scm–1., Thus Ksp of BaSO4 is –, (1) 103y / 2(x1+x2–2x3), (2) 106y2 / (x1+x2–2x3)2, (3) 106y2 / 4(x1+x2–x3)2, (4) (x1+x2–2x3) / 106y2, , 30., , Select the correct statement based on the, following half cell reactions, Fe2+, Fe3+ + e– ; E° = –0.77 V, O2 + 4H+ + 4e–, 2H2O ; E° = 1.23 V, Fe, Fe2+ + 2e– ; E° = 0.44 V, (1) Fe2+ solution is not stable in air, (2) Fe nails can prevent oxidation of Fe2+ to, Fe3+ by air, (3) Corrosion of Iron takes place by air, (4) All, , 1, 250, (4) 255, , The standard reduction potentials Eº of the, following reactions are, Eº (Volt), –, +, –, 2+, (i) MnO4 + 8H + 5e, Mn + 4H2O 1.51, 4+, –, 2+, (ii) Sn + 2e, Sn, 0.15, 2–, +, –, 3+, (iii) Cr2O7 +14H +6e, 2Cr +7H2O 1.33, (iv) Ce4++ e–, Ce3+, 1.61, The oxidising power of the various species, decreases in the order :(1) Ce4+ > Cr2O72– > Sn4+ > MnO4–, (2) Ce4+ > MnO4– > Cr2O72– > Sn4+, (3) Cr2O72– > Sn4+ > Ce4+ > MnO4–, (4) MnO4– > Ce4+ > Sn4+ > Cr2O72–, The reduction potential of a half-cell consisting, of a Pt electrode immersed in 1.5 M Fe2+ and, 0.015 M Fe3+ solution at 25º C is, E oFe3, , / Fe 2, , 0.770 V, , (1) 0.652 V, (3) 0.710 V, , (2) 0.88 V, (4) 0.850 V, , 25., , The number of Faradays required to produce, one mole of water from a hydrogen-oxygen, fuel cell containing aqueous alkali as electrolyte is, (1) 1, (2) 3, (3) 2, (4) 4, , 26., , 4 mole of electrons were transferred from, anode to cathode in an experiment on, electrolysis of water. The total volume of the, two dry gases (at STP) produced will be, approximately (in L) :(1) 22.4 (2) 44.8 (3) 67.2 (4) 89.4, , PHYSICAL CHEMISTRY, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 1, , 1, , 2, , 2, , 2, , 4, , 4, , 1, , 4, , 1, , 4, , 2, , 2, , 1, , 2, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans., , 1, , 3, , 2, , 2, , 1, , 2, , 1, , 2, , 1, , 3, , 3, , 3, , 4, , 3, , 4, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 29

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SURFACE CHEMISTRY, 1., , 2., , Arrange the following electrolytes in increasing, order of coagulation power for As2S3 sol. :A1, A2, A3, A4, KCl, CaCl 2, AlCl3, SnCl4, (1) A1 < A2 < A3 < A4 (2) A1 > A2 > A3 > A4, (3) A2 < A4 < A1 < A2 (4) A2 < A3 < A4 < A1, , 5., , Which of the following statements are correct ?, a. The smaller the gold number of lyophilic, colloid, the larger will be its protective, power., b. Lyophilic sols, in contrast to lyophobic sols, are easily coagulated on addition of small, amounts of electrolytes., c. Ferric chloride solution is used to stop, bleeding from a fresh cut because it, coagulates the blood., d. The flocculation value of arsenious, sulphide sol is independent of the anion of, the coagulating electrolyte., (1) a, b and c, (2) a, c and d, (3) b, c and d, (4) a, b and d, , 6., , When a graph is plotted between log x/m and, log p, it is straight line with an angle 45º and, intercept 0.3010 on y-axis. If initial pressure is, 0.3 atm, what will be the amount of gas, adsorbed per gm of adsorbent :(1) 0.4, , 7., , (3) 0.8, , (4) 0.1, , Silica gel, a colloidal dispersion of hydrated, SiO2 called ....... which is formed when dilute, HCl is added to dilute solution of sodium, silicate., (1) Water gas, , (2) Water glass, , (3) Quartz silica, , (4) Pearl glass, , Coagulation value of the electrolytes AlCl3 and, NaCl for As 2 S 3 sol are 0.093 and 52, respectively. How many times AlCl3 has greater, coagulating power than NaCl :(1) 930, , 8., , (2) 0.6, , (2) 520, , (3) 560, , (4) 230, , Which one of the following statements is correct, (1) Brownian movement is more pronounced, for smaller particles than for bigger ones, (2) Sols of metal sulphides are lyophilic, , 3., , The coagulation value in millimoles per litre, of electrolytes used for the coagulation of As2S3, are as below :I. NaCl = 52, II. KCl = 51, III. BaCl2 = 0.69, IV. MgSO4 = 0.22, The correct order of their flocculating power, is :, (1) I > II > III > IV, (2) I > II > III = IV, (3) IV > III > II > I, (4) IV = III > II > I, , (3) Schulze-Hardy law states, the bigger the size, of the ion, the greater is its coagulating power, (4) One would expect charcoal to adsorb, chlorine more strongly than hydrogen, sulphide, 9., , Which can adsorb larger volume of hydrogen gas, (1) Colloidal solution of palladium, (2) Finely divided nickel, (3) Finely divided platinum, (4) Colloidal Fe(OH)3, , 4., , 30, , The example of cationic surfactants is :(1) C17H35COONa, , 10., , Which of the following has minimum, flocculation value for positively charged sol ?, , (2) C16H33 N (CH3)3 Cl, , (1) Cl, , (3) RC6H4SO3Na, (4) C16H33C6H4NHCl, , (2) SO 42, , (3) PO 4 3, , (4) [Fe(CN)6]–4, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 11., , 12., , 13., , Associated colloids :(1) Raise both the surface tension and viscosity, of water, (2) Lower both the surface tension and the, viscosity of water, (3) Lower the surface tension and raise the, viscosity of water, (4) None of these, , 17., , Below critical micelle concentration (CMC) :(1) The surfactant molecules of ions undergo, associated to form clusters, (2) The viscosity of solution increase abruptly, (3) Substances like grease, fat etc. dissolve, colloidally, (4) Salt behave as normal, strong electrolyte, Equal volume of two sols of AgI, one obtained, by adding AgNO3 to slight excess of KI and, another obtained by adding KI to slight excess, of AgNO3 are mixed together. Then :(1) The two sols will stabilize each other, (2) The sol particles will acquire more electric, charge, (3) The sols will coagulate each other mutually, (4) A true solution will be obtained, , 14., , On addition of one mL solution of 10% NaCl, to 10mL gold sol in presence of 0.00015 g gum, arabic so that coagulation is just prevented. The, gold number of gum arabic is :, (1) 15, (2) 1.5, (3) 0.15 (4) 0.025, , 15., , Cleansing action of soap occurs because :(1) Oil and grease can be absorbed into the, hydrophobic centres of soap micelles and, washed away, (2) Oil and grease can be absorbed into, hydrophilic centres of soap micelles acid, washed away, (3) Oil and grease can be absorbed into both, hydrophilic and hydrophobic centres but, not washed away, (4) None of these, , E, , 16., , PHYSICAL CHEMISTRY, , When 1g charcoal is kept in SO2 gas container,, CO2 gas container and H2 gas container. The, correct order of amount of gas adsorbed is :(1) SO2 > CO2 > H2, , (2) H2 > CO2 > SO2, , (3) CO2 > H2 > SO2, , (4) H2 = CO2 > SO2, , Which of the following is correct equation for, freundlich adsorption isotherm :1, , (1), , x, m, , KP n ; 1 <, , (2), , x, m, , KP n ; 0, , (3) log, , 1, , 1, n, , 1, n, , 1, , x, 1, = logK + log p ; 0, m, n, , 1, n, , 1, , (4) Both (2) & (3), 18., , Lyophilic sols are known as protective colloids, due to, (1) They stabilizes lyophobic sols, (2) They have less Iron number, (3) They have any metal number, (4) None of above, , 19., , The standard gold sol contains ...... & ......to, Measure protective power of lyophilic sol ?, (1) 10 mL Au sol, 10 mL 10% NaCl solution, (2) 10 mL NaCl sol, 1 mL 10% Au solution, (3) 10 mL Au sol, 1 mL of 10% NaCl, (4) 10 mL Au sol, x mg NaCl, , 20, , Which of the following will have the highest, coagulating power for Fe(OH)3 colloid ?, (1) PO 4 3 (2) SO 42, , 21., , (3) Ca+2, , (4) Al+3, , Blue colour of the sky is due to :(1) Absorption of light by dust particles, (2) Reflection of light by dust particles, (3) Scattering of light by dust particles, (4) None of these, , Your Target is to secure Good Rank in Pre-Medical 2021, , 31

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TARGET : PRE-MEDICAL 2021, Smoke precipitator works on the principle of, (1) Centrifugation, (2) Neutralization of charge on colloids, (3) Absorption, (4) Addition of electrolyte, , 23., , In homogeneous catalytic reaction there are, three paths A, B and C. Which one of the, following indicates the relative, ease with which the, A, reaction can take, place?, B, (1) A > B > C, C, (2) C > B > A, (3) B > C > A, Reaction coordinate, (4) A = B = C, , 28., , Incorrect match regarding catalyst ?, (1) Zigglers Natta catalyst, Heterogeneous, catalyst, (2) Fe/Mo, Heterogenous catalyst/inhibitor, (3) Pd/BaSO4 Catalyst, Catalytic poison, (BaSO4), (4) Shape selective catalysts, ZSM-5, , 29., , Tyndal effect and less colligative properties can, be shown by :(1) True solution, (2) Colloidal solution, (3) Hypertonic solution, (4) Hypotonic solution, , 30., , Micelle can not be formed by :(1) CH 3(CH2)16 COO– Na+, (2) CH3(CH2)11 SO4 Na+, (3) CH3(CH2)16N+(CH3)3 Br, (4) CH3COO–K+, , 31., , Which of the following is purification method, of colloidal solution., (1) Electrodialysis, (2) Peptization, (3) Electrophoresis (4) Electro osmosis, , 32., , A colloidal sol is formed by mixing AgNO3 and, KI in 2 : 1 molar ratio. This colloidal sol is to, be coagulated by, I. NaI, II. MgSO4 III. AlPO4, Molar ratio of these required to coagulate, 1 mole of colloidal sol is :(1) 1 : 1 : 1, (2) 1 : 2 : 3, (3) 3 : 2 : 1, (4) 6 : 3 : 2, , 33., , Which temperature is related to micelle ?, (1) Critical temperature, (2) Kraft temperature, (3) Boyle's temperature, (4) Inversion temperature, , 34., , What the flocculation value of NaCl if 100 mL, of arsenious sulphide sol requires 5 mL of 1 M, NaCl for coagulation ?, (1) 50, (2) 5, (3) 100, (4) 10, , energy, , 22., , 24., , 25., , 26., , In multimolecular colloids sols, atoms or, molecules are held by :(1) Dative bonding (2) Vander waals force, (3) Ionic bonding, (4) Polar covalent bond, Activated charcoal is prepared by :(1) Heated charcoal with steam so that it, becomes more porous, (2) Addition Ca3(PO4)2 to charcoal, (3) Addition impurity to charcoal, (4) Reacted with conc. HNO 3, Among the following the surfactant that will, form micelles in aqueous solution at the lowest, molar concentration at ambient condition is :(1) CH3(CH2)15 N (CH3)3 Br, (2) CH 3(CH2)11 OSO3 Na, (3) CH3(CH2)6COO Na, (4) CH3(CH2)11 N(CH3)3 Br, , 27., , 32, , Air becomes dry in presence of silica gel, because, (1) Colloidal solution formation, (2) Catalytic properties, (3) Adsorption, (4) Absorption, , PHYSICAL CHEMISTRY, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 35., , One gram of activated charcoal has a surface, area of 10 3 m 2 . If complete coverage by, monolayer is assumed, how much NH3 at STP, would be adsorbed on the surface of 25 g of, the charcoal?, (Given diameter of NH3 molecule = 0.3 nm), (1) 11.16 L, (2) 13.16 L, (3) 15.24 L, (4) 22.18 L, , 36., , Which of the following statmenets is incorrect?, (1) Emulsions are prepared by shaking two, liquid components, say oil and water and, adding some emulsifying agent., (2) Water-in-oil emulsions are formed when, the emulsifying agent at the interface is, chiefly in the water phase., (3) Water-in-oil emulsions are formed when, the emulsifying agent at the interface is, chiefly in the oil phase., (4) Gems and gels mixed together to give, emulsion., , 37., , PHYSICAL CHEMISTRY, , Choose the correct reasons for the stability of, the lyophobic colloidal particles., (a) Preferential adsorption of ions on their, surface from the solution., (b) Preferential adsorption of solvent on their, surface from the solution., (c) Attraction between different particles, having opposite charges on their surface., (d) Potential difference between the fixed layer, and the diffused layer of opposite charges, around the colloidal particles., (1) c, d, (2) a, b, (3) a, b, c, (4) a, d, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans., , 1, , 2, , 3, , 2, , 2, , 2, , 3, , 1, , 1, , 4, , 3, , 4, , 3, , 3, , 1, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans., , 1, , 4, , 1, , 3, , 1, , 3, , 2, , 2, , 2, , 1, , 1, , 3, , 2, , 2, , 4, , Que., , 31, , 32, , 33, , 34, , 35, , 36, , 37, , Ans., , 1, , 4, , 2, , 1, , 2, , 4, , 4, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 33

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SOME BASIC CONCEPT OF CHEMISTRY (MOLE CONCEPT), 1., , 0ºC and 760 mm = NTP, , 22.4, 224, = 10–3 mol, 22400 224000, no. of molecules = 10–3 NA, , n NO2, , 46, =1, 46, , n O2, , 16, = 0.5, 32, , n=, , 2., , 3, H (g), 2 2, 0, 0, 3 100, –, = 150 mL, 2, , PH3, , P(s) +, , 100 mL, (100 – 100), , 3., , 4., , Vi = 100 mL, Vf = 150 mL, (Vf – Vi) = 50 mL, mass of 1 molecule of H2O = 18 amu, = 18 × 1.67 × 10–24 g, = 30 × 10–24 g, = 3 × 10–26 kg, No. of atoms of gold = no. of moles × NA, =, , 5., , mole, 2 ; 1 ; 0.5 =, 1, 2, 0.5 Stoichiometric coefficient, So NO2 is limiting reagent, 2 mol NO2 will give = 1 mol Pb(NO 3)2, , 1 mol NO2 will give =, , = 0.5 mol × molar mass (g), = 0.5 × 331, = 165.5 g, 8., , 19.7 10 3, × NA, 197, , = 102 NA = 6.023 × 1025 atoms, MnO2(s) + 4HCl(aq), MnCl2(aq) + 2H2O( ) + Cl2(g), 1 mol MnO2 requires = 4 mol HCl, 87 g MnO2 requires = 4 × 36.5 g HCl, , 7., , acid), molecules of amino acid = 10–5 × NA, = 6.023 × 1018 molecules, 1, PbO + 2NO2 + O2, Pb(NO3)2, 2, nPbO, , HS, , 446, =, =2, 223, , xCO2 +, , y, HO, 2 2, , 88, = 2 mole, 44, , 36, =2, 18, y, =2, 2, , y=4, but mass of organic compound is, 44 = 12 × 2 + 4 × 1 + mass of oxygen, 44 – 28 = mass of oxygen, mass of oxygen = 16 = 1 mol of oxygen atom, hence formula = C 2H4O, , 0.032, = 3.2 × 10–4g, 100, , 3.2 10 4, = 10–5 mol (mol of amino, 32, , y, O2, 4, , mol of H2O =, , = 8.39 g HCl, , mol of S =, , x, , x=2, , 5 4 36.5, 5 g MnO2 requires =, g HCl, 87, , Mass of S = 1 ×, , Cx H y +, , mol of CO2 =, , 4 36.5, 1 g MnO2 requires =, g HCl, 87, , 6., , 1, mol Pb(NO3)2, 2, , 9., , mol of CO2 =, mol of H2 =, , 0.22, 44, , 0.01, 2, , 1, 200, 1, mol, 200, , mol of NH3 =, , 0.085, 17, , mol of SO2 =, , 320, 1000 64, , Your Target is to secure Good Rank in Pre-Medical 2021, , 1, mol, 200, 1, mol, 200, 1

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TARGET : PRE-MEDICAL 2021, 10., , 0.1 g atom C = 12 × 0.1 = 1.2 g, 0.1 mol NH3 = 17 × 0.1 = 1.7 g, 6.02 × 1022 molecules of H2, , 40 10 3, = 103, 40, 3C, A4B2C3, 0.72 mol, , no. of g atom = no. of mol =, 16., , 22, , 6.02 10, × 2 g = 0.2 g, 6.02 10 23, 1120 mL of CO2 at NTP, , =, , 4A +, 1 mol, , 1, 4, , 1120, × 44g = 2.2 g, 22400, 2.2 g is highest mass, H2SO4 + NaCl, NaHSO4 + HCl, , 2B +, 0.6 mol, , 0.6, 2, , 0.72, 3, , 0.25, 0.3, 0.24, (C) is LR, 3 mol of C will give = 1 mol product, , =, , 11., , PHYSICAL CHEMISTRY, , 1 mol of C will give =, 98 g, x, 120 g, 27.5 g, Since balanced reaction follows law of, conservation of mass, 98 + x = 120 + 27.5, x = 147.5 – 98.0, x = 49.5 g, 12., , 13., , 14., , x x x, : :, 32 2 16, of O2, H2 and CH4 = 1 : 16 : 2, NH3(g) + HCl(g), NH4Cl(s), 20, 40, NH3 is LR So final volume of gas remained = 20cc, X2O3, +, 3H2, 3H2O + 2X, , 0.72 mol will give =, 17., , Ratio of moles =, , 18., 19., , 0.1596, 2x 48, , 6 10, 2, , 1000, 1000, mol of CaC2 =, mol of C2H2, 64, 64, C2H4, , 3, , mol of C2H2 =, , 1000, mol (mole of C2H4), 64, , 1 mol of X2O3 is reduced by = 3 mol H2, So, , mass of polythene =, , 0.1596, X O is reduced by, 2x 48 2 3, 3 0.1596, =, 2x 48, , 6 10, 2, , 3, , 20., , x=, , 15., 2, , 111.6, = 55.8, 2, , 6.664 10 23, Atomic mass of X =, = 40, 1.66 10 24, , 1000, 7000, × 28 =, = 43.75g, 64, 16, , = 0.4375 kg, Let % of oxygen = x, % of H =, , –3, , (2x + 48) × 10 = 0.1596, 2x + 48 = 159.6, 2x = 159.6 – 48, 2x = 159.6 – 48, 2x = 111.6, , 0.72, = 0.24 mol, 3, , Ca3(PO4)2 : P : O, 1, : 2 : 8, 1/2, : 1 : 4, H3PO3 : P : 0, 1, : 1 : 3, E = molarmass/v.f. of salt, CaC2 + H2O, Ca(OH)2 + C2H2, , C2H2 + H2, n=, , 1, mol product, 3, , 1, 1.5x, × % of C =, 6, 6, , % C = 1.5 × % of O = 1.5 × x, element %, A, %/A Simple ratio, C, , 1.5 x, , 12, , 1.5x, 12, , 1.5x, × 16 = 2, 12, , H, , 1.5x, 6, , 1, , 1.5x, 6, , 1.5x, × 16 = 4, 6, , O, , x, =1, 16, Empirical formula = C2H4O, x, , 16, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , ATOMIC STRUCTURE, 1., , Ionisation energy of He ion = E – E1, = 0 – (–21.8 × 10–18 ×, = 8.72 × 10, , 2., , –18, , 4, ), 1, , 6., , (n 1)2, n2, Å 0.529, Å, Z, Z, , J, , 0.529, , =, , 6.62 10 34 3 10 8, 5893 10 10, , = 3.37 × 10–19 J, Total energy emitted by sodium lamp, = 60 Watt = 60 J/sec, Number of photon emitted in, , r(n+1) – rn = r(n–1), 0.529, , hc, , Energy of 1 photon=, , (n 1) 2, Å, Z, , 60, 3.37 10, , 1 sec =, , (n+1)2 – n2 = (n–1)2, , 19, , and in 10 hours, , (n2 + 2n + 1) – n2 = n2 – 2n + 1, 2n = n2 – 2n, , Total no. of emitted photons =, , n2 = 4n, n=4, 3., , 7., , Potential energy of electron, , = 6.4 × 10 24, Distance between 3 rd and 2nd orbit of H atom, = r3 – r2, , – Nuclear charge × charge on electron, Radius of orbit, , =, , = 0.529 × 10, , Ze 6e, r, , 4., , P, , =, , =, , =, , 2mqV, , 9., , 9m p 3q p, Be, , 1, 27, , =, , 3, , :, , p, , [, , V is same], , thus in berylium (Z = 4) ion no. of neutrons, , =, , h, and =, m, , h, m, , n=2, , visible region (2 lines), , n=1, , ultraviolet region (3 lines), , Spherical node is not present for 1s orbital, , 11., , Angular momentum is integral multiple of, , h, 2, , in succesive orbits., 12., , x× p, , h, 4, , Since x =, , or, , p=m, , p therefore, ( p)2 =, , =, , =9–4=5, 4, , 2, , n=4, , Ionisation energy of ion = E – E1 = 217.6 eV, , 217.6, Z2 =, = 16 and Z = 4, 13.6, , or, , 10., , =1: 3 3, , Z2, therefore E1 = –217.6 eV = –13.6 × 2, 1, , h, m, , n=3, , 2m Be 3 q Be 3 V, , m pq p, , =, , h, , 2m p q p V, , therefore ratio, 5., , 22, cm., 1, , Wavelength of e ( ) = Velocity of e ( ), =, , V = Potential by which charged particles are, accelerated, 3, , 32, 1, , 2, , de Broglie wavelength, , Be, , –8, , = 5 × 0.529 × 10–8 = 2.646 × 10–8 cm, 8., , 6Ze, r, , 10 3600 60, 3.37 10 19, , Your Target is to secure Good Rank in Pre-Medical 2021, , h, 4, , and, , v=, , h, 4, 1, 2m, , h, , HS

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TARGET : PRE-MEDICAL 2021, 13., , PHYSICAL CHEMISTRY, , Circumference of 4 th orbit = 2 r4, and angular momentum m r4 =, de-broglie wavelength, , =, , 4h, ...(i), 2, , RH, , h, h, & m = ...(ii), m, , therefore from eq.(1) and (ii), h, , 4h, 2, , r4 =, , therefore, 18., , 4, , –, , 5, , = 912, , =, , 9 196, 2 45, , or ni2 – nf2 = 7, , thus the electronic transition is from 4th orbit to, 3rd orbit, , x=?, 19., , h, 4 m, , 6.626 10 Js, 4 3.14 10 3 kg 10 2 ms, , 1, , = 5.25 × 10–30 m, 15., , 1, 1, , and E2 (for Be+3) = –13.6 ×, , 16., , E1, E2, , 20., , 42, 22, , 13.6, 1, =, 13.6 4, 4, 32, 12, , Ionisation energy of Li+2 ion = 0 – 13.6, , 12, 12, , h, mv, , I.E. (of Li+2) = 9 × I.E. (of H), Wavelength of 4th line of Balmer series, , RH, , me v, , e, , m ball v, , h, , 1, 1 1, 4 36, , :, , 9.1 10, 0.91, , 31, , = 10–30 : 1, , e, , Circumference of orbit 2 r = n, , = 912 ×, , 4, , 5.32, = 1.33 nm, 4, , In H-atom ionisation energy is less than 1 eV is, for n = 4 (E4 = –0.85 eV) on wards. therefore, minimum value of n = 4., , 22., , (n – 1)d subshell has higher energy than ns, subshell for example 5d subshell has higher, energy than 6s subshell., , 23., , An orbital can be represented by using three, quantum numbers n, and m., E1 = E n 2, , E n1, , E2 = E n 3, , E n2, , E3 = E n3, , E n1, , therefore E3 = E1 + E2 and, ( E, ), , 9, Å, 2, , and also, , th, , and wavelength of 5 line of Balmer series, , =, , 21., , 24., , = 13.6 eV, , =, , h, , therefore, , and Ionisation energy of H atom= 0 – 13.6, , HS, , =, , and for 4th orbit 2 r4 = 4 = 5.32 nm, , = 122.4 eV, , 17., , ball, , ball, , E1 (for H) = –13.6 ×, , therefore,, , De-broglie wavelength, , v, 34, , =, , = 131.7Å, , In H-atom ri – rf = 7 × 0.529 Å, = 7 × 0.529, , v = 1 cms–1, , x=, , 912 196, Å, 45, , therefore 0.529 × ni2 – 0.529 nf2, , or2 r4 = 4, , and circumference of 4th orbit is equal to 4 times, to wavelength of electron., 14., , 1, 1 1, 4 49, , =, , 3, , 1, , 2, , E, , 1, , 3, , =, , 1, , +, , 2, , or E, , 5, , Your Target is to secure Good Rank in Pre-Medical 2021, , 5

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TARGET : PRE-MEDICAL 2021, 25., , 26., , Electronic config. of Cr, = 1s22s22p63s23p63d54s1 for electrons with, n + m = 3 in Cr there are 3 possibilities., (i) n = 2, m = +1, for two 2p electrons, (ii) n = 3, m = 0, for two 3s electrons +, two 3p electrons + one 3d electron., (iii)n = 4, m = –1, no electron of this type, therefore totally 7 electrons are in Cr with, n+m=3, h, A, P, P, h, A, = ;, = B, h, PA, P, B, PB, B, , PA, , A, , =, , PB, , =, , 31., , = 1400 ms, 32., , =, 28., , 1, n 22, , RH 4, , 1, 1, , 1, 9, , 9, 32 R H, , 19.6 10 18, J, 4, = –4.9 × 10–18 J, –Z2, , 30., , 18, , J, , or n, , 4.2178 10 34 2 3.14, =4, 6.625 10 34, , 1, Thus,, , RH, , 1, n12, , 1, n 22, , The transition spectral line for 4th to 3rd shell is, , 1, , 33., , 109678, , 1, 32, , 12, = 2, 3, , 1, 42, , = 1.8 × 10–4 cm, Energy of photon liberated from He+ during, emission of first line of Lyman series, 1 1, 2, = hC.RHZ 12 22, , 6.54 × 10 –11 = E1 of H +, , 3, 4, , 1, mu2, 2, , = 13.6 × 1.602 × 10–12 +, ? = –44.1 × 10–18 J, , Ni2+ : [Ar]4s°3d8, , 3d, n(n 2) B.M., , 1, mu2, 2, , 1, mu2 = 6.654 × 10–11 – 2.179 × 10–11, 2, = 4.361 × 10–11 erg, 4.361 10 11 2, 9.108 10 28, u = 3.09 × 108 cm sec–1, u2, , 2(2 2) B.M. = 2 2 B.M. = 2 × 1.42 B.M., = 2.84 B.M., , 6, , nh, 2, , = 6.54 × 10–11 erg, This energy is used in liberating electron from H, atom from ground state, therefore,, , Z 2H, Z 2Li2, , 4.9 10, ?, , m, , –1, , = 6.625 × 10–27 × 3 × 1010 × 109678 × 22, , E1(H) =, , E (H), E (Li2 ), , 10, , nh, = 4.2178 × 10–34, 2, , I.E.(SES) = –E1(H) × Z2, 19.6 × 10–18 J = –E1(H) × Z2, , E, , mur, , Given,, , 1, , 1, n 21, , R H Z2, , photon, , 6.6 10 34 Js, 9.1 10 31 kg 5200 10, , v, , = 10–7 m., n2 + n1 = 4, .....(i) and, 2, 2, n2 – n1 = 8, ....(ii), therefore n2 = 4 – n1, and from equation (ii) (4 – n1)2 – n12 = 8, 16 – 8n1 + n12 – n12 = 8, or, n1 = 1, and, n2 = 4 – 1 = 3, =, , =, , h, = 5200 × 10–10 m, mv, , 5 10 8 PA, PA / 2, , 1, , h, p, , From, e, , B, , 27., , PHYSICAL CHEMISTRY, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , CHEMICAL EQUILIBRIUM, 1., , PCl5(g), a, a– a, , PPCl3 =, , 2., , PCl3(g) + Cl2(g), b, c, b+a, c+a, nT = a + b + c + a, n PCl3, nT, , (b a ), P =, ×P, (a b c a ), , S8(g), At t =0 1 atm, At t = eq. 1 – p, , KP =, , p, , = 0.2, , 0.8, , 0.8, , pS8, , K, , p, 1, p = 0.2, =, , pCO2, , p H 2O, , 2p = 1.04, , KP = p CO2 p H2O, , p = 0.52 atm, , KP = 0.52 × 0.52, = 0.2704, K = 2 at Temp = T, =?, , B2, 2AB, a, 0, a – x 2x, , a – a, , a–a, , K=, , x, a, x=a, , 2a, , =, , 4a, (2a )2, =2= 2, a (1, (a a )(a a ), 2, , (1, , 7., , 1.8, [N2O3] : [NO] :, , p, , A2 +, a, a– x, , 2, 4, , )2, , taking squire root, , 2, , )2, , =2, , 1, , 0.2, , =, , 1.34, = 0.5726, 2.34, x, 0.5726, Conc. of CO =, =, = 0.573 mol L–1, V, 1, N2O4, 2NO 2,, when [N2O4] = 0.1 = [NO2], x=, , 1, , 9., , Q=, 1, ( 2 1), , HS, , x, = 0.1, a, x = 0.1 × 2, 0.2 0.2 x = 0.2, [NO2] = 1.8 : 0.2 : 0.2, =9:1:1, H2O(g) + CO(g), 0, 0, x, x, 0.2, , 8., H2(g) + CO2(g), t=0 1, 1, At t=eq. 1 – x 1 – x, x x, x2, V V, K, 1.8, 1 x 1 x (1 x)2, V, V, x, 1.8 = 1.34, 1 x, x = 1.34 – 1.34 x, 2.34 x = 1.34, , 1, 2, 1, 2, , 2, , 2, , =2, 1 x, x = 2 – 2x, 3x = 2, , x, 2, =, = 0.66, 66 %, a, 3 1, N2O3, NO + NO2, t=0 2, 0, 0, 10% =, t = eq 2 – 0.2, , p H 2O, , x, , =, , = 0.512 atm 3, Na2CO3(s) + CO2(g) + H2O (g), 0, , 4, , 2, 3, , x=, , (0.8) 4, = (0.8)3 atm3, (0.8), , CH3COOC2H5 + H2O, 0, 0, x, x, , x2, (1 x) 2, , n, , 4p, 4 × 0.2, , ps42, , x x, v v, (1 x) (1 x), V, V, , taking squire root =, , 0, p CO2, , 4., , 4S2(g), , 1 – 0.2, , 3., 2NaHCO3(s), t=0, 0 atm, t = eq, , 5., C2H5OH +CH3COOH, t=0, 1, 1, t = teq 1 – x, 1– x, , [NO 2 ]2, [N 2 O 4 ], , Q < Kc, , [0.1]2, = 0.1 M, [0.1], , Reaction goes forward direction, Kc = Q, at point D & F, equilibrium is attained, Your Target is to secure Good Rank in Pre-Medical 2021, 7

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TARGET : PRE-MEDICAL 2021, 17., , pH, , 1, pk a, 2, , 1, log C, 2, , 25., , 1, (4 log10 2 ), 2, , [H+]=, , 2 0.09 1000, 180, 100, , C, , =, , PHYSICAL CHEMISTRY, , M1 V1 M 2 V2 25 0.5 10 0.5, =, 35 15, V1 V2 VH 2O, , 7.5, 50, , 3, 20, , pH = –log [H+], , 1, (4 2), 2, , 18 10, 18, , C, , 2, , M, , –log, , =3, 18., , 3Ag+ +, , Ag3PO4, , 26., , s, , Ksp = (3s + 0.1)3 (s) = 1.1 × 10–16, 10–3 × s = 1.1 × 10–16, s = 1.1 × 10–13, 19., , pH = pkIn + log, , In, H In, 75, 25, , 5.48 = pkIn + log, , 27., , PbBr2, Pb+2 + 2Br–, s, 0.8 s 1.6 s, Ksp = 0.8 s × (1.6)2 s2, s3 =, , 8 10 5, Ksp, =, 0.8 (1.6)2, 0.8(1.6)2, , s=, , 10 4, 1.6 1.6, , pH = 7 +, , pkIn = 5.48 – log 3 = 5.48 – 0.48 = 5, =7+, , kIn = 1 × 10–5, 20., , (CH3)2 NH2, , 21., , +, , (CH3)2NH + H+, , A (aq.) + X–(aq.), , BX2, , B+(aq.) + 2X–(aq.), s, , Ksp1 = s2, Ksp 2 = 4s'3, , 2s, , s2 = 4s'3, 22., t=0, , 0.01, , teq, , 0.01 – 0.01, , 0, , NH4+ + Cl–, , 0.01, , 0.01 0.01, (0.01 )(0.01, 0.01(1, , 2 × 10–5 = 0.01, = 2 × 10, %, 23., 10, , 1, (pka + log C), 2, 1, 5, 10 log 5 log, 2, 10, , 1, [10 – log5 + log5 – log 10], 2, 1, = 7 + [9], 2, pH = 11.5, CO2, H2CO3, HCO3–, CO3–2, s2 = 6.25 × 10–18, s = 2.5 × 10–9, M = 2s = 2 × 2.5 × 10–9, = 5.0 × 10–9 M, , 0, , (0.01 + 0.01) 0.01, , NH4Cl, , Kb =, , 28., 29., , NH 4 + + OH –, , NH 4OH, , 1, 3, , =7+, , conjugate base, AX, , = +log 20 – log 3, , = 1.3 – 0.48 = 0.82, , PO4–3, , (3s + 0.1), , 3, 20, , 30., , 10.4 = 9.4 + log, , 0.01), ), , (1 +, , ), , Ksp(BaCrO4) < Ksp(SrCrO4) < Ksp (CaCrO4), , Salt, Acid, , 0.01, x, , 0.01, 0.01, ; 10 =, x, x, –3, x = 0.001 = 10, [H+]1 = 10–3 [H+]2 = 10–5, 1 = log, , –3, , = 2 × 10–3 × 100 = 0.2, , pH = pka + log, , 31., , [H1 ], [H 2 ], , 10, 10, , 3, 5, , =, , 100, 100 : 1, 1, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 34., 32., , KCN + HCl, 0.04, 0.02, 0.02, 0, , n0 :, nf, , pH = pKa + log, pH = 6 + log, , 33., , KCl + HCN, 0.02, , where c = [CH3COONa] =, , 1, 10, 2, =, , w H 2SO4, , HS, , 10, 2, 2, , = 2 × 10–5, [OH ], , 10 3, M, [H2SO4] =, 2, , 10 2, n H 2SO4, 1mol, 2, Now ATQ,, , n H 2SO4, , 1, 0.009 mol, 2, , 10, , 14, , 5 10, 2 10 5, , 2, , 2.5 10, , 3, , 11, , = 5 × 10–6 M, 35., , Ksp = 4s3 = 4 × (5 × 10–6)3, = 4 × 125 × 10–18, = 5 × 10–16, 10 14, [OH ] in buffer solution =, 10 8, Ksp = [Pb2+] [OH–]2, 5 × 10–16 = s × (10–6)2, –, , 3, , 1, 10, 2, , 10 3, 1mol, 2, , 1 0.25, = 0.05 M, 1 4, , Kw, 10 14, & Ka for CH3COOH = K =, 5 10 10, b, , II case, pH = 3, [H+] = 10–3 M, , n H2SO4, , Kw C, Ka, , n HCN, , 10 2, M, [H2SO4] =, 2, , n H 2SO 4, , =, , n CN, , =6, I case, pH = 2, [H+] = 10–2 M, , 10, 2, , The nature of the mixture is basic only due to, CH3COONa, [OH–] = Ch, , 0.02, , 0.02, 0.02, , 2, , PHYSICAL CHEMISTRY, , s=, , 10, , 6, , M, , 5 10 16, = 5 × 10–4 M, 10 12, , 1, 0.009 98g, 2, = 0.009 × 49 g, = 0.441 g, , Your Target is to secure Good Rank in Pre-Medical 2021, , 11

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SOLID STATE, 1., , 6., , For bcc, 4r = a 3, r=, , 2., , Z M, , 7., , Z 120, 6 10, (4 10 8 )3, , Cu2+, , 1, 1, +6×, =4, 8, 2, , z=8×, , a=, =, =, =, M=, , 4., , 4 M, 6 10, (5.6 10 8 )3, 23, , 0.559 nm, 0.559 × 10 –9 m, 5.59 × 10–10 m, 5.59 × 10–8 cm, 3.19 6 10, , 23, , 8., , 10, , 24, , 175.6, , 8, No of moles of element X =, = 0.1 mol, 80, No of atoms of element X = 0.1 NA, For fcc' 4 atoms = one unit cell, , O2–, , 4 M, NA, , 1, 1, +6×, =4, 8, 2, , 1, 1, THV =, ×8=1, 8, 8, , B3+, , 1, 1, OHV =, ×4=2, 2, 2, , 4r, 2, , 3, , (d)fcc =, , 2 2 4 M, N A 64r 3, , (d)bcc =, , 2 M, =, NA a3, , 1, unit cell, 4, , A2+, , AB2O 4, 16, , ccp = 8 ×, , x, 1.8 – x, by law of conservation of charge, 2 × x + (1.8 – x) × 1 = 2, 2x + 1.8 – x = 2, x = 2 – 1.8, x = 0.2, 0.2, % Cu2+ =, × 100 = 11.11%, 1.8, 4 M, (d)fcc =, NA a3, , 84, , 0.1 N A, 0.1 NA =, unit cell, 4, 5., , Cu+, , (d)fcc =, , 4, , 1 atom =, , IIIrd nearest neighbours (0.85a) distance = 8Cl–, Cu1.8S, Nonstoichiometric compound, , z=2, , 23, , Z M, d = N a3, A, 3.19 =, , distance = 12Na+, , 2, , d = N a3, A, , For fcc,, , a, , IInd nearest neighbours, , So crystal lattice is bcc, 3., , a, distance = 6Cl–, 2, , So 1st neighbours at, , a 3, 350 3, =, = 151.5pm, 4, 4, , 6.25 =, , In NaCl, Na+ are present in OHV, , (d)bcc =, , ...(1), 2 M, , NA, , 4r, 3, , 2 M, 3 3, N A 64r 3, , (d) fcc, Ratio (d), bcc, , 2 2 4 M, N A 64r 3, , 4 2, (d)fcc, =, 3 3, (d)bcc, , 3, , ...(4), NA, , 64r 3, , 2M 3 3, , 4 1.4, 3 1.7, , 5.6, (d)fcc, =, (d)bcc, 5.1, (d)bcc, 5.1, =, = 0.918, (d)fcc, 5.6, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 9., , a = 5 × 10–8 cm, d = 3.84 g/cm3, , 14., 15., , Z 72, 3.84 =, 6 10 23 (5 10 8 )3, 23, , Z=, , 10., , 3.84 6 10, 125 10, 72, , =4, , no. of formula units = 4, So, +2, 2–, no. of Fe = 4,, no. of O = 4, Calculated density, , 13., , % efficiency =, , 2.4 10 3 1000g, × 100, 2.5, 10 6 cm 3, , =, , 2.4, 24, × 100 =, × 100, 2.5, 25, , % efficiency = 96%, Along body diagonal, 2 corner, 1 OHV, 2 THV, 2A, C, 2D, fcc = 6 ×, , Y, , OHV = 12 ×, , a3 =, , 17., , A, , 8×, , 1, 1, 6, =4, 8, 2, , B, , 4×, , 50, =2, 100, , 50, =4, 100, Formula of compound A2BC 2, , 18., , 2, 2, × OHV = × 6 = 4, 3, 3, Al4O6, formula, Empirical formula = Al 2O3, 19., , A, , 1, , B, , 8×, , 1, =1, 2, Empirical Formula, C, , 20., , A, , 21., , A, , 7×, , 1 7, =, 8 8, A7B24, , A, , ABC, B, , 6×, , 1, =3, 2, , 1, 1, +6× =4, 8, 2, 8=8=N, 8×, , no. of A atoms =, O2–, , 1, =1, 8, , 2×, , A7/8 B3, , 22., , rCd 2 = 2.25 – 1.24, , 1, 1, +2× +3=6, 6, 2, , Al+3 =, , 4 128, = 10.31 × 10 –23 cm3, 6.023 10 23 8.27, , rCd 2 + 1.24 = 2.25, , O2– = 12 ×, , B, , 2rO2 = 4.5, , 1, +4×2=9, 8, , C=8×, , 4 128, 6 10 23 a 3, , a = 4.5 × 10–8 cm, a = 4.5Å, 2rCd2, , = 0.225 (for THV), , In a unit cell no. of atoms =8 ×, , 1, =3, 4, , Z, THV = 6, X15/4 Y3 Z 6, X15 Y12 Z24, X5 Y4 Z 8, Z = formula units = 4, 8.27 =, , rB, , 16., , 1, 1 15, +6× =, 8, 2, 4, , X, , rA, , rA = 200 × 0.225 = 45 pm, , 10, =, = 2.5 g/cm3, 4, , 12., , Do your self, , 24, , 4 24, 4 24, =, 23, 8 3 =, 6 10, (4 10 ), 6 10 1 64, , 11., , PHYSICAL CHEMISTRY, , N, = 4, 2, , 1, 1, 8× +6× =4, 8, 2, 1, 4, ×8=, 6, 3, , 1, 4, ×4=, 3, 3, Empirical formula= A4/3 B4/3 O4, B, , rCd 2 = 1.01 Å, , HS, , Your Target is to secure Good Rank in Pre-Medical 2021, , ABO3, 17

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TARGET : PRE-MEDICAL 2021, 23., , 24., 25., , A, lattice point, B, all the THV, C.N. = 8, 4, 4, 4, 8, 6, , 27., , 26., , no. of moles of NaCl =, , In a unit cell, n = 1 for cubic crystal, Density, , 10, 58.5, , 10, × NA, 58.5, , 4 formula units of NaCl = 1 unit cell, , n Formula mass, V At. no., , n Formula mass, a 3 At. no., 3.97, , no. of formula units =, , PHYSICAL CHEMISTRY, , 1 168.36, a 3 6.023 10 23, , a = 4.13 × 10–8 cm, a = 4.13 Å, For a cube of side length 4.13 Å,, , 10N A, 58.5, , Diagonal =, , 1 10N A 2.5N A, =, formula units of NaCl =, 4 58.5, 58.5, , 28., , 3 4.13 7.15 Å, , As it is a bcc with Cs+ at centre (radius r+) and, Cl– at corners (radius r–) so,, 2r+ + 2r– = 7.15 or r+ + r– = 3.57Å, i.e., distance between neighbouring Cs + and, Cl– = 3.57 Å, Now, assum two Cl– ion touch with each other, so,, Length of unit cell = 2r– = 4.13 Å, r– = 2.06 Å, r+ = 3.57–2.06 = 1.51, r+/r– = 1.51/2.06 = 0.73, A+, B–, , 4, , 1, 1, 4, 8, 2, , 1, 2, 2, 2.5, AB, , 18, , Your Target is to secure Good Rank in Pre-Medical 2021, , 10, , 1, 4, , 2.5, , HS

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , CHEMICAL KINETICS, 1., , 2., , H2O + O, 2OH, H = 72 kJ, H = Ea.f – Ea,b, 72 = 77 – Ea,b, Ea,b = 77 – 72 = 5 kJ, For first order, r1 = KICA0, r0 = k0, For zero order, K I CA 0, , r1, r0, , k0, , 9., , t=, , C A0, , K1 =, , 2.303, 100, log, ;, t, 10, , K1, K2, , 2 log10, =1, log100, , 2.303, 100, log, 2t, 1, , K2 =, , log, , K 27 ºC, K 47ºC, , log, , 1, 4, , 2, , k[0.4][0.4], k[0.6][0.8]2, , 0.4 0.4 0.4, 0.6 0.8 0.8, , 11., , 13., , Ea, 2.303 8.314, , 1, 300, , 20, 320 300, , 0.6 320 300 2.303 8.314, 20 1000, , from given condition [A], , KI =, , 0.693, 40, , 0.693, 40, , KO =, , 1.386, 2 20, , KI, KO, , 1, –1, 3, 2 = 0.5 mol dm, , 0.693, 20, , From first experiment, 0.1 = K[1] [0.2]2, , 1, 6, , K = 2.5, r = 2.5[2] [0.6]2 In exp. II, , It is zero order reaction, x = kt, x = 1.2 × 10–2 × (10 × 60), x = 7.2 M, Apply formula, , on solving for t,, , Ea, 1, 2.303R 320, , = 55.14 kJ/mol, , = 1.8 M s–1, 14., , Remaining concn = initial concn, , HS, , 2.303, 100, 2.303, × log, =, log2, 5, 50, 5, , Ea =, , [A]0, e, A + 2B, C+D, initally, 0.6, 0.8, At time t 0.6 – x 0.8 – 2x x x, given, x = 0.2, At time t PA = 0.6 – 0.2 = 0.4, PB = 0.8 – 0.4 = 0.4, rinitial = k[PA] [PB]2, rt = k[PA] [PB]t2, rinitial, , 8., , K47ºC =, , [A]t = A0e–kt, , rt, 7., , 2.303, 100, 2.303, × log, =, log2, 20, 50, 20, , 2K 0, , [A]t = A0 e–1=, 6., , K27ºC =, , t1/2,I = t1/2, Zero, , r1, = 2 × 0.693, r0, , 4., , 2.303, 1, 3 log, 2.303 10, 0.25, , t = 1000 × 0.6 = 600 second, 10., , 0.693, KI, , 3., , It is a first order reaction, , 1, 2, , 1, 2, , t/5, , =, , No. of half lives, , [A] 1, 4 2, , K, A, , e, , –, , Ea, RT, , 0.0001, 100, , Ea, = 2.303 log 10–6, RT, , Ea = 2 × 400 × 2.303 × 6, t /15, , = 11.05 k Cal/mol, , t = 15 min, , Your Target is to secure Good Rank in Pre-Medical 2021, , 19

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TARGET : PRE-MEDICAL 2021, 15., , mol, , 2.303, V, log, t, V Vt, , K, , 2.303, 10, log, 20, 10 5, at t = 10 min., , 2.303, 10, log10, 40, 10 Vt, , ...(2), , 19., , 2.303, 10, log, 40, 10 Vt, , 10, 10 Vt = 4, , 10, log 22 = log 10 V, t, , Vt = 7.5 mL, , t1/ 2, , 1, , t1/ 2, t1/ 2, , 0.693, K1, , t1/ 2, , K2, K1, , 3, 2, , 1, 2, , 0.693, K2, , 2, , 20., , K2, K1, , 3, 2, , 17., , t 25%, t 75%, , 3, 2, , C(1, , C(10, , n), , put n = 3, , n), , t 25%, t 75%, , concentration i.e. =, 20, , 2, , 21., , 0.311, 1, , C0 2 = 2 kt, , mol, , 100, 50, , n 1, , ...(2), , = (n – 1) kt, , C, , = 30, , from given data, , Again, , 0.602, 0.1249, , 0.1249, 0.602, , 2.303, a, log, k, 2a / 3, , n 1, , 3.52, P, 1.5, 50, P = 50 × 2.34, P = 117, , 2.303 0.602, 2.303 0.1249, , t 75%, t 25%, , P2, P1, , ...(1), , K2(t)75% = 2.303 log, , K 2 (t) 75%, K1 (t)25%, , (t1/ 2 )1, (t1/ 2 )2, , 2 = 2n – 1, n–1 =1, n=2, , K1(t)25% = 2.303 log, , 100, 25, = 2.303 × 0.602, From equation (2) / (1), , 0.693, K, , a0, 0.693, min–1, Kt = 2.303 log a x, 60, 0, 0.693, 8, × t = 2.303 log, 60, 7, t = 11.56 minutes, Given t67% – t33% = 30, , 8.52, 1.96, , 100, 75, = 2.303 × 0.1249, , 60 =, , 2.303, [log3 – log3 + log2] = 30, k, 2.303 0.3 2.303, k=, 30, 100, 2.303, a, t25% =, × 100 log, 2.303, 3a / 4, 4, t25% = 100 × log, 3, = 100 × 0.123 = 12.3 min., , 10, 2 log2 = log 10 V, t, , 16., , 2, , 2.303, a, log, k, a /3, , from (1) & (2), 2.303, log 2, 20, , = K × second, , K=, , 2.303, log2 ...(1), 20, , K=, , K=, , 18., , 2, , mol–2 sec–1, 0.693, t1/2 =, K, k=, , V = vol. of gas collected at the end of reaction, Vt = vol. of gas collected at any time 't', at t = 20 min., , PHYSICAL CHEMISTRY, , 22., , 2 1, , P, 50, , 3.52, 1.5, , A(g), 2B(g) + C(g), Initial pressure :, 0.5, 0, 0, Pressure after 2 hrs.: 0.5 – p, 2p, p, Total pressure after 2 hours = 0.5 – p + 2p + p, = 0.5 + 2p, Given that : 0.5 + 2p = 0.7 or p = 0.1, Pressure of A after 2 hours = 0.5 – p, = 0.5 – 0.1 = 0.4, Units of rate constant suggest that it is a first, order reaction., Rate of reaction after 2 hours = k[A], = 10–3 × 0.4 = 4 × 10–4 atm s–1, Eaf – Eab = H, 70 – Eab = – 22, Eab = 92 kCal, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SOLUTION AND COLLIGATIVE PROPERTIES, 1., , molality =, , n, × 1000, wg, , =, , 201624 2000, 186 2168 1000, , 1+2 =1, , n, molality =, × 1000 = 2n, 500, , 2 =0, =0, , Tb = Tb – Tb0, , Hence Hg(NO3)2 is fully ionised but HgCl2 is, unionized., , Tf = Tf0 – Tf, Tb + Tf = (Tb – Tf) + (Tf0 – Tb0), , 3., , ( Tf)I = Kf × m, , (Kb × m + Kf × m) = 103.57 + (0 – 100), 0.2 = 1.86 ×, , (0.52 + 1.86) × 2n = 3.57, n=, , 357, 3.57, =, mol, 2 238, 2 2.38, 357 1000, = 750 millimol, 2 238, , no. of millimol =, 2., , x=, , x, 1000, 100, , 0.2, 2, =, mol, 1.86 10, 186, , ( Tf)II = 1.86 ×, , 2 1000, 186 W, , For Hg(NO3)2, Tf = i × Kf × m, , 0.25 = 1.86 ×, , 0.0558 = (1 + 2 ) × 1.86 ×, , 3.24 1000, 324 1000, , 2 1000, 186 W, , W=, , 2 1000, 25, , W = 80 g, Amount of ice separated out = 100 – 80 = 20 g, , 1+2 =, , 0.0558, × 100, 1.86, , 1+2 =, , 5.58, 1.86, , 4., , Higher is (i × c); higher will be Tf, So, lower, will be Tf, i × c for, , KNO3 = 2 × 0.05 = 0.1, BaCl2 = 3 × 0.04 = 0.12, Sucrose = 1 × 0.140 = 0.14, , 2 =3–1, , CuSO4 = 2 × 0.075 = 0.15, , 2, =1, =, 2, , 100%, , 5., , i=1+2, 1.98 = 1 + 2, , For HgCl2, , 2 = 0.98, , Tf = 1.86 ×, , 1+2 =, HS, , 21.68 1000, (1 2 ), 271 2000, , = 0.49, %, , = 49 %, , 0.0744 271 2000, 1.86 21.68 1000, , Your Target is to secure Good Rank in Pre-Medical 2021, , 21

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TARGET : PRE-MEDICAL 2021, 6., , P = PA0 × 0.5 + PB0 × 0.5, PA0 + PB0 =, 1 + x = PA0 ×, , 1, =2, 0.5, 1, (1 3), , .....(i), 9., + PB0 ×, , 3, 4, , 1 L solution contains = 10–2 kg gas, 0.25 L solution contains = 0.25 × 10–2 kg, = 2.5 × 10–3 kg, For S1; i1 × C1 = 2 × 0.1 = 0.2 Hypertonic, For S2; i2 × C2 = 2 × 0.05 = 0.15 Hypotonic, , 10., , Molarity =, , 11., , PB0, , 0.25 PA0 + 0.75 PB0 = 1 + x, , 1 x, 3P =, 0.25, , 0, A, , 0, B, , P, 1 = PA0, , 1, 3, 4, PB0, PC0, 8, 8, 8, , 1 = PA0, , 1, 3, 4, PB0, 0.8, 8, 8, 8, , 3PB0, 8, , PA0, = 0.6, 8, 3PB0 = 4.8, , PA0, , .....(ii), , 12., , 13., , 8., , 14., , x, 5.6, 400, 5.6 = 10, 224, , m P so,, 4 10, m2, , m 1 P1, =, m 2 P2, 3, , Molality =, , 100, 250, , i×c, , 22, , 25 4 10, 10, , PB0, 0x, B, , PB0, , 138, , PA0, 0 x, A, , PA0, , 258 mm of Hg, , lim, , 3, , = 10–2 kg L–1, , 18 1000, = 0.197m, 60 1518, Tb, Tb, , 1 1, 1, = 0.0555, 180 0.1 18, 1, 1, 10, =, 1% sucrose = (i × c) =, = 0.029, 342 0.1 342, 1, 1, × 2 = 0.34, 1% NaCl in H2O = (i × c) =, 58.5 0.1, 1 3, 1% CaCl2 = (i × c) =, = 0.27, 111 0.1, PS = PA0 xA + PB0xB, = PA0 · xA + PB0(1 – xA), PS = (PA0 – PB0)xA + PB0, .....(i), P = 120 xA + 138, .....(ii), Equating (1) & (ii), PA0 – PB0 = 120,, PB0 = 138 mm of Hg, PA0 = 120 + 138, = 258 mm of Hg, From equation, When xA = 0, xB = 1, xA, , m2 =, , 18 1000, 60 (1578 60), , 1% glucose = (i × c) =, , x, ; x is volume strength of H2O2, 5.6, , x, 6.8 1000, =, 5.6, 17 2240, , x=, , PB0, , Molality =, , So from (i) & (iii) ; (iii) – (i), 2PB0 = 4.8 – 2 = 2.8, PB0 = 1.4 atm, PA0 = 2 – PB0 = 2 – 1.4 = 0.6 atm, , 400, 224, , 0.5, 0.0076, 65, =, = 0.0073, 0.5 158, 0.0076 102, 65 154, , PS, , .....(iii), , x 0.2, , N=, , total moles 36 50, = 9M, =, 2 100, total vol, , 143 PS, = 0.0073; PS = 143 – 143 × 0.0073, 143, PS = 143 – 1.052, PS = 141.93, , 1 x, from (ii) & (iii), = 4.8, 0.25, 1 + x = 1.2, , 7., , PHYSICAL CHEMISTRY, , lim, , xB, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 15., , 4nA = 10, , PB0 P, = xsolute, PB0, , nA =, , PB0, , 0.95PB0, = xsolute, PB0, xsolute = 0.05, xsolvent = 0.95, , nA, nB, , xA, xB, , wA, mA, , mB, wB, , wA, wB, , 1 mA, 19 m B, , 5, 95, , 19., , 1, 19, 1, mA, 1, =, 19 0.3m A, 5.7, , wB, = 5.7, wA, Molecular mass = 12 × 11 + 8 + 32, of napthoic acid = 132 + 40, = 172, Tf = i × Kf × m, , 2 = i × 1.72 ×, 2=i×, , i=, , 17., , PA0, PB0, , 20., , yA =, , PA0 x A, PA0 x A PB0 x B, , 18., , PB0, , 1, 5, , n A 10, , nA, n A 10, , nA + 10 = 5nA, HS, , SP = SR + SQ, [H+] = 10–2 = C, 1, , ( Tb)I = Kb ×, , 0.1, 1000 .....(i), m P 100, , ( Tb)II = Kb ×, , 0.1, 1000, m Q 100, , .....(ii), , MQ, , ( Tb) I, ( Tb) II, , 0, B, , P xB, , MP, MP, MQ, , MQ, , 0.2, 0.4, 23., , nA, , PB0 x B, , I/II, , xB, 2, , 1, 5, , 4 0, PB, 5, , PS = PA0 x A, , 10 2 10 2, 10, C, 0.1, i=1+, = 1 + 0.1 = 1.1, P = i × CRT, = 1.1 × 0.1 RT, = 0.11 RT, , 1, 2, PB0, 2, = 0, PB x B, 4, , 150 × 0.78, = 2.99 m, 46×0.85, , =, , 22., , yA = 0.2, PB0, , 21., , 20 1000, 172 50, , 2, = 0.5, 4, , PB0 x B, yA =, 5 PB0 x B, , wA, = 2.5, 40, wA = 40 × 2.5 = 100 g, Mass of C2H5OH = 150 × 0.78 g, Volume of water added = 1000 – 150 = 850 mL, Mass of Water = 850 g = 0.85 kg, , SP = PA0 0.2 0.8 PB0, , 20, 5, , 1 xA, ,, 2 xB, , 10, = 2.5, 4, , Molality =, , Hence, 16., , PHYSICAL CHEMISTRY, , MP, , 2, 1, , = 1+ 2, = C1RT1 + C2RT2, =, , 0.6 3, 60 0.6, , =, , 1, 10, , 1, 3.42 3, RT =, 6, 342 0.6, , 1, RT, 20, , × 0.082 × 293, , P = 2.4 atm, , Your Target is to secure Good Rank in Pre-Medical 2021, , 23

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TARGET : PRE-MEDICAL 2021, 24., , NHCl, , 29., , 0.03659, =, × 1000, 36.5, , NHCl =, , 36.59, =1, 36.5, , N CH3COOH, , 0.04509 1000, 60, , N CH3COOH, , 45.09, = 0.75, 60, , m exp, , P, , 480 1.5 520 1.2, Mfinal =, 1000, , n (solute), n (solvent), , RLVP = Xsolute, , Now,, , or, , 30., , MM (A), MM (B), , 2, 1, , MA, MB, , 28., , Thus, , RT, M, , 300, x × 10 = 0.0821, 300, x × 10–2 = 8.21 × 10–2, x = 8.21, –2, , 24, , CRT, M, , RT, M, , OA = log(x × 10–2) = log, , x × 10–2 =, , mN, (1 2 0.7), , 164, 2.4, , 68.33, , For monobasic acid HA, HA, H+ +, 1, 0, (1– ), From Ostwald dilution law,, , Now,, , i, , RT, M, , 7 18, 68.33 100 = 0.0184, , 760, = 746.27 mm, 1.0184, , K, W RT, M V, , log = logC + log, , = 0.7), , P, Ps – 1 = 0.0184, , MA = 2 × M B, , n, RT, V, , Ps, Ps, , Ps =, , MM (solvent ), , (For the same amount of the same solute in same, amount of solvent), RLVP(A), RLVP(B), , (, , o, Also at 100°C, PH2 O = 760 mm, w = 7g, W=100 g, , 720 624, =, = 1.344 M, 1000, 26., , Ca2+ + 2NO–3, 0, 0, 2, , Ca(NO3)2, Before dissociation, 1, After dissociation, (1– ), Total mole at equilibrium, = (1+2 ) = (1+2×0.7) = 2.4, mN, For Ca(NO3)2 : m, =1+2, exp, , So NHCl > N CH3COOH, 25., , PHYSICAL CHEMISTRY, , C, (1, , A–, 0, , 2, , ), , Tnor = K'f × molality = 1.86 × 0.025, = 0.0465, Observed T, Calculated T, , 1, , 0.06, 1, 0.0465, = 0.29 and C = 0.025 M, By Eq. (1),, i, , K, , 0.025 (0.29) 2, (1 0.29), , Your Target is to secure Good Rank in Pre-Medical 2021, , 2.96 10, , 3, , HS

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , ELECTROCHEMISTRY, 1., , +3, , Initial equivalent of Cr, , but at equilibrium condition Ecell = 0, , = M × V × V.F., , 0.2 ×, , 250, ×3, 1000, , 0.0591, log Keq, n, , E ocell, , 0.15, , Final equivalent of, , 250, ×3, 0.075, 1000, Left equivalent of Cr+3 = 0.15 – 0.075 0.075, Cr+3 = 0.1 ×, , w=, , equivalent weight I t, 96500, , n E ocell, 0.0591, , log Keq =, , 2 0.32, 0.0591, , K eq, , 96.5 t, 96500, t = 75 sec., NaCl + 4H2O, NaClO4 + 4H2, –1, +7, Change in oxidation no. of NaClO4 (V.F.) = 8, Molecular wt. of NaClO4 = 122.5 g/mole, 0.075 =, , 2., , log10 Keq =, , 1000, = 8.16, 122.5, No. of Faradays = 8.16 × 8 65.3 66, HA + NaA, acidic buffer solution, , 6., , 10, , % efficiency of a cell =, 84 =, , (pH)Aanode = pKa +log, , 7., , 0.0591, (1)1 / 2, log, 1, 1, Ered = E°red = 0, At 100 atm pressure, , (1), =4, (1), , 2Ha+ + 2e–, H2, 2Ha+, , (H a ), 0.0591, log, (H c ) 2, 2, , 0.0591, 10, Ecell = 0 –, log, 10, 2, , 5, , HS, , E1red, , 0, – 0.0591, E red, , For the following concentration cell, 2Cl–(0.1 M), , Cl2(0.4 bar) + 2e–, 2Cl–(10–2 M), , Cl2(0.4 bar) + 2Cl– (10–2), , Zn+2 (0.01 M) + Fe, , 0.0591, 10, log, 2, 10, , – 0.0591, , 2Cl–(0.1 M) + Cl2(0.2 bar), , 4, , 0.0591, (Zn 2 ), log, 2, (Fe 2 ), , o, 0.2905 = E cell, , E ocell = 0.32, , E 0red, , for conc. cell, , Zn(s) + Fe+2(0.001 M), Ecell = E ocell, , 8., , Cl2(0.2), , 2, , Ecell = 0.06 V, 5., , 0.0591, (100)1 / 2, log, 1, 1, , E1red, , E1red = 0 – 0.0591, 2, , Ecell = (Ec° – EA°) –, , 1, H (g) (1 atm), 2 2, , H+ + e–, , At 1 atm pressure Ered = E°red –, , [H+]Anode = 10–5, , At Anode, H2, At Cathode2Hc+ + 2e–, 2Hc+, , nFE cell, × 100, H, , 2 96500 E cell, 100, 285 10 3, Ecell = 1.24 volt, , (1), [Salt], = 4 + log, =5, (0.1), [Acid], , Similarly (pH)Cathode = 4 + log, , G, × 100, H, , 84 =, , Mol of NaClO4 =, 4., , 0.32, 0.0295, , 2, , Ecell = 0 –, Ecell = –, , E 0cell = 0, , 0.0591, (10 2 )2 (0.4), log, 2, (0.1) 2 (0.2), , 0.0591, log (2 × 10–2), 2, , 3, , Ecell = 0.051 volt, , Your Target is to secure Good Rank in Pre-Medical 2021, , 25

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TARGET : PRE-MEDICAL 2021, 9., , Mg(s) + 2Ag+(aq), , Mg+2(aq) + 2Ag(s), , Ecell = E°cell –, , 0.0591, [Mg 2 ], log, n, [Ag ]2, , Ecell = 3.17 –, , 0.0591, (2 10 2 ), log, 2, (10 3 )2, , 0.0591, × 4.3, 2, = 3.17 – 0.129, = 3.04 volt, G° = – nF E°cell, = –2 × 96500 × 3.17, = –611.8 kJ, , 15., , According to nernst equation, , (0.120), 0.0591, log, (10 4 )2, 2, Ecell = 2.96 volt, e.m.f. of cell will not be zero because acetic acid, is weak electrolyte (Acid) which is not completely, ionised., Stronger is reductant. weaker is its conjugate, oxidant and vice-versa., , Ecell = 3.17 –, , 17., 18., ClO3, , ClO, , 10., , ClO, 1, , 1, Cl 2, 2 0, ClO3, , Cu, , 0.0591, 1, log, Ered = E°red –, [Cu 2 ], 2, , on increasing [Cu ] Erd, therefore order of S.R.P. Q > R > S > P, 12., , W=, , eq.wt. Q, 96500, , 19., , eq.wt. Q, 96500, (Area × Thickness) × d, (a × b × c) × d =, , (10 × 10 × 10–2) × 8.94 =, , 8.94 96500, 31.7, diameter = 2r, , Q=, 14., , 31.7 Q, 96500, , 1, 0.5 cm, 2, Area (A) = r2, 3.14 × (0.5)2, 0.785 cm2, r=, , Molar conductivity (, , m), , 0.40, , G 02, , Cl, , n3 = 1, , E 3o 1.36, , G 03, , n= 6, , Eo = ?, , 1, , Cl, , 1, , G 04 = ?, , Gº = G10, G 20, G30, 0, 0, nEº = n1E1 + n2E2 + n3E30, 4 0.50 1 0.40 1 1.36, Eº =, 0.63 volt, 6, If same quantity of electricity is passed then, equivalent of Cu+2 = equivalent of Cu+, W, W, eq.wt Cu 2, eq.wt Cu, WCu 2, , WCu, , At.wt./ 2, , At.wt. /1, , 1, 2, , Anode half reaction H2(g), Cathode half reaction, , 2H+(C) + 2e–, , Hg2 Cl2 (s) 2e, 2Hg( ) 2Cl (1M), H 2 (g) Hg2 Cl2 (s) 2H (C) 2Hg( ) 2Cl (1M), , =, , 1000, M, , 1, 50, 1, 1000, 1000, 3, A R, 0.785, 5.55, 10, ( m) =, =, M, 0.05, 2, –1, 229.65 cm mol eq, , 26, , G10, , E o2, , WCu, , 20., , 0.50, , n2 = 1, , WCu 2, , 27172 C, , E1o, , 1, Cl 2, 2 0, , 5, , +2, , n1 = 4, , 1, , 5, , [Mg2+ ], Q=, = 20000, [Ag+ ]2, Q = 20000, Cu+2 + 2e–, , 0.0591, (Mg 2 ), log, (Ag )2, n, , Ecell = E°cell =, , 16., , Ecell = 3.17 –, , PHYSICAL CHEMISTRY, , Ecell = E, , o, cell, , [H ]2 [Cl ], 0.0591, log, (PH2 ), n, , 2, , 0.0591, (H ) 2 (1) 2, log, 0.55 = (0.28 – 0) –, 2, 1, 0.55 = 0.28 – 0.0591 log [H+], , 0.55 0.28, = PH, 0.0591, PH = 4.57, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , PHYSICAL CHEMISTRY, , SURFACE CHEMISTRY, 1., , As 2 S 3 is an example of (–)vely charged, colloidal solution. So valency of (+) charge;, coagulation power., , 13., , (excess), , 3., 4., 5., , (excess), , a, c, d are correct, will be coagulation power, , Both colloids have opposite charge so they, coagulate with each other., , cogulation value, , C6H33N+(CH3)3 Cl–, Slope = m = tan 45° =, , 1, n, , 14., , x, m, , = 0.15, , log k, , 1, log P, n, , 15., 16., , Intercept = log k = 0.30, , 17., , 1, x, = k Pn, m, , 9., 10., , log, , HS, , 1, n, , 1, , x, 1, = log K + log P; O, m, n, , 1, n, , 1, , Lyophilic sols are protective colloids because, They stabilize lyophobic sols., , Water glass, , 19., , 10 mL AuSol, 1 mL of 10% NaCl, , 20., , Fe(OH)3 Sol is (+) vely charged, , 1, Coagulation value, , Coagulation power, , 52, 0.093, , 560, , So valency (–)ve charge will be coagulating, power, PO43–, 21., , Blue colour of sky is due to scattering of light., , 22., , Smoke precipitator works on the principle of, neutralization of charge on colloids., , Brownian movement is more pronounced for, smaller particle than bigger particle., , 23., , Because collidal sol will have higher surface area., , 24., , Vander walls's force, , 25., , Activated charcoal is prepared by heated charcoal, with steam., , 26., , cmc, , Associated colloids lowers surface tension but, increases viscosity of H2O, , 27., , Silica gel adsorbs moisture., , Below CMC salts behaves as strong electrolyte., , 28., , Mo is promoter, , will be valency of (–)ve charge, , coagulation value, , 12., , O, , 18., , coagulation power but, , 11., , x, = KP1/n, m, , x, = 0.6, m, , AlCl3, NaCl, 8., , TC, rate of adsorption., , taking log on both side., , x, = 2 × (0.3), m, , 7., , Soaps are emulsifier for oils & grease, which is, absorbed on hydrophobic centres of soap, micelles, , SO2 > CO2 > H2., , So; k = 100.30 = 2, , 6., , mass of lyophilicsol mg, Gold no = 10 × volume of lyophobicsol mL, = 10 × 0.00015 × 1000 / 10, , n=1, log, , [AgI]Ag+; NO3, , AgNO3 + KI, , A4 > A3 > A2 > A1, 2., , [AgI] I– ; K+, , AgNO3 + KI, , Will be activation energy will be rate., , 1, molecular mass, , Your Target is to secure Good Rank in Pre-Medical 2021, , 29

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TARGET : PRE-MEDICAL 2021, 29., , Tyndall effect and less colligative properties, are shown by colloidal solution., , 30., , Fact basis, , 31., , Fact basis, electrodialysis., , 32., , Colloidal sol is [AgI] Ag+, [AgI]Ag+ + I–, , 2AgI, , +, , 2[AgI]Ag + SO42–, 3[AgI] Ag+ + PO43–, , 2AgI + Ag2SO4, Ag3PO4 + 3AgI, +, , thus 1 mol [AgI]Ag requires -, , 34., , Total surface area to be covered = 25× 103 m, 2r for NH3 = 0.3 × 10–9 nm = 0.3 × 10–9 × 102, cm, = 0.3 × 10–7 cm, r = 1.5 × 10–8 cm, Surface area of 1 molecule = r2, = 3.14 × (1.5 × 10–8)2 = 7.065 × 10–16 cm2, No. of NH3 molecules adsorbed, =, , 1 mol I– : 1/2 mol SO42– : 1/3 mol PO43–, , 33., , 35., , =, , 1, , :, , 1/2, , : 1/3, , =, , 6, , :, , 3, , :2, , 25 10 3, 7.065 10, , 20, , 3.539 10 23, , Moles of NH3 adsorbed, =, , The micelle formation takes place only above a, particular temperature called as Kraft temperature, (Tk)., , PHYSICAL CHEMISTRY, , 3.539 10 23, 6.023 10 23, , 0.5875, , Now using PV = nRT, , 0.05875 0.0821 273, 1, , Milli mole of NaCl in 5mL, , V, , of 1 M NaCl = 5 × 1 = 5, , V = 13.167 litre, , NaCl required by 100 mL, of As2S3 sol = 5 millimole, NaCl required by 1 L of sol =, , 50 1000, 100, , = 50 millimole, , 30, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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INORGANIC CHEMISTRY, , Race, No., , TOPIC NAME CONTENTS, , Page, No., , 01, , PERIODIC TABLE, , 1, , 02, , CHEMICAL BONDING, , 8, , 03, , COORDINATION COMPOUNDS &, , 16, , d-BLOCK COMPOUNDS, 04, , p-BLOCK ELEMENT, , 27, , 05, , s-BLOCK ELEMENTS, , 33, , 06, , METALLURGY, , 35

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , PERIODIC TABLE, 1., , 2., , 3., , Correct order of ionic Radii is :(1) Yb+3 < Pm+3 < La+3 < Ce+3, (2) Ce+3 < Yb+3 < Pm+3 < La+3, (3) Yb+3 < Pm+3 < Ce+3 < La+3, (4) Pm+3 < La+3 < Ce+3 < Yb+3, If P.T would have contained 10 periods,, maximum elements in that P.T. would be :(1) 72, (2) 190, (3) 144, (4) 290, Which of the following statement is not correct, , 7., , 8., , 23, A, B, C, , 4., , 5., , 6., , E, , (1) Atomic no. of A, B, C are 40,57, 105 resp., (2) Group no of A, B, C are IV B, III B and, V B respectively, (3) Period no of A, B, C are, 4th, 5th and 6th resp., (4) C is a radioactive element, If an element can have four values of spin, quantum numbers and rest of the quantum no., are same, which of the following statement, would be incorrect :(1) Be would have been in the first period of, P.T., (2) The total no of elements in 2nd period would, have been 12, (3) There would have been 36 elements in 4th, period, (4) Number of periods would have been less, than the no. of periods present in the, modern P.T., Which two elements are in same period as well, as same group of modern periodic table ?, (1) Z = 23, Z = 31, (2) Z = 65, Z = 66, (3) Z = 52, Z = 87, (4) Z = 58, Z = 46, Incorrect statement for radius of 3d series metal/ions:, (1) Metallic radius of Mn is higher than that of, Cr and Fe, (2) I.EII of Mn is greater then CV, (3) Fe, Co, Ni have almost same atomic radius, (4) Irregular trend of atomic radius on moving, from Sc to Zn, , 9., , 10., , 11., , 12., , 13., , 14., , Which of the following statement is not correct, (1) Nobel gases have a different number of, outermost electrons than their group, number, (2) In the sixth period the orbitals being filled, are 6s, 4f, 5d, 6p, (3) The second transition series contains the, elements from Y to Cd., (4) O–2 has the same no. of e–s in its outermost, as well as penultimate shell, Which of the following statement is not correct, (1) Tc and Pm are not found in nature, (2) Element having ns2 np5 configuration are, placed in the column before, the extreme, right in the P.T., (3) Most of the man made element occurs in, the actinoid series, (4) The 3d - transition series contains elements, having atomic number from 21 to 29, Which of the following statement is not correct, (1) In the transition elements the incoming e–, occupy (n–1)d subshell in preference to np., (2) Elements having atomic number 57 to 71, belong to same group, (3) Lanthanum is the first element of Lanthanoids, (4) Actinium violates the Aufbau's principle, Total number of elements of 6th period which, have one or more than one 4d electrons :(1) 10, (2) 16, (3) 32, (4) Zero, Suppose an orbital may accomodate 3 electrons, then the number of elements in IV period., (1) 18, (2) 27, (3) 12, (4) 45, Which of the following is not correctly matched, (1) [Xe] 4f14 5d10 6s2, Transition element, (2) [Rn] 5f14 6d1 7s2 Inner transition element, (3) [Xe] 4f14 5d10 6s2 6p6 7s2, Representative, element, 14, 2, 2, (4) [Xe] 4f 5d 6s, d-block element, An element whose IUPAC name is ununtrium, (Uut) belongs to :(1) s-block, (2) p-block, (3) d-block, (4) ƒ-block, Which of the following facts are not, explainable by lanthanoid contraction, (1) I.E. of Ag < Au, (2) I.E.I of Hg > Cd, (3) Size of Hf Zr, (4) Size of Y < La, , Your Target is to secure Good Rank in Pre-Medical 2021, , 1

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TARGET : PRE-MEDICAL 2021, 15., , Which of the following property gradually, increase from C to F ?, , 19., , (1) I. P, (2) EA, (3) Shielding Constant, (4) All of these, 16., , Which of the following statement is not correct :(1) The first ionisation energies (in kJ mol–1), of carbon, silicon, germanium, tin and lead, are 1086, 786, 761, 708 and 715, respectively., , 20., , (2) Down the group, electronegativity decreases, regularly from B to Tl in boron family, (3) Among oxides of the elements of carbon, family, CO is neutral, GeO2 is acidic and, SnO is amphoteric., (4) The 4f-and 5f-inner transition elements are, placed separately at the bottom of the, periodic table to maintain its structure., 17., , S el ect th e corr ect st at em en ts o f th e, following:(a) Effective nuclear charge for nitrogen is, 3.90, , 21., , 22., , 23., , (b) IP of Ne is more than Na+, (c) Order of electronegativity- sp > sp 2 > sp3, (d) Order of acidic character- NH3 < PH3 <AsH3, (1) a, b, d, , (2) b,c, , (3) a, c, d, , (4) a, b, c, d, , 18., , 25., , On the basis of given part of periodic table,, incorrect statement is :, , 26., , Which of the following statement is not correct ?, (1) EN of nitrogen on pauling scale is 3.0 in, all nitrogen compounds, (2) The first I.E. for two isotopes of the same, element has to be same, (3) Removal of electron from orbitals bearing, higher n value is easier. than from orbital, having lower n value., (4) the size of isoelectric species is affected by, nuclear charge (z), Which statement is/are incorrect ?, (1) In alkali metals in a group, from top to, bottom increase in size is maximum from, Na to K, (2)Addition of e– in P atom will be exothermic, (3) IP of F is greater than its EA value, O (g) + S – (g) is, (4) Reaction O – (g) + S (g), endothermic, If Zeff of sodium is 'x' then Zeff of calcium is :(1) x + 0.35, (2) x + 0.65, (3) x – 0.35, (4) x – 0.65, According to Slater's rule, the set of elements, that show incorrect order of Zeff are :(1) Al > Mg, (2) Na < Al, (3) K > Na, (4) Sc < Ti, Lanthanoid contraction will not have any, influence when we compare size of :(1) Zr & Hf, (2) Y & La, (3) Mo & W, (4) Tc & Re, In which one of the following pairs the, radius of the second species is greater than, that of the first ?, (1) O–2 , N–3, (2) Na, Mg, (3) Al, Be, (4) Li+, Be+2, Pair of smallest and largest species of radii, among Mg, Al, Mg+2, Al+3 is :(1) Mg+2 , Mg, , (2) Al+3, Mg, , (3) Mg+2, Al, , (4) Al+3 , Al, , The correct order of increasing order of size is, , (1) A is an alkaline earth metal, , (1) S < O < Se < C, , (2) O < C < S < Se, , (2) Atomic number of B is 103 which belongs, to III B group, , (3) O < Se < S < C, , (4) C < O < S < Se, , (3) Atomic number, group no. and period, number of D are 72 IVB and 6 th, respectively, (4) C is a transuranic element, 2, , 24., , INORGANIC CHEMISTRY, , 27., , The difference between atomic radii is, maximum in which one of the following pairs., (1) Rb, Cs, , (2) Na, Ca, , (3) Li, Na, , (4) Na, K, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 28., , 29., , 30., 31., , 32., , 33., , 34., , 35., , 36., , Correct order of Ionic radii :(1) Ti4+ < Mn7+, (2) Cr+6 > Cr3+, (3) K+ > Cl–, (4) P3+ > P+5, Which two are closest to one another in size ?, (1) Li+ and Na+, (2) Be+2 and Mg+2, +2, +, (3) Be and Li, (4) Li+ and Mg+2, Which of the following ion has highest ionic radius, (1) Sc+3, (2) La+3, (3) Ce+3 (4) Lu+3, Total number of elements of 5th period which, have one or more than one 5d electrons :(1) 10, (2) 16, (3) 30, (4) Zero, Total number of d electrons present in an, element with atomic number 78 is :(1) 8, (2) 58, (3) 29, (4) 38, How many g subshells will be required in case, element Uuo is discovered :(1) 1, (2) 2, (3) 3, (4) None, In which pair the first atom or ion is not larger, than the second :(1) N, F, (2) Cl–, Cl, (3) O, S, (4) Fe2+, Fe3+, Incorrect order of radius is :(1) Sr+2 < Rb+ < Br– < Se–2, (2) Ni > Cu > Zn, (3) Co > Co+2 > Co+3 > Co+4, (4) Ba+2 < Cs+ < Se–2 < As–3, Which of the following diagrams shows correct, change in the polarity of bond ?, O–H, , (1), , Decrease, , Decrease, Decrease, , S–H, O–H, , (2), , Decrease, , Increase, , O–H, , (3), , Increase, , Decrease, Decrease, , S–H, O–H, , (4), E, , Decrease, , Increase, , S–H, , 38., , 39., , 40., , 41., , Cl–H, Increase, , 42., , F–H, , 43., , Cl–H, Decrease, , Decrease, , S–H, , 37., , 44., , F–H, Cl–H, Increase, , 45., , F–H, Cl–H, Increase, , Decrease, , F–H, , INORGANIC CHEMISTRY, , Correct order of size is :(1) F > C > Br > Ge (2) Ge > C > F > Br, (3) Ge > Br > C > F, (4) Ge > C > Br > F, Which one of the following statements is, incorrect ?, (1) Greater the nuclear charge, greater is the, electron gain enthalpy, (2) Nitrogen has almost zero electron affinity, (3) Electron gain enthalpy decreases from, fluorine to iodine in the group, (4) Chlorine has highest electron gain enthalpy, Which of the following properties among, halogens decrease(s) from fluorine to iodine ?, (1) Electronegativity (2) Bond energy, (3) Ionisation energy (4) (1) & (3) both, Which of the following statements is incorrect ?, (1) The second ionization energy of sulphur is, greater than that of chlorine, (2) The third ionization energy of phosphorus, is greater than that of magnesium, (3) The first ionization energy of aluminium is, less than as that of gallium, (4) The second ionization energy for boron is, greater than that of carbon, The correct values of ionization enthalpies (in, kJ mol–1) of Si, P, Cl and S respectively are :(1) 786, 1012, 999, 1256, (2) 1012, 786, 999, 1256, (3) 786, 1012, 1256, 999, (4) 786, 999, 1012, 1256, Correct order of first ionisation energy is :(1) C > N > O, (2) Mg > Al > P, (3) Li < Be < N, (4) T > B > In, The second ionisation energy is maximum for :, (1) Boron, (2) Beryllium, (3) Magnesium, (4) Aluminium, From the ground state, electronic configuration, of the elements given below, pick up the one, with highest value of second ionization energy :, (1) 1s2 2s2 2p6 3s2, (2) 1s2 2s2 2p6 3s1, (3) 1s2 2s2 2p6, (4) 1s2 2s2 2p5, An element has successive ionization, enthalpies as 940 (first), 2080, 3090, 4140,, 7030, 7870, 16000 and 19500 kJ mol –1 . To, which group of the periodic table does this, element belong ?, (1) 14, (2) 15, (3) 16, (4) 17, , Your Target is to secure Good Rank in Pre-Medical 2021, , 3

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TARGET : PRE-MEDICAL 2021, 46., , 52., , Consider the following changes :, M(s), , M(g), , ....... (1), , M(s), , M2+(g)+ 2e, , ....... (2), , M(g), M+(g), M(g), , M, , +, (g), , +e, , ....... (3), , M+2(g) + e, , ....... (4), , M, , 2+, (g), , + 2e, , ....... (5), , The second ionization energy of M(g) could be, calculated from the energy values associated, with :, , 47., , 53., , (1) 1 + 3 + 4, , (2) 2 – 1 + 3, , (3) 1 + 5 – 3, , (4) 5 – 3, , 54., , Read the following statements:, (I) Atomic size of following pair are almost same, 55., , Fe, Co; Al,Ga ; Zr, Hf, (II) E.A. order of Li, Be,B,C,N,O is, (III) Ionisation energy of, , (2) X Joules is sufficient to ionise 1 mole of, gaseous F into F +, , Al < Ga & Zr < Hf, (IV) Ionic radius, , (3) X Joules is sufficient to ionise 1 mole of, gaseous F into F + as well as 1 mole of, gaseous Cl into Cl+, , O–2 < F– < Na+ < Mg+2, Select the correct statements(s), (1) I, III, IV, , (2) I, II, III, , (3) II, III, IV, , (4) All the four, , Passage (Q. No. 48 to 53) :, Ionization energies of five elements in kcal/mol, are given below :, P, Q, R, S, T, 48., 49., , 4, , III, , 300, 99, 118, 176, 497, , 549, 734, 1091, 347, 947, , 920, 1100, 1652, 1848, 1500, , The first ionisation enthalpies of four, consecutive elements present in the second, period of the periodic table are 8.3, 11.3, 14.5, and 13.6 eV respectively. Which one of the, following is the first ionisation enthalpy of, nitrogen ?, (1) 13.6 (2) 14.5 (3) 11.3 (4) 8.3, , 57., , The Incorrect statements(s) among the, following is/are :(1) The first ionisation energy of calcium is, more than first ionisation energy of Gallium, , (2) T, , (3) R, , (2) The second ionisation energy of copper is, greater than that of potassium, , (4) S, , (2) Q, , (3) T, , (3) The third ionisation energy of Mg is greater, than the third ionisation energy of Al, , (4) S, , The element having most stable oxidation state, +2 is ?, (1) P, , 51., , II, , 56., , The element form stable unipositive ion?, (1) P, , 50., , I, , (4) Less than 1 mole of gaseous F or Cl atom, will be ionised to F + or Cl+, , Which element is a noble gas ?, (1) P, , (2) Q, , (3) R, , If Q reacts with fluorine and oxygen, the, molecular formula of fluoride and oxide will, be respectively :(1) QF 3, Q2O 3, (2) QF, Q2 O, (3) QF 2 , QO, (4) None of these, Which of the following pair represents, elements of same group ?, (1) Q, R, (2) P, Q, (3) P, S, (4) Q, S, The first ionisation energy of first atom is, greater than that of second atom, whereas, reverse order is true for their second ionisation, energy. Which set of elements is not in, accordance to above statement ?, (1) C, B (2) P, S, (3) B, Be (4) Mg, Na, When one mole of F atoms are ionised to F –,, the energy released is X Joules. Then :(1) X Joules is sufficient to ionise 1 mole of, gaseous Cl into Cl+, , Be < N < B < Li < C < O, , Atom, , INORGANIC CHEMISTRY, , (4) S, , (4) The IE1 of Mg+ is less than the IE1 of Na+, 58., , Find the incorrect second ionisation energy, order from following option :-, , Which is non-metal (excluding noble gas) ?, , (1) Al > Mg, , (2) Te > Sb, , (1) P, , (3) Fe > Fe+, , (4) In > Sr, , (2) Q, , (3) S, , (4) T, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 59., , 60., , 61., , 62., , 63., , Element, , I.E.I, , I.E.II, , H eg, , P, , 520, , 7300, , 60, , Q, R, , 419 1051, 1681 3374, , 48, 328, , S, , 1008 1846, , 295, , T, , 2372 5251, , 48, , 65., , 66., , Which of the following statement is not correct, for above elements ?, (1) P is the metal which form halide of the, formula MX, (2) S is the less reactive non metal, (3) T is the least reactive element, (4) Q is a non-metal and does not form binary, halide of the formula MX2, If atomic number of an inert gas is Z then an, element with which of the following atomic, number will has highest I.E., (1) Z – 2, (2) Z – 1, (3) Z + 1, (4) Z + 2, If I.E. of Na, Mg and Si are respectively 496,, 737 and 786 kJ mol– The I.E. of Al in KJ mol–, is :(1) 575, (2) 760, (3) 390, (4) 1120, Correct order of metallic character is :(1) P < Si < Be < Mg < Na, (2) Si < P < Be < Na < Mg, (3) P < Si < Mg < Be < Na, (4) Si < P < Mg < Na < Be, Which one of the following statements is, incorrect in relation to ionization enthalpy?, , 67., , 68., , (3) End of valence electrons is marked by a big, jump in ionization enthalpy., (4) Removal of electron from orbitals bearing, lower n value is easier than from orbital, having higher n value., 64., , IP1, IP2, IP3 , IP4 and IP5 for an element is 7.1,, 14.3, 34.5, 46.8 and 162.2 eV respectively then, element is :(1) Na, , E, , (2) Si, , (3) F, , (4) Ca, , Which process requires maximum energy :(1) Na(g), Na+(g) + e–, (2) Al+3 (g), Al+4 (g) + e–, (3) Al+2 (g), Al+3 (g) + e–, (4) Na+(g), Na+2 (g) + e–, Amongst the following the incorrect order is :(1) IE1(Al) < IE1 (Mg) (2) IE1 (Na) < IE1(Mg), (3) IE2(Mg) > IE2(Na) (4) IE3(Mg) > IE3(Al), Which of the following statement is correct ?, (1) Number of e – in (n–1) th shell of f block, element are (0–1), (2) 6th period contains 10 elements which have, one or more 6d electrons, (3) In the 8th period, subshell being will be 8s,, 5g, 6f, 7d, 8p, (4) 1 and 3 both, The increasing order of electron affinity of the, electronic configurations of element is :(I) 1s 2 2s2 2p6 3s2 3p5 (II) 1s 2 2s2 2p3, , 69., , (III) 1s 2 2s2 2p5, , (IV) 1s 2 2s2 2p6 3s1, , (1) II < IV < III < I, , (2) I < II < III < IV, , (3) I < III < II < IV, , (4) IV < III < II < I, , The element having very high ionization, enthalpy but zero electron affinity is :(1) H, , 70., , (2) F, , (3) He, , (4) Be, , Which of the following statement is correct, regarding following process ?, (i) Cl, (iii) Cl, , E.A., , I.E., , Cl–, Cl+, , (ii) Cl–, (iv) Cl+, , I.E., I.E., , Cl, Cl2+, , (1) |I.E. of process (ii)|=| E.A. of process (i)|, , (1) Ionization enthalpy increases for each, successive electron., (2) The greatest increase in ionization enthalpy, is experienced on removal of electron from, core noble gas configuration., , INORGANIC CHEMISTRY, , (2) |I.E. of process (iii)|=| I.E. of process (ii)|, (3) |I.E. of process (iv)|=| E.A. of process (i)|, (4) |I.E. of process (iv)|=| I.E. of process (iii)|, 71., , Which of the following statements is/are, correct ?, (1) Van der Waals' radius of iodine is more than, its covalent radius., (2) All isoelectronic ions of corresponding, elements belong to the same period of the, periodic table, (3) The electron affinity of fluorine is greater, than that of chlorine., (4) IE2 of N-atom is higher than that of O-atom,, while IE1 of O-atom is higher than that of, N-atom, , Your Target is to secure Good Rank in Pre-Medical 2021, , 5

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TARGET : PRE-MEDICAL 2021, 72., , 73., , 74., , 75., , 76., , 77., 78., , 79., , 80., , 81., , 82., , 6, , Which one is least basic ?, (1) Tb(OH)3, (2) Yb(OH)3, (3) Gd(OH)3, (4) Eu(OH)3, Highest electron affinity observe in :(1) 2s 22p 5, (2) 2s 22p 4, (3) 2s 2 2p 3, (4) 2s 22p 1, Electron affinity of :, (1) carbon is greater than oxygen, (2) sulphur is lesser than oxygen, (3) iodine is higher than bromine, (4) bromine is lesser than chlorine, Which of the following EA order is not correct, (1) N < O < S, (2) Cl > O > N > C, (3) O < S < F < Cl, (4) B < C < Si < S, The value of IInd egH of O & S respectively in, KJ/mole :(1) +580, +780, (2) +780, +580, (3) +580, –780, (4) –780, –580, I.P is maximum for :(1) Li, (2) Ne, (3) Be, (4) B, Select the incorrect statements :, (1) Size of H– is larger than F –, (2) Rb is more electropositive compared to Ca, (3) Na+ is more electronegative than the Na, (4) Cl– is more electronegative than that of F, Which is/are correct about electronegativity, order of the following elements ?, (1) P > Si (2) C > N (3) C > Br (4) Sr > Ca, Select the incorrect statement(s) :, (1) In general more the ionisation energy more, will be electronegativity, (2) Electronegativity increases means metallic, character increases, (3) In general lower will be the ionisation, energy, higher will be reducing property, (4) Cl has higher electron affinity than F, Pauling's electronegativity scale is based on, experimental value of:(1) atomic radii, (2) bond energies, (3) bond lengths, (4) electron affinity, An atom with high electronegativity generally has:(1) tendency to form +ve ions, (2) high ionisation potential, (3) large atomic size, (4) low electron affinity, , 83., , 84., , 85., , 86., , 87., , 88., , 89., 90., , 91., , INORGANIC CHEMISTRY, , Which order is correct ?, (1) N > O (IP2 ), (2) O > N (IP1 ), (3) Zn > Mn (IP1 ), (4) Al > B (IP1 ), th, p block elements of 6 period are represented, as :(1) [Xe] 4f14 5d10 6p 1–6, (2) [Xe] 5f14 6d10 6p 1–6, (3) [Kr] 5f14 5d 10 6p 1–6, (4) [Xe] 4f0 5d10 6p 1–6, Correct atomic size is :(1) Li > I > F < Cl < Br, (2) I > Li > F < Cl > Br, (3) I > Br > Cl > F > Li, (4) Li > F < I < Br, Which of the following valence electron, experiences maximum effective nuclear charge?, (1) 4s1, (2) 4p 1, (3) 3d 1, (4) 2p 3, Which of following ions has lowest magnetic, moment ?, (1) Cu+2, (2) Ni+2, (3) Co+3, (4) Fe+2, Incorrect order of IP is :(1) Cu + > Zn+, (2) Cu < Zn, (3) Tl < Al, (4) Pd > Ag, Lowest Ist IP is of :(1) Pb, (2) Si, (3) Sn, (4) C, Which of following radius order is not correct?, (1) Ti < Zr Hf, (2) Sc < Y La, (3) B < Al Ga < In Tl, (4) O < N < S < P, Correct order of EA is :(1) Cl > O > N > C, (2) Cl > O > C > N, (3) Cl > N > C > O, (4) Cl > C > O > N, , MATCH THE COLUMN TYPE QUESTIONS, 92., , 93., , Column I, , Column II, , (A), , Z = 102, , (P), , s-block, , (B), , Z = 120, , (Q), , d-block, , (C), , Z = 107, , (R), , f-block, , (D), , Z = 82, , (S), , p-block, , Column I, (A) Natural transuranic element, (B) Rare earth metals, (C) Diagonally related elements, (D) Typical elements, , Your Target is to secure Good Rank in Pre-Medical 2021, , Column II, (P) Na, Mg, (Q) Be, Al, (R) Ce, Pr, (S) Np,Pu, E

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TARGET : PRE-MEDICAL 2021, 94., , Column I, , 96., , Column II, 2nd Pd, 2, , (B) [Rn] 6d 7s, , 2, , (Q) d-block, II B,, 4th Pd., , (C) 1s2 2s2 2p6 3s 2 (R) f-block III B,, 3p 6 3d 10 4s 2, , 7th Pd, , (D) 1s 2 2s 1 2p 1, , (S) p-block VI A,, 3rd Pd, , 95., , Column-I, (Characteristic involve, in the given process, of Column-II), (A) Energy released, (B) Energy absorbed, (C) Inert gas configuration, is achieved, (D) Half filled configuration, is achieved, , Column-I, , Column-II, , (A) Electron affinity (P) Depends upon, effective nuclear, charge, (B) Ionisation, (Q) Depends upon, potential, shielding, constant, (C) Electronegativity (R) Depends upon, half filled and, fully filled, electronic, configuration, (S) Can be estimated, from bond, energy data, , (A) 1s2 2s2 2p6 3s 1 (P) s-block, II A,, 3p 3 3d 2, , INORGANIC CHEMISTRY, , Column-II, (Process, described), (P) S, (Q) O–, (R) Sr, , S–, O2–, Sr2+, , (S) N–, (T) Ge, , N, Ge–, , ANSWER KEY, , E, , Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , A ns, , 3, , 4, , 3, , 2, , 2, , 2, , 4, , 4, , 3, , 3, , Que., , 11, , 12, , 13, , 14, , 15, , 16, , 17, , 18, , 19, , 20, , A ns, , 2, , 1, , 2, , 4, , 3, , 2, , 3, , 2, , 1, , 4, , Que., , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , A ns, , 2, , 3, , 2, , 1, , 2, , 2, , 4, , 4, , 4, , 2, , Que., , 31, , 32, , 33, , 34, , 35, , 36, , 37, , 38, , 39, , 40, , A ns, , 4, , 3, , 4, , 3, , 2, , 4, , 3, , 3, , 4, , 2, , Que., , 41, , 42, , 43, , 44, , 45, , 46, , 47, , 48, , 49, , 50, , A ns, , 3, , 3, , 1, , 2, , 3, , 4, , 2, , 2, , 2, , 4, , Que., , 51, , 52, , 53, , 54, , 55, , 56, , 57, , 58, , 59, , 60, , A ns ., , 1, , 2, , 1, , 3, , 4, , 2, , 2, , 3, , 4, , 2, , Que., , 61, , 62, , 63, , 64, , 65, , 66, , 67, , 68, , 69, , 70, , A ns ., , 1, , 1, , 4, , 2, , 2, , 3, , 3, , 1, , 3, , 1, , Que., , 71, , 72, , 73, , 74, , 75, , 76, , 77, , 78, , 79, , 80, , A ns ., , 1, , 2, , 1, , 4, , 2, , 1, , 1, , 4, , 1, , 2, , Que., , 84, , 85, , 86, , 87, , 88, , 89, , 90, , 1, , 1, , 4, , 1, , 3, , 3, , 81, , 82, , 83, , A ns ., , 2, , 2, , 1, , Que., , 91, , 92, , 93, , 94, , A ns ., , 2, , A -R; B -P; C-Q; D -S, , A -S ; B -R; C-Q; D -P, , A -S ; B -R; C-Q; D -P, , 2, , Que., , 95, , 96, , A ns ., , A -P,S,T; B -Q,R; C-Q,R; D -S,T, , A -P,Q,R; B -P,Q,R; C-P,Q,S, , Your Target is to secure Good Rank in Pre-Medical 2021, , 7

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , CHEMICAL BONDING, 1., , Which of the following is/are correct :-, , 8., , (1) Carbon-carbon bond length in CaC2 will be, more than that in CH2 CCH2, (2) O–O bond length in KO2 is more than that, in Na2 O 2, , 9., , (3) O–O bond length in BaO2 will be more than, that in KO2, , When iodine is dissolved in aqueous potassium, iodide, the shape of the species formed is :-, , 3., , (1) Linear, , (2) Angular, , (3) Triangular, , (4) See-Saw, , 4., , (2) O2,O22, , (3) O2 ,O22, , (4) O2 ,O2, , Two hybrid orbitals have a bond angle of 120º., The percentage of p-character in the hybrid, orbital is nearly:(1) 25%, , 6., , (2) 33%, , (3) 50%, , 10., , 11., , 12., , 8, , (1) XeO4, SF 4, , (2) XeO3, BrF 3, , (3) H2 O, SnCl2, , (4) I3 , I 3, , Which of the following order of Bond strength, is not correct ?, (1) Diamond < Graphite (C–C bond), (2) SO2 > SO3–2 > SO4–2 (S–O bond), (3) CO3–2 < HCO2– (C–O bond), (4) O2– < O2 < O2+ (O–O bond), A molecule XY2 contains two , two bond, and one lone pair of electron in the valence, shell of X. The arrangement of lone pair as well, as bond pair is :, (1) Square pyramidal, (2) Linear, (3) Trigonal planar, (4) Unpredictable, The molecule which contain bonds, bonds, and lone pairs in 1 : 1 : 1 ratio :(2) C6H 6 (Benzene), (3) C(CN) 4 (Tetracyano methane), (4) C3O2 (Carbon suboxide), , 13., , In CO 2 , SO 2 , SiO 2 each central atom is, covalently bonded with :(1) 2,2,4 oxygen atoms respectively, (2) 2,2,2 oxygen atoms respectively, (3) 2,4,4 oxygen atoms respectively, (4) 4,4,4 oxygen atoms respectively, , 14., , The incorrect order of bond angle :(1) CO2 CO23 CF2 Cl2, (2) NO2 NO3 NO2, (3) XeF 2 > XeO3 > XeO4, (4) PH3 > AsH3 > SbH3, , In ICl 4 , shape is square planar. The number, , 7., , Which of the following can not be explained, on the basis of polarisation :-, , (1) C2 N2 (Cyanogen), , (4) 66%, , of bond pair – lone pair repulsion at 90° are:(1) 6, (2) 4, (3) 12, (4) 8, Which of the folowing set of molecules have, same shape but different hybridisation ?, , (4) All of these, , (4) Melting point of AlCl3 is much less than that, of NaCl., , (2) He2 is not stable but He2 is expected to exist, , 5., , (3) KNO3, , (3) BaCO3 is less soluble than MgCO3, , Which of the following statements is not correct, from the point of view of molecular orbital, theory ?, (1) Be2 is not a stable molecule, , (3) Bond strength of N2 is maximum amongst, the homonuclear diatomic molecules, (4) The order of energies of molecular orbitals, in F 2 molecule is 2 px, 2 py, 2 pz, , (2) NaNO3, , (2) BeCO3 is thermally less stable than BaCO3, , Which of the following pairs of species would, you expect to have largest difference in spin, only magnetic moment ?, (1) O2 ,O2, , (1) LiNO3, , (1) Ag2 S is much less soluble than Ag2 O, , (4) N–O bond length in NO gaseous molecule, is equal to bond length in NOCl gaseous, molecule, 2., , Which of the following compound gives, paramagnetic gas on heating :-, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 15., , Which of following statement is incorrect :-, , 20., , (1) Boiling point of H2O2 is greater than that, of H2O., (2) Ethylene glycol is less viscous than glycerol., , (1) PF5, , (2) PCl5, , (3) o–nitrophenol can be separated from its, meta and para isomer, using its order of, volatile property., , (3) PBr5, , (4) None of these, , Which of the following combination of orbitals, is correct ?, (1), , +, , –, , +, , +, , 21., , (3), , +, , –, , (2) H2 O > H2 S > H2Se, (3) BCl3 > AlCl3 > GaCl3, (4) NO2 + > NO2 > NO2 –, 22., , +, , –, , +, , – +, , –, , 23., , 24., , +, , +, , Which of the following statements is not correct, regarding bonding molecular orbital ?, , 25., , (2) Bonding molecular orbitals have low, electron density between the two nucleus, (3) Every electron in bonding molecular orbitals, contributes to the attraction between atoms, , (2) Basic strength, , (3) Viscosity, , (4) Oxidation state, , In which of the following compound all the, bond angles are equal :(2) CCl4, , (3) CHCl3 (4) XeF 6, , Correct order of Bond angle is, , (3) NH4 + > NH3 > NH2 –, (4) OF2 > OCl2 > OBr2, 26., , Which of the following do not exhibit, resonance., (1) CO3 –2, , (2) ClO3 –, , (3) SiO2, , (4) SO3 –2, , 27., , The incorrect statement regarding chloral, hydrate CCl3CH(OH)2 is :(1) It exhibits intramolecular hydrogen, bonding, (2) It has 9 lone pair and 9 bond pair, (3) It is stable inspite of coexistence of two-OH, groups on a carbon atom, (4) Compound is non-planar and polar, , 28., , Which of the following statements is incorrect?, , Which of the following statement is correct:-, , (1) The bond angle decreases, (2) The bond strength increases, , E, , (1)Acidic nature, , (2) BeCl2 > BF3 < CF4, , As the %s- character of a hybrid orbital, decreases, , 19., , (4) N2+1, , (1) NO2 + < NO2 < NO2 –, , (4) They are formed when the lobes of the, combining atomic orbitals have same sign, , (3) The bond length decreases, , (3) N2–1, , 1, 2, , Order H3PO4>H2SO4>HNO3> HCl is correct for :-, , (1) SF 4, , (1) Bonding molecular orbitals possess less, energy than the atomic orbitals from which, they are formed., , 18., , In which of the following molecule 2 and, bond is present ?, (1) O2–1, (2) O2+, , +, , +, , +, , (4), , +, , Incorrect order of bond angle is :(1) NH3 > PH3 > AsH3, , –, , (2), , 17., , Which of the following does not contain PX 4, type cation in solid phase ?, (X=halogen atom), , (4) In ice, each 'O' atom is tetrahedrally, arranged by four H-atom which are all in, the equal distance., 16., , INORGANIC CHEMISTRY, , (4) Size of orbital decreases, , (1) C F 3 has T-shape, , Which of the following molecule has two lone, pairs and bond angle < 109°28' :(1) SF 2, (2) KrF 4, (3) ICl 4, (4) All of these, , (2) In SF4, F-S-F equatorial bond angle is less, than 120°, (3) In [IC 4]– , C -I-C bond angle is 109°, (4) Shape of I3 – molecule is linear, , Your Target is to secure Good Rank in Pre-Medical 2021, , 9

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TARGET : PRE-MEDICAL 2021, 29., , 38., , (2) (CH3)3 B is a planar molecule, , Which of the following molecule exhibit, P –P bonding ?, (2) NO3–1, (1) CO3–2, , (3) In NH4Cl, ‘N’ atom is in sp3d Hybridisation, , (3) SiO2, , Identify the correct option :(1) NO3– > NH3 > NH2– (order of bond angle), , (4) BF3 < BCl3 < BBr3 < BI3 (Order of bond angle), 30., , 31., , Which of the following is not correctly match, between given species and type of overlapping ?, (1) XeO3 : Three (d –p ) bonds, (2) H2SO 4: Two (d –p ) bonds, (3) SO3 : Three (d –p ) bonds, (4) HClO4 : Three (d –p ) bonds, In which of the following molecules no. of, lonepairs and bond pairs on central atom are, not equal :(1) H2 O, , 32., , 34., , 36., , 10, , (4) SCl2, , (2) 3, , (3) 6, , 40., , 41., , (2) NH4+ & PH4 +, , (3) PCl6– & [SiF6 ]–2, , (4) BCl4– & ICl4 –, , (3) PCl5, , (4) SiF4, , (2) ICl2+ & SF 4, , (3) XeF 2 & I3 –, , (4) AsF4 – & SCl4, , (3) SeCl4, , 42., , 43., , (3) TeCl 4, ICl 4--, , (4) BrO3F, XeOF 2, , Which of the following have same geometry -, , In which hybridisation, resulting all orbitals are, NOT equivalent(1) sp3, , (2) sp3 d, , (3) sp3 d 2, , (4) sp2, , Out of CHCl3, CH4 and SF4, the molecule are, not having regular geometry are :(1) CHCl3 only, , 44., , 45., , 46., , (2) CHCl3 & SF 4, , (3) CH4 only, (4) CH 4 & SF4, The correct order of increasing %s-character in the, hybrid orbitals of following molecule/ion is :(I) CO3 2, , (4) AsF 4 –, , Consider the following compounds and select, the incorrect statement from the following :, NH3,PH3,H2S, SO2,SO3,BF3,PCl3,IF7,P4,H2, (1) 3 molecules out of given compounds, involve Sp2 hybridisation, (2) Three molecules are hyprevalent, compounds, (3) Six molecules out of above compounds are, non-planar in structure, (4) Two molecules out of given compounds, involves (d –p ) bonding as well as also, involves (p –p ) bonding., , (2) XeO2F 2 , IO2 F2 --, , (4) COCl2 , SOCl2 , XeOF 2, , Which of the following has different, hybridization than other :(2) XeO3, , (1) XeO2F 2, SiF4, , (3) SF6, PF 6–, IOF 5, , Which of the following set do not have sp3 d, hybridization :(1) PF4 – & BrF 3, , Which of the following statement is not correct ?, (1) PCl 3F2 has zero dipole moment, (2) PH+4 is having tetrahedral geometry with, sp3 hybridisation of central atom., (3) All diatomic molecules with polar bonds, have dipole moment., (4) Four half filled pure orbital of carbon form, same kind of bonds in CH4, Select in which both have sea-saw shape-, , (2) SF4 , XeOF 4, PCl4 +, , In which of the following molecule all bond, length are equal :(2) B2H 6, , (4) (1) & (2) both, , (1) SbF 5 2–, XeF 5 –, IF 5, , (4) 1, , (1)BH4 – & AlH4 –, , (1) I3 –, 37., , (3) O2 F 2, , 39., , In which pair both are not isostructural :-, , (1) SF 4, 35., , (2) I3, , Number of carbon atom present linearly in, C3 O2 :(1) 2, , 33., , INORGANIC CHEMISTRY, , (II) XeF 4, , (III) I 3, , (IV) NCl 3 (V) BeCl2, (1) II < III < IV < I < V, (2) II < IV < III < V < I, (3) III < II < I < V < IV, (4) II < IV < III < I < V, Which of the following will have pyramidal, shape :(1) [ClOF2 ]+, (2) ICl4–, (3) [BrICl]–, (4) All of these, Which of the following is electron deficient, compound :(1) PF 3, (2) CIF 3, (3) AlF 3, (4) BF 3, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 47., , 48., , Maximum number of identical bond length are, present in, (1) SF 6, (2) IF 7, (3) PCl5, (4) SO4–2, Match column-I with column-II and select the, correct answer :Column-I, (Molecules), , 54., , Which of the following molecule has some, dipole moment :OH, (1), , Column-II, (Peoperty), , P IF7, , 1 Planar and polar, , Q SO2, , 2 Non planar and polar, , R SF4, , 3 planar and nonpolar, , S CS2, , 4 Non planar and non, polar, , OCH3, (2), , OH, 55., , 56., , INORGANIC CHEMISTRY, , (3) PF3Cl2, , OCH3, , Which of the following species is non polar, with presence of polar bond and lone pair of, electron on central atom., (1) CO2, , (2) SF 4, , (3) XeF 4, , (4) CF 4, , Which of the following species are hypervalent ?, (I) C O4 –, , 49., , 50., , 51., , 52., , (1) (P), (4) ; (Q), (1) ; (R), (2) ; (S), (3), (2) (P), (4) ; (Q), (2) ; (R), (1) ; (S), (3), (3) (P), (3) ; (Q), (1) ; (R), (2) ; (S), (4), (4) (P), (3) ; (Q), (1) ; (R), (4) ; (S), (2), In which type of molecule, the dipole moment, will be nonzero :(1) AB 2L 2 (2) AB 2L 3 (3) AB 4L 2 (4) AB 4, Which of the following compounds give, paramagnetic gas on decomposition, (i) Pb(NO3 )2, (ii) LiNO3, (iii) NaNO3, (iv) NH4NO 2, (1) I, II, III, (2) II, III, (3) I, II, (4) III, IV, Arrange the following compound in order of, increasing dipole moment :, (I) 1, 3, 5-Trichloro benzene, (II) 1, 2, 4-Trichloro benzene, (III) 1, 2, 3, 4-Tetrachloro benzene, (IV) P-dichloro benzene, (1) I = IV < II < III, (2) IV < I < II < III, (3) IV = I < III < II, (4) IV < II < I < III, Which of the following molecule is planar as, well as polar :, (1) PC 3, (2) SF 4, (3) C F3, , 53., , E, , (4) None of these, , Which of the following compound have number, of p –p bond equal to p –d bond., (1) SO3, (2) SO2, (3) SOCl2, (4) SO2Cl2, , (III) SO, , 57., , (4) All, , (II) BF3, (IV) CO–2, 3, , –2, 4, , (1) I, II, III, , (2) I, III, , (3) III, IV, , (4) I, III, IV, , Bond, , Bond dissociation energy (kJ mole–1), , C-I, , 240, , Element A, , C-II, , 328, , Element B, , C-III, , 276, , Element C, , C-IV, , 485, , Element D, , Elements A, B, C and D, which element has, the smallest atom ?, (1) I, 58., , 59., , (3) II, , (4) IV, , Which have maximum number of lone pair on, central atom :(1) SO2, , (2) SCl2, , (3) XeF 2, , (4) XeO2F 2, , Total no. of vacant orbitals in valence shell of, sulphur when it undergoes formation of SF4:(1) 5, , 60., , (2) III, , (2) 4, , (3) 3, , (4) 2, , Indicate the wrong statement :(1) Generally a sigma bond has free rotation, along the axis, (2) p-orbitals always have only sideway, overlapping, (3) s-orbital never form -bond, (4) There can not be more than one sigma bond, between two atoms, , Your Target is to secure Good Rank in Pre-Medical 2021, , 11

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , 117. PCl5 exist but NCl5 doesnot because :-, , 112. The incorrect order of bond angle :(1) CO2 > CO3–2 > CF2Cl2, , (1) Nitrogen atom is much smaller than P, , (2) NF3 > NH3 > NCl3, , (2) NCl5 is unstable, , (3) NO2+ > NO3– > NO2–, , (3) Nitrogen has no vacant d-orbitals, , (4) PH3 > AsH3 > SbH3, , (4) Nitrogen is highly inert, , 113. Which of the following has been arranged in, order of decreasing bond length ?, (1) P–O > S–O > Cl–O, , 118. The correct order of increasing s-character (in, percentage) in the hybrid orbitals of following, molecules/ions is :-, , (2) P–O > Cl–O > S–O, , (A) CO 3–2, , (3) S–O > Cl–O > P–O, , (1) B < A < C, , (2) A < B < C, , (4) Cl–O > S–O > P–O, , (3) C < A < B, , (4) C < B < A, , 114. Which of the, hypervalent?, , following, , species, , are, , (B) NCl3, , (C) BeCl2, , 119. Among MgCl 2 , RbCl, BeCl 2 and LiCl. The, compounds with highest and lowest % of ionic, characters are :-, , (A) ClO4–, , (B) BF3, , (C) SO4–2, , (D) CO 3–2, , (1) RbCl and BeCl2, , (2) MgCl2 and BeCl2, , (1) A, B, C, , (2) C, D, , (3) BeCl2 and MgCl2, , (4) RbCl and LiCl, , (3) A, C, , (4) A, B, , 115. The correct order of increasing C–O bond, length of CO, CO3–2 and CO2 is :(1) CO3–2 < CO2 < CO, , (2) CO < CO2 < CO3–2, , (3) CO < CO3–2 < CO2, , (4) CO2 < CO3–2 < CO, , 120. Which of the following is correct order of, dipole moment ?, (1) NH3 > NF3, , (2) BF3 > BCl3, , (3) CF4 > CH4, , (4) XeF2 > XeO3F 2, , 116. The species having pyramidal shape is :(1) OSF2, , (2) BrF3, , (3) SiO3–2, , (4) SO3, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 3, , 1, , 2, , 4, , 4, , 4, , 3, , 4, , 3, , 2, , 3, , 4, , 1, , 3, , 4, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans, , 3, , 2, , 1, , 4, , 1, , 3, , 3, , 3, , 2, , 3, , 3, , 2, , 3, , 1, , 3, , Que., , 31, , 32, , 33, , 34, , 35, , 36, , 37, , 38, , 39, , 40, , 41, , 42, , 43, , 44, , 45, , Ans, , 2, , 2, , 4, , 4, , 2, , 2, , 3, , 2, , 4, , 2, , 3, , 2, , 2, , 1, , 1, , Que., , 46, , 47, , 48, , 49, , 50, , 51, , 52, , 53, , 54, , 55, , 56, , 57, , 58, , 59, , 60, , Ans, , 4, , 1, , 1, , 1, , 1, , 1, , 3, , 2, , 4, , 3, , 2, , 4, , 3, , 2, , 2, , Que., , 61, , 62, , 63, , 64, , 65, , 66, , 67, , 68, , 69, , 70, , 71, , 72, , 73, , 74, , 75, , Ans, , 1, , 4, , 2, , 3, , 3, , 1, , 2, , 1, , 3, , 3, , 3, , 4, , 4, , 1, , 4, , Que., , 76, , 77, , 78, , 79, , 80, , 81, , 82, , 83, , 84, , 85, , 86, , 87, , 88, , 89, , 90, , Ans, , 2, , 2, , 4, , 1, , 2, , 4, , 3, , 3, , 2, , 2, , 2, , 4, , 1, , 4, , 4, , Que., , 91, , 92, , 93, , 94, , 95, , 96, , 97, , 98, , 99, , 100, , 101, , 102, , 103, , 104, , 105, , Ans, , 3, , 2, , 1, , 2, , 1, , 4, , 3, , 3, , 3, , 4, , 3, , 4, , 4, , 2, , 3, , Que., , 106, , 107, , 108, , 109, , 110, , 111, , 112, , 113, , 114, , 115, , 116, , 117, , 118, , 119, , 120, , Ans, , 1, , 2, , 2, , 1, , 2, , 2, , 2, , 1, , 3, , 2, , 1, , 3, , 1, , 1, , 1, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 15

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , COORDINATION COMPOUNDS & d-BLOCK COMPOUNDS, 1., , What is the charge on the complex, [Cr(C 2O4 )2(H2 O)2] formed by Cr(III), , Among the following metal carbonyls,, the C-O bond order is lowest in., (1) [Mn(CO)6 ]+, (2) [Fe(CO)5 ], (3) [Cr(CO)6 ], , (1) +3, , (4) [V(CO)6] –, , The oxidation state of Mo in its oxido-complex, species [Mo2O 4(C 2H 4) 2(H 2O) 2], (1) +2, , 2., , 3., , (2) +3, , (2) +1, , 2–, , 10., , is, , (3) +4, , (4) +5, , (3) +2, , (4) –1, , In which of the following complex the nickel, , 11., , metal is in highest oxidation state?, (1) Ni(CO)4, , 4., , 5., , 6., , (a) Acetylacetonato, , (2) K2NiF6, , (b) Oxalato ion, , (3) [Ni(NH 3)6](BF 4 )2, , (c) Dimethylglyoximato, , (4) K4 [Ni(CN)6 ], A complex of platinum, ammonia and chloride, , Select the correct answer :-, , produces four ions per molecule in the solution., , (1) (a) only, (2) (a) and (c) only, , The structure consistent with the observation, , (3) (c) only, , is –, (1) [Pt(NH3)4]Cl4, , (4) (b) and (c) only, (2) [Pt(NH3)2 Cl4 ], , (3) [Pt(NH3)5Cl]Cl3, , (4) [Pt(NH3)4Cl2]Cl2, , 12., , (1) Chelating agent, (2) Tridentate neutral molecule, , when Co(NH3 )5 Cl 3 is treated with excess of, , (3) Tridentate monoanion, , AgNO 3 ?, (1) 1 mol, , (4) (1) and (2) both, (2) 2 mol, , (3) 3 mol, , (4) No ppt is formed, , 13., , NH, OH, , (2) +3, , 3+, , 14., , Co(en)2, , The donor sites of [EDTA], , (4) +6, , are, , 16, , Which of the following name is impossible :, , (4) All the impossible, 15., , The formula of sodium nitroprusside is, , (4) Three N atoms and Three O atoms, , (1) Na4 [Fe(CN)5 NO2 ], (2) Na2 [Fe(CN)5 NO+], , Among the following, metal carbonyls, the, , (3) NaFe[Fe(CN)6 ], , C-O bond is strongest in :, (1) [Mn(CO)6 ]+, (2) [Cr(CO)6 ], , (4) Na2 [Fe(CN)6 NO2 ], , (3) [V(CO)6], , (4) 8, , (3) Dichlorobis (urea) copper (II), , (2) N atoms only, (3) Two N atoms and four O atoms, , –, , (3) 6, , (2) Barium tetrafluoridochromate (II), , (1) O atoms only, , 9., , (2) 4, , (1) Potassium tetrafluoridoxido chromate (VI), , (3) +4, –4, , Total number of isomers in [Pt(NH 3) 2 (CN)2 ], is :(1) 2, , The oxidation number of Co in the complex ion, , (1) +2, , 8., , Diethylenetriamine is :-, , How many moles of AgCl would be obtained,, , (en)2Co, , 7., , Which of the following are bidentate, monovalent anion ligands ?, , (4) [Ti(CO)6], , 2–, , 16., , The formula of complex tris (ethylenediamine), cobalt (III) sulphate is :, , The bond length in CO is 1.128Å. What will, , (1) [Co(en)2 SO4 ], , be the bond length of CO in Fe(CO)5 ?, (1) 1.158Å, (2) 1.128Å, , (2) [Co(en)3 SO4 ], , (3) 1.078Å, , (4) [Co(en)3 ]2(SO4) 3, , (4) 1.118Å, , (3) [Co(en)3] 2SO 4, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 17., , Which of following pairs of name and formula, of complexes, is not correct ?, , 24., , of 1 : 3. The aqueous solution of the compound, , [Cu(NH3 )4 ]SO4, , showed 4 particles per molecule whereas molar, , (2) Diamminesilver(I)chloride..[Ag(NH3 )2 ]Cl, , conductivity reaveals the presence of six, , (3) Potassiumhexacyanidoferrate(III)..K4[Fe(CN)6], , electrical charges. The formula of the, , (4) Potassiumamminepentachloridoplatinate(IV), , compound is, , .......... K[PtCl5 (NH3)], , (1) Co(NO2)3 .2KNO2, , Complex ion [CuCl2(NH2CoNH2] is named as, , (2) Co(NO2)3 .3KNO2, , (1) dichloro bis (urea) copper (II), , (3) K3[Co(NO2 )6 ], , (2) bis (urea) dichloro copper (II), , (4) K[Co(NO2)4 ], , (3) dichloro bis (urea) copper (I), (4) bis (urea) dichloro copper (I), 19., , 22., , 23., , conductance, (1) [Co(NH3 )6]Cl3, , (1) [Al(C2 O4)3], [BF 4]3–, , (2) [Co(NH3)3Cl3 ], , (2) [Al(C2 O4)3 ]3+,[BF 4 ]3+, , (3) [Co(NH3)4Cl2]Cl, , (3) [Al(C2O4 )3]3– , [BF4 ]–, , (4) [Co(NH3 )5Cl]Cl2, , 2–, , 26., , A Coordination complex has the formula, , Calculate the EAN of central atom in the, following complexes:, , PtCl 4 .2KCl., , (i) [Cr(CO)6 ], , ion in one formula unit. Treatment with AgNO3, , (ii) [Fe( 5-C5 H5 )2 ], , produces no precipitate of AgCl. What is the, , In sodium nitroprusside, The oxidation number, coordination No. and effective atomic number, of iron are respectively:, (1) +3, 6, 36, (2) +2, 6, 36, (3) +3, 3, 36, (4) 6, +3, 35, In Tollen's reagent [Ag(NH3)2]+1. The oxidation, number coordination number and effective, atomic number of central metal ion are, respectively, [Atomic number of Ag = 47], (1) +1, 2, 50, (2) +1, 2, 51, (3) +2, 1, 50, (4) +1, 1, 50, , coordination no. of Pt in this complex, , Electrical, , (1) 5, 27., , (2) 6, , (3) 4, , three moles of Silver chloride when its one mole, is treated with excess of Silver nitrate:, (1) [Cr(H2 O)3 Cl3 ], (2) [Cr(H2O)4 Cl2]Cl, (3) [Cr(H2O)5 Cl]Cl 2, (4) [Cr(H2O)6]Cl3, 28., , Concentrated H 2 SO 4 will not dehydrate the, , (1) oxidation of Co, , (2) [Cr(H2O)4Cl2]Cl.2H2 O, , (4) (2) & (3) both, , (4) 3, , Which of the following complexes produces, , following complex:, , (3) dimerization, , conductance, , measurements indicate the presence of three, , The effective atomic no. of Co(CO)4 is 35 and, hense is less stable. It attains stability by:, (2) Reduction of Co, , E, , Which of the following shows maximum molar, , borate(III) ions are :, , (4) [Al(C2 O4 )3] , [BF4 ], , 21., , 25., , Trioxalatoaluminate (III) and tetrafluoro-, , 2–, , 20., , A compound is made by mixing cobalt (III), nitrite and potassium nitrite solution in the ratio, , (1) Tetraamminecopper(II)sulphate................, , 18., , INORGANIC CHEMISTRY, , (1) [Cr(H2 O)5Cl]Cl2 .H2 O, (3) [Cr(H2O)6]Cl6, (4) All of these, , Your Target is to secure Good Rank in Pre-Medical 2021, , 17

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TARGET : PRE-MEDICAL 2021, 29., , On adding AgNO 3 solution to a solution of, , 35., , [Pt(NH 3 ) 3 Cl 3 ]Cl. The percentage of total, chloride ion precipitated is–, (1) 100, 30., , (2) 75, , (3) 50, , One mole of the complex compound, Co(NH 3 ) 5 Cl 3 gives 3 moles of ion on, , 36., , (4) NH3, , The complexes [Pt(NH 3 ) 4 ][PtCl 6 ], [Pt(NH3)4 Cl2] [PtCl4] are :-, , (1) [Co(NH3)4Cl]Cl2.NH3, , (4) Ionisation isomers, 37., , [Co(NH 3 )5 NO 2 ] Cl 2 and [Co(NH 3 )5 ONO]Cl 2, are related to each other as :(1) Geometrical isomers, (2) Linkage isomers, , Select the correct statement for the complexes, [Cr(H2O)6]Cl 3 and [Cr(H2O)5 Cl]Cl2.H2 O, (1) There can be differentiated by amount., , (3) Coordination isomers, (4) ionisation isomers, 38., , (2) There can be diffrentiated by electrical, conducting measurement method., 39., , (4) All of these, , 0, , (d) [PtCl2(NH3 )2] exihibits optical isomerism, , 0, , (1) TTFT, , (2) CoCl3.5NH3, , (3) CoCl3.4NH3, , (4) CoCl3.3NH3, , Following sidwick's rule of EAN, Co(CO)x will, be:, , (3) Co(CO)6, , (4) Co(CO)10, , Consider the following statement and arrange, in the order of true/false as given in the, codes :-, , 0, , (1) CoCl3.6NH3, , (2) Co(CO)3, , (4) 4, , (c) [Pt(NH3)4Br2]Cl2 and [Pt(NH3)4Cl2] Br2 are, linkage isomers, , Which of the following is non-conducting?, , (1) Co(CO)4, , (3) 3, , (b) [Cr(Py) 2 (H 2 O) 2 Cl 2 ]Cl, and, [Cr(Py)2(H2O)Cl3]H2O are ionisation isomer, , CFSE, 0 0, 1.2, 1.6, 0.8, , (2) 2, , (a) [Cr(NH3 )6 ][Cr(CN)6] and [Cr(NH3 )4(CN)2 ], [Cr(NH3)2(CN)4] are coordination isomers:-, , Select incorrect match for [M(H 2 O) 6 ] 2+, complex., , Electronic, Metal ions, configuration, 2, Mn, t 32g e 2g, V2, t 32g e 0g, Ni2, t 62g e 2g, Ti 2, t 22g e 0g, , The no. of geometrical isomers of, [Co(NH3 )3(NO3)3 ] are :(1) 0, , (3) There can be diffrentiated by heating with, conc. H2 SO4 ., , 1, 2, 3, 4, , and, , (3) Co-ordination isomers, , (4) [Co(NH3)4Cl2 ]Cl.NH3, , 18, , (3) CN, , (2) Optical isomers, , (3) [Co(NH3 )3Cl].2NH3, , 34., , (2) SCN, , solution to yield two moles of AgCl(s). The, structure of the complex is–, , (2) [Co(NH3)5 Cl].Cl2, , 33., , (1) NO2, , (1) Linkage isomers, , complex reacts with two moles of AgNO 3, , 32., , Which of the following cannot show linkage, Isomerism :-, , (4) 25, , dissolution in water. One mole of the same, , 31., , INORGANIC CHEMISTRY, , 40., , (2) FTFT, , (3) TTFF, , (4) TFFF, , Which of following isomers of [M(NH3 )2Cl2 ], would react with silver oxalate (Ag 2C2 O4 ) :Cl, , H3N, M, , (1), H3N, , M, , (2), Cl, , (3) Both, , Your Target is to secure Good Rank in Pre-Medical 2021, , Cl, , H3N, Cl, , H 3N, , (4) None, E

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TARGET : PRE-MEDICAL 2021, 41., , Which of the following complex will follow, , 45., , Three arrangements are shown for the complex, , EAN rule ?, , [Co(en)(NH 3 ) 2 Cl 2 ] + pick up the correct, , (1) [Mn(Co)5 ], , statement:Cl, , (2) [Mn(Co)6 ], (I), , (4) [Co(Co)4 ], , NH3, Co, , en, , H3 N, , (II), , NH3, Co, , en (III) en, , Co, NH3, , NH3, NH3, , Identify the geometrical isomers of the, following:-, , Cl, , Cl, , (1) II and III are optical isomers, , Cl, , en, , Cl, , en, , Cl, , Cl, , Cl, , (3) [Fe(Co)5 ], , 42., , INORGANIC CHEMISTRY, , en, , Cl, , en, , (2) I & III are optical isomers, Cl, , (3) I & II one geometrical isomers, , en, , (4) II & III are geometrical isomers, Cl, , Cl, (I), , en, , en, , (II), , Cl, , (III), , en, , Cl, , 46., , Which kind of isomerism is exhibited by, octahedral [Co(NH 3 )4 Br2 ]Cl ?, , (iv), , (1) Geometrical & ionization, (1) I with III, , (2) Geometrical & optical, , (2) II with IV, , (3) Optical & ionization, , (3) I with II, , (4) Geometrical only, 47., , (4) None of these, 43., , (1) [Co(en)(NH3 )2 ]2+, , Which of the following compounds show, , (2) [Co(H2O) 4 (en)]3+, , optical isomerism ?, , (3) [Co(en)2 (NH3) 2] 3+, , (a) Cis-[Co(NH3)4Cl2 ]+, (b) trans-[Co(en)2 Cl2 ], , (4) [Co(NH3 )3 Cl]+, , +, , 48., , isomers ?, , (d) [Co(en)3 ]3+, , (1) [Pd(PPh3)2 (NCS)2] and [Pd(PPh3)2(SCN)2 ], , (1) a & b, , (2) [Co(NH3 )5NO3 ]SO4 and [Co(NH3)5SO4] NO3, (3) [PtCl2(NH3)4 ]Br2 and [PtBr2 (NH3)4 ]Cl2, (4) [Cu(NH3)4][PtCl4 ] and [Pt (NH3 )4] [CuCl4 ], , (3) c & d, , 49., , (4) a, b & d, , (2) Linkage, (3) Gemetrical, (4) Optical, , Select the correct statement from the following?, (1) [Sc(H 2 O) 6 ] 3+ and [Ti(H 2 O) 6 ] 3+ both are, , Which of the following isomerism is/are not, shown by the complex [CoCl2(OH)2(NH3)2]Br?, (1) Ionization, , E, , Which of the folloing pairs represents linkage, , (c) cis-[Co(en)2Cl2 ]+, , (2) b & c, , 44., , Which of the following has an optical isomer ?, , colourless, (2) [Co(NH3 )4 Br2]Cl show ionization isomers, and geometrical isomers, (3) [Pd(NO 2 ) 2 (NH 3 ) 2 ] is square planar and, shows geometrical as well as linkage, isomers, (4) Both (2) and (3) are correct, , Your Target is to secure Good Rank in Pre-Medical 2021, , 19

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TARGET : PRE-MEDICAL 2021, 50., , 57., , Complex, (a) Na2[Fe(CN)5NO], (b) [Fe(H2O)5NO]SO4, (c) K4[Fe(CN)6], Which of the following statement are wrong ?, (1) (a) is used in detation of S 2–, (2) complex part of each compound in, octahedral, (3) (c) is used in detection of Fe3+, (4) O.S. of Fe in (a) and (b) is +1, , 58., , 3. Geometrical isomerism, , [Pt(NH3 )(NH2 OH)(NO2)(Py)]+ will form how, many geometrical isomers :-, , 4. Optical isomerism, , (1) 2, , [Fe(en)2 (H 2 O)2 ] 2+ + en, , complex (x). The, , correct statement about the complex (x) it is, (1) a low spin complex, (2) diamagnetic, (3) shows geometrical isomerism, (4) (1) and (2) both, 51., , Which kind of isomerism is shown by the, complex [Co(NH3 )5 (ONO)]SO4 ?, 1. Ionization isomerism, 2. Linkage isomerism, , (1) 1, 2, 3, & 4 are correct, , 59., , (3) 1 & 2 are correct only, , (1) Ionisation, optical, , (3) Geometrical, optical, , (i) [Cr(ox) 3 ]3–, , (4) Coordinate, geometrical, 60., , Co(NO2)(Cl)2.5NH3 (Co is in + 3 oxidation state), , Select the correct code, , (1) It shows ionisation isomerism, , (1) (i) only, , (2) (i) & (ii) only, , (2) It is inner orbital complex, , (3) (ii) & (iii) only, , (4) (i), (ii), & (iii), , (3) It is diamagnetic, , The total No. of possible isomers of the, compound [CuII(NH3)4 ][PtII Cl4 ] are :(2) 5, , (3) 4, , (4) 6, , (4) All, 61., , (1) 2, 62., , (3) four optically active isomers; cis, d & from, and trans d & form, , (2) 3, , (3) 4, , (4) 5, , The complex [Pt(NH3)4]2+ has structure :(1) Square planer, (2) Tetrahedral, , (4) None, , 20, , The total No. of isomers possible for the, complex [Co(en)2 Cl2] is :-, , [Co(en)3] 3+ ion is expected to show :(2) Two optically inactive isomers, , 56., , Which of the following is true for the complex, , (iii) [Co(NH3)2Cl2 (en)]+, , (1) Two optically active isomers, , 55., , (4) 5, , (2) Hydrate, optical, , Which of the following complexes show, geometrical as well as optical isomerism ?, , (1) 3, 54., , (3) 0, , Isomerism exhibited by [Cr(NH3 )2 (H2O)2Cl2 ]+, are:-, , (ii) [Rh(en)2 Cl2 ]+, , 53., , (2) 3, , (2) 1, 3, & 4 are correct only, (4) 2, 3 & 4 are correct only, 52., , INORGANIC CHEMISTRY, , The number of geometrical isomers for, octahedral [Co(NH 3 ) 2 Cl 4 ] – , square planar, [AuCl2Br2 ]– respectviely are :(1) 4, 2, , (2) 2, 2, , (3) 3, 2, , (4) 2, 3, , (3) Pyramidal, (4) Pentagonal, 63., , Which of the following is not correctly matched ?, (1) [MnCl 4]–2 tetrahedral, zero CFSE, (2) [Pt(NH3)(Br),(Cl)(Py)] tetrahedral, EAN = 36, , How many isomers are possible for the complex, ion [Cr(NH3 )3 Cl3 ?, , (3) [Fe(CO)2 (NO)2]tetrahedral, EAN = 36, , (1) 3, , (4) [Co(CO)4]– tetrahedral, C–O B.L. larger than CO, , (2) 2, , (3) 4, , (4) 5, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 74., , Which of the following are square planar, , 80., , [Cu(NH3)4]SO4 :, , (i) [AuCl4]–, , (1) It is a Tetrahedral complex, , (ii) [PtCl4]2–, , (2) It is paramagentic with one unpaired, electron in the d-subshell, (3) It gives white precipitate with BaCl2, , (iv) [Cu(NH3)4]2+, , (4) Its aqueous solution does not conduct, , Select the correct answer using the codes given, , electricity., , below :81., , (1) i and ii only, , are:(1) Both sp3d2, , (3) ii and iv only, , (2) Both d2sp3, , (4) i, ii, and iv only, , (3) sp3d 2 and d2sp 3, , The crystal field-splitting for Cr 3+ ion in, , (4) d2sp 3 and sp3d 2, 82., , of the same metal with same oxidation state has, zero magnetic moment. The metal Ion could be:-, , (2) CN < I– < H2O < NH3, (3) CN < NH3 < H2O < I, (4) NH3 < H2O < I < CN, , 83., , Which of the following is a high spin complex?, , (3) Fe2+, , (4) Fe3+, , [Sc(H2O)6]3+ ion is :(1) Coloured and paramagnetic, (2) Colourless and paramagnetic, , (3) [Ni(CN)4]2–, , (4) [FeF 6]3–, , (3) Colourless and diamagnetic, , Which has maximum paramagnetic nature ?, 2+, , (2) [Cu(NH3)4], , (3) [Mn(H2O)6]2+, , (4) [Fe(CN)6]4–, , (4) Coloured & octahedral, , 2+, , 84., , Which of the following order of CFSE is, , Which of the following complex compounds, does not exhibits cis-trans isomerism ?, (1) [PtCl2(NH3)2 ], , (1) [Cr(NO2)6]3– > [Cr(NH3)6]3+ > [Cr(H2O)6]3+, , (2) [PdCl2BrI], , (2) [PtF4]2– > [PdF4]2– > [NiF4]2–, , (3) [Pt(NH3 )2 (Cl)(Br)], , (3) [Ni(DMG)2] < [Ni(en)2]2+, , (4) [Pt(NH3)3(Cl)]+, , (4) [Co(EDTA)]– > [Co(en)3]3+, Which of the following is/are inner orbital, complex as well as dimagnetic in nature :, (1) [Zn(NH3)6]2+, , (2) [Ni(NH 3)6]2+, , (3) [Cr(NH 3)6]3+, , (4) [Co(NH3)6]3+, , [Atomic no., 22, , (2) Mn2+, , (2) [Fe(CN)6]4–, , incorrect?, , 79., , (1) Co2+, , (1) [Co(NH3)6]3+, , (1) [Cu(H2O)4], 78., , A complex of certain metal has the magnetic, moment of 4.91 BM. whereas another complex, , (1) I < H2O < NH3 < CN, , 77., , The hybridisation of [CoF 6]3–& [Co(C 2O4)3]3–, , (2) ii and iii only, , octahedral field changes for I , H2O, NH3, CN, and the increasing order is :-, , 76., , Which of the following is/are correct about, , complexes ?, , (iii) [Mn(Br)4]2–, , 75., , INORGANIC CHEMISTRY, , Cr=24, Mn=25, Fe=26, Co=27], , 85., , Which of the following correct?, (1) Ti(NO3)4 is coloured, (2) [Cr(NH3)6]Cl3 is colourless, (3) K3[VF6] is colourless, (4) [Cu(NCCH3)4] [BF4] is colourless, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 86., , Of the following complex ions. The one that, , 93., , (1) [Ag(NH3)2][Ag(CN)2], , constant Kf is :-, , (2) [Pt(en)2][PtCl4], , 3+, , (2) [Co(H2O)6], , 3+, , (3) [Pt(NH3)4][Pt(C2O4)2], (4) [Pt(NH3)4][PtCl6], , (3) [Co(NH3)2 (H2O)4]3+ (4) [Co(en)3]3+, 94., , Which is not a -bonded complex ?, (1) Zeise's salt, (2) ferrocene, , (ii) Fe(CO)5, , (4) Tetraethyl lead, , (iii) V(CO)6, , What is wrong about the compound, , (iv) Cr(CO)6, , 2, , K[Pt( –C2H4)Cl3], , Select the correct code :-, , (1) It is called zeise's salt, , (1) I & II, , (2) It is, , (2) II, III & IV, , bonded complex, , (3) II & IV, , (3) Oxidation number of Pt is + 4, , (3) I, II, & IV, , (4) Four ligands surrounds the platinum atom, 89., , 95., , Which of the following order is not correct ?, , (2) [Co(CN)6]–3 > [Co(NH3)6]+3 > [Co(H2O)6]+3 value, , (3) No evolution of oxygen, (4) Bluish - green precipitate, , (3) [Ni(CO)4] > [Co(CO)4]– > [Fe(CO)4]–2, (M–C, +2, , bond strength), +2, , (Thermodynamic stability), , Which of the following is correct for zeise's salt ?, (1) The complex ion is square planar, (2) The CMI, Pt is in + 2 oxidation state, (3) H2C=CH2 Molecule is perpendicular to the, PtCl3 plane, (4) All of these, , 92., , Which amongst the following are, organometalic componds :(i) Al2(CH3)6 (ii) K[PtCl3(C2H2)] (iii) N(CH3)3, (1) i only, (2) iii only, (3) i, ii, and iii, The number of, salt is :(1) 8, , E, , (4) i and ii only, bonds in cation of shwetzer, , (2) 12, , (3) 14, , 96., , Pick out the incorrect statement:, , +2, , (4) [Ni(NH3)4] < [Ni(en)(NH3)2] < [Ni(en)2], , 91., , To an acidified dichromate solution, a pinch of, Na2O2 is added and shaken. What is observed:, (1) blue colour, (2) Orange colour changing to green, , (1) [Cr(NH3)6]+3 > [Mn(CN)6]–3 > [V(CO)6] spin m.m., , 90., , Which amongst the following metal carbonyls, are inner orbital complex with diamagnetic, property, (i) Ni(CO)4, , (3) bis(benzene) chromium, , 88., , Co-ordination isomerism is possible in :, , probably has the largest overall formation, , (1) [Co(NH3)6], , 87., , INORGANIC CHEMISTRY, , (4) 16, , (1) MnO 24, , is quite strongly oxidizing and, , stable only in very strong alkalies. In dilute, alkali,, neutral, solutions,, it, disproportionates., (2) In acidic solutions, MnO 4 is reduced to, Mn2+ and thus, KMnO4 is widely used as, oxidising agent, (3) KMnO4 does not acts as oxidising agent in, alkaline medium, (4) KMnO4 is manufactured by the fusion of, pyrolusite ore with KOH in presence of air, or KNO 3 , followed by electrolytic, oxidation in acidic medium, , Your Target is to secure Good Rank in Pre-Medical 2021, , 23

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TARGET : PRE-MEDICAL 2021, 97., , 98., , When a small amount of KMnO4 is added to, concentrated H2SO4, a green oily compound is, obtained which is highly explosive in nature., Compound may be :, (1)Mn2 O 3, (2) MnSO4, (3) Mn2O 7, (4) MnO2, The incorrect statement(s) about Cr2+ and Mn3+, is (are), [Atomic numbers of Cr = 24 and Mn = 25], (2) Mn3+ is an oxidizing agent, (3) Both Cr2+ and Mn3+ exhibit d4 electronic, (4) When Cr2+ is used as a reducing agent, the, chromium ion attains d, configuration, , 5, , electronic, , (1) CH 3Cl, , (2) AgCl, , (3) Hg2Cl2, , (4) NH4Cl, , 0, , (2) –0.6, , (3) –1.2, , 0, , (4) –1.6 + P, , 0, , 101. Select the incorrect statement on basis of, following conversion :H, , Dark, green, , Z, , +, , X, , an oxidising, agent, , 105. Species which represent maximum crystal field, stablisation energy :(1) [Co(CN)6]–3, , (2) [Co(C2O4)3]–3, , (3) [Ni(H 2O)6]+2, , (4) Both (1) and (2), , value of d 5 configuration for tetrahedral, complex ?, (2) 0.0, , (3) –2, , (4) +2, , 107. Which of the following complex show, maximum numbers of stereo isomers is :-, , –2, , (3) Cr(NH 3 )2 (en) 2, , +3, , –3, , 108. A Pt complex of NH3 and chlorine produces, four ions per molecule in the solution is :(1) [Pt(NH3)4Cl2]Cl 2, , (2) [Pt(NH3)6]Cl 4, , (3) [Pt(NH3)2]Cl 4, , (4) [Pt(NH3)5Cl]Cl 3, , 109. The most stable complex ion is :-, , (1) X may be MnO2, (2) Y can be K2MnO4, , (1) [Fe(C 2O4)3]3–, , (2) [Fe(H2O)6]+3, , (3) [Fe(CN)6]4–, , (4) [Fe(CN)6]3–, , 110. Which of the following complex is example of, , (3) Z can be KMnO4, , strongest reducing agent ?, , (4) None of these, , (1) [Co(CN)6]–3, , (2) [Co(CN)6]–4, , (3) [Ag(CN)2]–1, , (4) [Cu(CN)4]–3, , 102. When KMnO 4 reacts with KBr in acidic, medium then oxidation state of Mn changes, from +7 to :(1) +2, , (2) +4, , (3) +3, , (4) +6, , 103. Crystal field stabalisation energy for complex, [Co(CN)6]–3 will be :-, , 24, , (4) [Fe2(CO)9], , (4) Co(C 2 O 4 )3, , (1) –1.8, , Black, coloured, ore, , (3) [Mn(CO)5], , (2) CuBr2Cl 2, , 100. Crystal field stablisation energy for high spin, d4 octahedral complex is :-, , Y, , (2) [Fe(CO)5], , (1) PtCl3 (C 2 H 4 ), , Chromyl chloride test is given by -, , KOH, air, , (1) [Mn2(CO)10], , (1) 0.4, , configuration, , X, , 104. Which of the following is an oxidising agent?, , 106. What is the crystal field stabalisation energy, , (1) Cr2+ is a reducing agent, , 99., , INORGANIC CHEMISTRY, , (1) +2.4, , 0, , + 3P, , (2) –2.4, , 0, , + 2P, , (3) –3.6, , 0, , + 3P, , (4) –1.8, , 0, , + 3P, , 111. Pair of compound which is planar :(1) [Ni(CN)4]–4, [PtCl4]–2, (2) [NiCl4]–4, [Ni(CN)4]–2, (3) [PtCl4]–2, [Ni(CO)4], (4) [Ni(CN)4]–2, [Rh(CO)2(PPh3)2]+, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 112. Which of following is diamagnetic ?, , 116. Match the column, Column-I, Column-II, (A) [Co(NH3 )4 (H2 O)2 ]Cl2 (p) Geometrical, isomers, (B) [Pt(NH3)2 Cl2 ], (q) Paramagnetic, (C) [Co(H2O)5Cl] Cl, (r) Diamagnetic, (D) [Ni(H2 O)6 ]Cl2, (s) Metal ion, with + 2, oxidation state, , (1) [RhCl(CO)(PPh3)(NH3)], (2) [RhF 6]–3, (3) [Ir(H2O)6]F 2, (4) [MoCl6]–3, 113. The relationship between, , [Co(NH 2–CH 2–CH–CH2–NH2)2Cl2]+ and, CH3, [Co(NH2–CH2–CH2–CH2–NH2]2Cl2]+ is, , INORGANIC CHEMISTRY, , 117. Match the column, Column-I, (A) [Ni(CO)4], , (1) Linkage isomer, (2) Ligand isomers, , Column-II, (p) Tetrahedral, , (B) [Fe (NO)2(CO)2] (q), , (3) Coordination isomer, (4) Solvate isomers, , -back bonding, , (C) [Ni (PF3)4], , (r), , diamagnetic, , (D) [NiBr2(PPh3)2], , (s), , One of the ligand, is three e– donor, , MATCH THE COLUMN, 114. Match the pair of complexes given in Column-I, the characteristic (s) given in Column-II, Column-I, , Column-II, , (1) (NH4 )2[NiCl4 ] and, (NH4) 2[Ni(CN)4 ], , same electrical, conductance., , (2) CoCl3.6NH3 and, , (Q) Both show, , PtCl4.5NH3, , Column-I, (A) [Cu(NH3)4, , Column-II, ]2+, , (4) K2[Fe(H2O) 6] and, , (p) Outer orbital complex, , (B) [CuCl4]2–, , (q) Inner orbital complex, , (C) K2[Cr(CN)4, , (r) Magnetic moment, , (NH3)(NO)], , = 1.73 B.M., , (D) K4[Co(NO2)6] (s) Metal O.S. +2, , same EAN., , (3) [Pt(NH3)2 Cl2 ] and, (NH4)2[PtCl4 ], , K4 [FeCl6 ], , (P) Both show, , 118., , (t) During hybridisation, , (R) Both show, same primary, , d-orbital e– jumps, , valancies, , to higher energy, orbital, , (S) Both gives, white precipitate, with AgNO3, Solution, , 119. match the complexes listed in column-I with, characteristic (s) /type of hybridisation listed in, column-II :, Column-I, , 115. Match the column, Column-I, (A) [Pd(NH3 )2Cl2 ], , Column-II, (p) Geometrical, isomerism, 3–, (B) [Co(OX)3 ], (q) Diamagnetic, (C) [Fe(H2 O)4 Cl2 ], (r) Inner orbital, complex, –, (D) [Co(NH3)2 (NO2) 4] (s) Paramagnetic, , E, , (A) [Co(en)3], , 3+, , Column-II, (p) Sp3 d2 hybridisation, , (B) [Co(ox) 3]3–, , (q) Diamagnetic, , (C) [Co(H2O)6]2+, , (r) d2 sp3 hybridisation, , (D) [Co (NO2)6]4– (s) Paramagnetic, , Your Target is to secure Good Rank in Pre-Medical 2021, , (t) Chelating reagent, , 25

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 2, , 4, , 2, , 3, , 2, , 2, , 3, , 1, , 1, , 4, , 2, , 4, , 3, , 1, , 2, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , Ans, , 4, , 3, , 1, , 3, , (i) 36 (ii) 36, , 2, , 1, , 4, , 3, , 1, , 2, , 4, , 3, , 4, , Que., , 30, , 31, , 32, , 33, , 34, , 35, , 36, , 37, , 38, , 39, , 40, , 41, , 42, , 43, , 44, , Ans, , 2, , 4, , 3, , 4, , 3, , 4, , 3, , 2, , 2, , 4, , 1, , 3, , 3, , 3, , 2, , Que., , 45, , 46, , 47, , 48, , 49, , 50, , 51, , 52, , 53, , 54, , 55, , 56, , 57, , 58, , 59, , Ans, , 3, , 1, , 3, , 1, , 4, , 4, , 3, , 3, , 3, , 1, , 2, , 2, , 4, , 2, , 3, , Que., , 60, , 61, , 62, , 63, , 64, , 65, , 66, , 67, , 68, , 69, , 70, , 71, , 72, , 73, , 74, , Ans, , 4, , 2, , 1, , 2, , 2, , 4, , 3, , 2, , 2, , 4, , 4, , 2, , 3, , 2, , 4, , Que., , 75, , 76, , 77, , 78, , 79, , 80, , 81, , 82, , 83, , 84, , 85, , 86, , 87, , 88, , 89, , Ans, , 1, , 4, , 3, , 3, , 4, , 3, , 3, , 3, , 3, , 4, , 4, , 4, , 4, , 3, , 3, , Que., , 90, , 91, , 92, , 93, , 94, , 95, , 96, , 97, , 98, , 99, , 100, , 101, , 102, , 103, , 104, , Ans, , 4, , 4, , 4, , 4, , 3, , 1, , 3, , 3, , 4, , 4, , 2, , 4, , 1, , 2, , 3, , Que., , 105, , 106, , 107, , 108, , 109, , 110, , 111, , 112, , 113, , Ans, , 1, , 2, , 3, , 4, , 4, , 2, , 4, , 1, , 2, , MATCH THE COLUMN, , 26, , Que., , 114, , (A) P, Q, R; (B) P, S; (C) Q, R; (D) Q, R, , Que., , 115, , (A) p, q, r ; (B) q, r ; (C) p, s ; (D) p, q, r, , Que., , 116, , (A) p, q, s ; (B) p, r, s ;(C) q, s ; (D) q, s, , Que., , 117, , (A)-p, q, r; (B) p, q, r, s; (C) p, q, r; (D)-p, , Que., , 118, , (A)-q, r, s, t; (B)-p, r, s; (C) q, r; (D)q, r, s, t, , Que., , 119, , (A)-q,r,t; (B)-q,r,t; (C)p,s; (D) r,s, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , p-BLOCK ELEMENT, 1., , The main factor responsible for weak acidic, nature of B-F bonds in BF 3 is :-, , 9., , (1) AlCl 3 - nonplanar, all bonds are not, identical, (2) SO 3 - p -d, bonding present, sp 3, hybridisation, (3) PBr5 - sp3 and sp3d2 hybridisation, (4) BeCl2 - Complete octet, nonplanar, , (1) Large electronegativity of F, (2) Three centred two electron bonds in BF 3, (3) p - d back bonding, (4) p –p, 2., , back bonding, , Which of the following statements is true on the, basis of back bonding ?, (1) Si-O bond is stronger than C–O bond, (2) Dimethyl ether acts as a better lewis base, but not disilyl ether (SiH3 -O-SiH 3 ), (3) (CH3)3C–O–H is less acidic than (CH3)Si-OH, , 10., , Which of the following statements is/are false, (1) NMe3 and N(SiH3)3 are not isostructural, , 11., , 12., , 6., , (2) PCl5, , (3) NO2, , (4) HCl, , –2, , –2, 6, , (2) S 2 O5, , –2, , (4) S 2 O7 –2, , (4) H4P 2O 6, , (I) H2S 2 O5 (II) H2 SO5 (III) H2S 2 O6, , Compound, , -bonds in, , Properties, , A B2H6, , 3c 2e bond, , B, , HNO3, H2SO4, , p bond, , C, , AlF3, AlCl3, , Hypovalent, , D NCl3, SbCl3, , Equal bond angles, , Correct code is :, (1) A, (2) A,C, 14., , (3) Pb+2 > Pb+4, (4) Bi+3 < Bi+5, , E, , (3) H4P 2O 5, , Determine the correct order of stability :(2) Sn+2 > Sn+4, , 8., , (2) H2S 2O 5, , 13., , (1) Al+1 > Al+3, , 7., , (1) H2 S 2 O 7, , (3) II < I < III, , There is no S-S bond in:, (3) S 2O, , Which of the following pyroacid has X-X bond, , (4) I > III > II, , Which is food presentive as well as anti chlor?, , (1) S 2 O3, , (4) 0, , (2) III < II < I, , (4) None, , 5., , (3) 2, , (1) I < II < III, , (3) In trisilyl amine [(SiH3)3 N] all N-Si bond, lengths are identical but shorter than the, expected N-Si bond length, , (1) SO2, , (2) 3, , Increasing order of number of, above compounds, , (2) Methyl isocyanate (CH3–N=C=O) is bent, but silyl isocyanate (SiH3-N=C=O) is linear, , 4., , Number of P–OH bonds is sodium dihydrogen, pyrophosphate –, (1) 4, , (4) All of these, 3., , Which of the following is not correctly matched, for solid state of following compound ?, , Which of the following oxyacid is not a true, peracid ?, (1) Perbenzoic acid, , (2) Pernitric acid, , (3) Perchloric acid, , (4) All of these., , Which oxy acids are stable only in aq. state not, in solid state ?, (1) HClO3, HClO4, , (2) HBrO4 , HIO4, , (3) HBrO3 , HIO3, , (4) HBrO2 , HIO2, , (3) A,D, , (4) All, , In which of the following options all species, contain X–O–X bonds in structure (X = central, atom), (1) H2S 2O5 , S 3O9, S 2O6 –2, (2) P 4 O10 , P 4 O6, H3 P 3 O9, (3) N2O 5, N2 O, N2O 4, (4) H4P 2 O7 , H4 P 2O6 , H4 P 2O 5, , 15., , Order of stability of halogen oxides :(1) I < Cl < Br, , (2) I > Cl > Br, , (3) I < Cl > Br, , (4) I > Cl < Br, , Your Target is to secure Good Rank in Pre-Medical 2021, , 27

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TARGET : PRE-MEDICAL 2021, 16., , Si2 O5, , 2n, n, , anion is obtained when :, , 22., , with another SiO44 tetrahedron, (2) one oxygen of a SiO, , (2) Boron is used as controller in nuclear, reactor., , tetrahedron is, 4, 4, , shared with another SiO tetrahedron, (3) two oxygen of a SiO, , 4, 4, , (4) All of these, 23., , (1) Dimetaphosphoric acid, , shared with another SiO44 tetrahedron, BCl3 does not exist as dimer but BH3 exist as, dimer (B 2 H6 ) because :-, , (2) Pyro phosphorous acid, , 4, 4, , (1) Chlorine is more electronegative than, hydrogen, , (3) Cyclic trimetaphosphoric acid, (4) Hypo phosphorous acid, 24., , (2) It is obtained by treating borax with conc., H2SO4, , (3) Large sized chlorine atoms do not fit, between the small boron atoms whereas, small sized hydrogen atoms get fitted, between boron atoms., (4) None of these, , Which of the following is incorrect for H3BO3, (1) It has a layer structure in which H3BO3 units, are joined by hydrogen bonds, , (2) There is p -p back bonding in BCl 3 but, BH3 does not contain such bonding, , 18., , P–O–P bond is absent in :-, , tetrahedron are, , (4) three oxygen of a SiO, 17., , (3) T and Pb are poisonous in nature, , tetrahedron are, , shared with another SiO44 tetrahedron, , Which of the following statement is correct:, (1) KI is added into I2 to increase its solubility, in water, , (1) no oxygen of a SiO44 tetrahedron is shared, 4, 4, , INORGANIC CHEMISTRY, , (3) It does not act as a proton donor but acts, as an acid by accepting hydroxyl ions, (4) None of these, 25., , Incorrect statement regarding following, reactions is :, , Maximum P-O-P linkage present in :(1) P 4O 6, (2) P 4 O10, (3) (HPO3 )3, (4) same for (1) & (2), , (1) 'X' is explosive, , 26., , (2) 'Y' is an oxyacid of xenon, , Which of the following oxide does not give, any oxyacid in aqueous solution ?, , (3) Both are example of non-redox reaction, , (1) N2 O 5, , (4) XeF 6 can undergo partial hydrolysis, 19., , 20., , 27., , Na2S 2O3 is oxidized by I2 to give, (1) Na2S, , (2) NaHSO3, , (3) Na2SO4, , (4) Na2S 4O6, , (1) (R3 NO) < (R3 PO), , 28., , (2)(R 3NO) > (R3PO), (3) (R3 NO) = (R3 PO), (4) None of these, 21., , 28, , Product formed when PCl 5 react with conc., H2SO4:, (1) SOCl2, , (2) SO2Cl2, , (3) S2Cl2, , (4) SO2, , 29., , (3) CrO3, , (4) N2 O, , Which is not correct ?, (1), (2), (3), (4), , Correct statement about dipole moment is :-, , (2) Cl2 O7, , Borax : Cyclic, 2-(six member ring), Calgon : Cyclic, (10 member ring), Beryl : Cyclic silicate, P4O10 : Cyclic, four -(Six member ring), , Number of peroxide linkage in CrO5 , H2 SO5 ,, H2 S 2 O8 are respectively :(1) 2, 1, 2, (2) 2, 2, 2, (3) 1, 1, 1, (4) 2, 1, 1, Which of the following salt does not give any, ppt with AgNO3 sol.:, (1) F– salt, , (2) Cl– salt, , (3) Br– salt, , (4) I– salt, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 62., , Which of the following statements is not, correct :-, , 68., , Which, , INORGANIC CHEMISTRY, , of, , Cold, dil. NaOH, , (1) Cl2, , (2) The ionic character of lead (II) halide, decreases with increase in atomic number, of halogen., , (3) F2, , 64., , S tro ngly, h ea ted, , (H y d rate d s alt), , 65., , (2) Fe2O3, , (3) V2O5, , 69., , 70., , 71., , 72., , (4) NO, , Which is not the use of sulphuric acid ?, , 73., , (1) Petroleum refining, (2) Detergent industry, (3) Manufacture of aqua regia, (4) In storage batteries, 66., , 74., , Which of following species do not give borax, bead test ?, , 75., , (1) Co +3, (2) Cv +3, (3) Ni2+, (4) Au +, 67., , In layer test of I– and Br–. If reddish -brown, layer comes first then (1), , Br–, , (2), , I–, , O, , x, , N, , absent, , (4) None of these, E, , 76., , tra n sp are n t, g la ssy be a d, , C + D, , Identify C(1) (BN)X, (2) NaPO3, (3) B2O3, (4) Mg(NH4)PO4, Find the number of water of crystallizations, in (A) :(1) 4, (2) 5, (3) 10, (4) 24, How many X–O–X linkages are present in, structure of A (X = central atom)(1) 4, (2) 3, (3) 5, (4) 2, Find the number of tetrahedral and trigonal, planar units in structure of A (1) 2,1, (2) 2,2, (3) 2,4, (4) 5,2, In S 8 each sulphur atom is :(1) sp hybridised with a planar ring, (2) sp3 hybridised with a planar ring, (3) sp3 hybridised with a non-planar ring, (4) sp3d hybridised two sulphur atoms, The percentage of p-character in the orbital, forming P–P bonds in P 4 is :(1) 25, (2) 75, (3) 33, (4) 100, Inorganic benzene reacts with HCl to form a, compound B3N3H9Cl3. The protonation occurs, at :(1) B-atom, (2) First at N-atom, then rearranges into B-atom, (3) N-atom, (4) First at B-atom, then rearranges into N-atom, Compare, , present, , (3) Both (1) and (2), , ( ), , B + C, , S tro ngly, h ea ted, , H 3B O 3, , Catalyst for Deacon's process, (1) CuCl2, , Conc., H 2SO 4, , (4) H3PO4, , (A ), , (1) redox reaction ; –3 and –5, , (3) disproportionation reaction ; –3 and +1, (4) disproportionation reaction ; –3 and +3, , (2) KCl, , H2 O, , (4) The liquification of Noble gases decreases, down the group., , (2) redox reaction ; +3 and +5, , shows, , Paragraph for Q. 69 to Q. 72, , (3) Melting point and boiling point of halogen, increases down the group due to increase, in London-dispersion force., , The reaction of white phosphorus with, aqueous NaOH gives phosphine along with, another phosphorus containing compound., The reaction type ; the oxidation states of, phosphorus in phosphine and the other product, are respectively, , following, , disproportionation ?, , (1) Oxidising power = SiCl4 < SnCl4 < PbCl4, , 63., , the, , O, , (1) x > y,, (3) x > y,, , <, >, , Your Target is to secure Good Rank in Pre-Medical 2021, , O, , y, , O, , N, O, , (2) x < y,, (4) x < y,, , <, >, 31

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TARGET : PRE-MEDICAL 2021, 77., , 78., 79., , 80., , When excess amount of NH3 is reagent with Cl2, gives :(1) NH4Cl, (2) N2, (3) NCl 3, (4) (1) & (2) both, Most stable tri halides of nitrogen :(1) NCl3, (2) NF 3, (3) NBr3 (4) NI3, Which of following acid can not be prepared, by using conc. H2SO4 from its corresponding, salt ?, (1) HF, (2) HBr, (3) H2S, (4) HI, Consider, , 81., , (2) sp3d2, sp3d, (3) sp3, sp 3d2, (4) sp3d3, sp3d, 82., , A, , PH4I + KOH, , A + B + H2O, (gas), , (salt), , Incorrect statement :(1) 'A' is inflammable gas, (2) 'B' is salt of (SB + SA), (3) 'A' follows Drago's rule, , –H2O, +O, , The hybridisation of Xe and Sb in product when, XeF4 react with SbF5 :(1) sp3d, sp3d 2, , D, E, , INORGANIC CHEMISTRY, , +H2SO4, –H2O, , –O, , B, , (4) 'A' is a weaker lewis base than NH 3, , C, 83., , +O, , F, If A is H2SO4 then incorrect statement is :(1) Hydrolysis of E produces H2O 2, (2) D has maximum oxidation state of S, (3) Both E and F contains peroxide linkage, (4) C is caro's acid, , 84., , In which of the following molecule, vacant, orbital is not necessary for dimer formation :(1) BH3, , (2) AlCl3, , (3) CH3 COOH, , (4) BeCl2(s), , Which of the following compound does not, have hydrogen bonding :, (1) K2HPO4, , (2) K2HPO3, , O, (3) NaHCO3(s), , (4) CH3–C=CH–C–CH3, , O–H, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 4, , 4, , 4, , 1, , 4, , 3, , 3, , 4, , 3, , 3, , 2, , 3, , 1, , 2, , 2, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , 25, , 26, , 27, , 28, , 29, , 30, , Ans, , 4, 31, , 3, 32, , 2, 33, , 4, 34, , 2, 35, , 2, 36, , 4, 37, , 4, 38, , 4, 39, , 4, 40, , 4, 41, , 2, 42, , 4, 43, , 1, 44, , 3, 45, , 1, 46, , 4, 47, , 3, 48, , 4, 49, , 3, 50, , 4, 51, , 3, 52, , 1, 53, , 2, 54, , 4, 55, , 3, 56, , 1, 57, , 4, 58, , 3, 59, , 4, 60, , 3, 61, , 3, 62, , 2, , 4, , 1, , 3, , 3, , 2, , 2, , 1, , 1, , 2, , 63, , 64, , 65, , 66, , 67, , 68, , 69, , 70, , 71, , 72, , 3, 73, , 2, 74, , 3, 75, , 1, 79, , 3, 80, , 4, 81, , 3, 82, , 1, 83, , 3, 84, , 3, , 3, , 2, , 3, , 2, , 3, , 1, , 4, , 1, , 1, , 3, , 2, , Que., Ans, Que., Ans, Que., Ans, Que., , 1, 76, , 4, 77, , 3, 78, , Ans, , 1, , 4, , 2, , 32, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , METALLURGY, 1., , 2., , 3., , 4., , 5., , E, , In order to refine "copper" it is melted in a, furnace and it is stirred with green logs of, wood. The purpose is :(1) to expel the dissolved gases in blister copper, (2) to reduce the metallic oxide impurities with, hydrocarbon gases liberated from the, wood, (3) to bring the impurities to surface and oxidise, them, (4) to increase the carbon content in copper, The process which involves the treatment of the, ore with a suitable reagent as to make it soluble, while impurities remain insoluble is called :(1) froth floatation process, (2) leaching, (3) self reduction, (4) hydrometallurgy, Select correct matching :(1) Pyrometallurgy : Extraction of Fe, (2) Electrometallurgy : Extraction of Al, (3) Hydrometallurgy : Extraction of Au, (4) All above are correct, Read the following statements :(I) Al has greater affinity than that of Cr, for, oxygen, (II) Al can be used for reduction of Fe2O3, (III) Carbon is used for reduction of copper, oxide (CuO), (IV) SnO2 can be reduced by carbon, Choose the correct set of statement(s), (1) I, III, (2) I, II, IV, (3) I, II, III, (4) All of these, Which of the following is incorrect ?, (1) Leaching is a method to remove, quantitatively Fe2O3 from red bauxite, (2) Metallurgy, of, gold, involves, pyrometallurgical process form soluble, complex formation, (3) Metallurgy, of, silver, involves, hydrometallurgical process form soluble, complex formation, (4) Self reduction is not possible during, metallurgy of Mg, , 6., , 7., , Which of the reactions occurs in slag formation, zone in blast furnace for manufacture of iron ?, (1) Fe2O3 + 3C, 2Fe + 3CO, (2) CO2 + C, 2CO, (3) FeO + SiO2, FeSiO3, (4) CaO + SiO2, CaSiO3, Which of the following diagram is correctly, related to the extraction of Zn from calamine ?, (1) Cala min e, , Roasting, , Roasting, with air, , (2) Cala min e, , 8., , Heating, with, cala min e, , Roasted ore, , Carbon, reduction, , Roasted ore, , (3), , Cala min e, , Calcination, , Calcinated ore, , Reduction by Hg, , (4), , Cala mine, , Calcination, , Calcinated ore, , Reduction byCarbon, , Zn, , Zn, Zn, Zn, , Select the flow diagram which is correct for, extraction of particular metal from its ore :(1), , (2) Red Bauxite, , Serpeck's, process, , Al2O3, , Electrolytic, reduction, , Al(impure), , Electrolytic, refining, , Al(pure), , (3), , (4), , 9., , Both copper carbonate and copper hydroxide, are present in :(1) malachite, (2) azurite, (3) chalcopyrite, (4) Both (1) and (2), , 10., , Ag2S + KCN, Excess, , Ag CN, , n, x, , [Ag(CN)x]–n + Zn, [Zn(CN)y ]–m, Find the sum of x and y, (1) 4, (2) 6, (3) 8, (4) 10, , Your Target is to secure Good Rank in Pre-Medical 2021, , 35

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TARGET : PRE-MEDICAL 2021, 11., , 12., , When ZnS and PbS minerals are present, together, Then NaCN added to separate them, in the froth floation process as a depressant,, beacuse :(1) Pb(CN)2 is precipitated while no effect on, ZnS, (2) ZnS forms soluble complex Na 2[Zn(CN)4 ], (3) PbS forms soluble complex Na2 [Pb(CN4)], (4) If decreases the floatation property of PbS, by making it hydrophillic, Which of the following statement is not correct, regarding calcination ?, (1) Impurities are removed in the form of, elemental vapours, (2) Carbonate ores convert into their oxides, (3) Temperature of the proces is maintained, below the melting point of the mixture, (4) Lower oxidation state oxides are oxidied, further, , 15., , Which of the following is not correctly matched :(1) Removal of its own oxide impurity from, impure Cu, , Poling process, , (2) Removal of Pb impurity from impure Ag, Cupellation, (3) Obtaining wrought iron from cast iron, Bessemerisation, (4) Refining of Nickel, 16., , Mond's process, , The method of zone refining of metals is based, on the principle of :(1) Greater mobility of the pure metal than that, of impurity, (2) higher melting point of the impurity than, that of the pure metal, (3) Greater noble character of the solid metal, than that of the impurity, (4) Greater solubility of the impurity in the, molten state than in the solid, , 17., , 13., , INORGANIC CHEMISTRY, , The reduction of an oxide by aluminium is, called :(1) Bayer's process, (2) Goldschmidt's aluminothermite process, (3) Hall's process, , 14., , above metallurgy is possible when ore is :(1) ZnCO3, (2) CaCO3.MgCO3, (3) CuCO3.Cu(OH)2, (4) PbS, The Ellingham diagram of ZnO and CO is, converting in corresponding oxides is :-, , (4) van Arkel process, 18., , Which of the following sulphide ore is not, concentrated by froth-floatation process ?, (1) Galena, (2) Zinc blend, (3) Argentite, (4) Cinnabar, , G°(kJ), –200, , 19., , 2Zn+O2, , nO, , 2C+O2 2CO, , –600, 1180, T in °C, To make ZnO, , C, , Zn CO reduction proces, , spontaneous, temperature should be :, (1) 1000°C, (2) > 1100°, (3) < 500°C, (4) < 1100°C, 36, , Which of the following statements is correct, regarding the slag formation during the, extraction of a metal like copper or iron., (1) The slag is lighter and lower melting than, the metal, (2) The slag is heavier and lower melting than, the metal, (3) The slag is lighter and higher melting than, the metal, (4) The slag is heavier and higher melting than, the metal., , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 20., , Which of the following factors is of no, significance for roasting sulphide ores to the, oxides and not subjecting the sulphide ores to, carbon reduction directly ?, (1) Metal sulphides are thermodynamically, more stable than CS 2, (2) CO2 is thermodynamically more stable than, CS2, (3) Metal sulphides are less stable than the, corresponding oxides, (4) CO 2 is more volatile than CS 2, In the context of the Hall-Heroult process for, the extraction of Al, which of the following, statements is false ?, (1) Al3+ is reduced at the cathode to form Al, (2) Na3AlF 6 serves as the electrolyte, (3) CO and CO2 are produced in this process, (4) Al2O3 is mixed with CaF2 which lowers the, melting point of the mixture and brings, conductivity, Paragraph for 22 to 24, , 21., , 22., , 23., , 24., , 25., , Which of the above curve is wrongly, presented (1) C, CO2, (2) Pb, PbO, (3) Zr, ZrO2, (4) Mg, MgO, Which of the above metal oxide is having, minimum, thermal, decomposition, temperature., (1) CaO, (2) FeO, (3) ZrO2, (4) MgO, Which of the following metal's oxide can be, reduced by Fe as reducing agent at, temperature (T1), (1) Zr, (2) Ca, (3) Mg, (4) None of these, Match column (I) (process) with column (II), (electrolyte), , Column (I) (process), (1) Castner Kellner's cell, (2) Self-reduction, (3) Hall-Heroult, , 26., , Match the column :-, , O, Zr Zr 2, , Extracted by the, reduction of ore by, carbon, , P Ag, , 2, , Extracted by the, formation of soluble, complex, , Q Zn, , 3, , By product as anode R Fe, mud of electrolytic, refining of Cu, , 4, , Metals involve in, hydrometallergy, , O, Fe Fe, Mg, , C C, O, , M gO, , Pb, PbO, , O, Ca Ca, , T1, Temperature, , Column-II, , 1, , 0, , G0, , Column (II) (electrolyte), (P) Cu, (Q) fused (Al2O3 + Na3AlF6 + CaF2), (R) Brine solution, , Column-I, , (+) ve, , (–)ve, , INORGANIC CHEMISTRY, , S Au, , ANSWER KEY, , E, , Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 2, , 2, , 4, , 2, , 2, , 4, , 4, , 3, , 4, , 2, , 2, , 4, , 3, , 2, , 3, , Que., , 16, , 17, , 18, , 19, , 20, , 21, , 22, , 23, , 24, , Ans, , 4, , 2, , 3, , 1, , 3, , 2, , 2, , 4, , 1, , Que., , 26, , Ans, , 1-Q,R, 2-P,S, 3-P,S, 4-P,S, , Your Target is to secure Good Rank in Pre-Medical 2021, , 25, R;, , P, , Q, , 37

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , PERIODIC TABLE, 2., , Till 7th period = 118 element (total magic no., add n ), , 0.65 ( ), , 21., , 8th period = 59, , Na, x, , Zeff, , Mg, x+0.65 constant, Ca, [x+0.65], , 9th period = 50 next magic no., 10th period = 72, Total 290, 3., , 4, , 5 th, th, , 7, , th, , Li+ & Mg2+ [ due to diagonal relationship], , 32., , Atomic Number 78, , IIIB IVB VB, 21 22 23, , th, , 6, , 29., , A, , Sc ____30 Zn, , 3d e– –––––10, , Y––––– 48 Cd, , 4d e ––––––10, , C, , 21 18, 39, 57 18, , 23 18, 41, 73 32, 105 32, , 22 18, 40, 72 32, , 34., , (i) N > F (ii) Cl– > Cl (iii) O < S (iv) Fe+2 > Fe+3, , 37., , Ge > Br > C > F, , 40., , (i) S, 3P, , 4e, , —, , 4e, , —, , —, , —, , 4e 4e 4e, , e, , 2, , 3s 3p, , ns, n, , n 2 f, , 6 6s 4f, , 6p, , (iv) B, , (iii) 2nd T.s. = Y–Cd, (iv) O–2 =, , 1s 2 2s2 2p6, 2e 8e, , 41., , 3d T.s. = 10 elements (21 to 30), , 9., , Lanthanum belongs to d block, , 10., , 6th period all elements contain 4d electrons, because in 6d electron filled in 5d subshell., 4s, , 11., , 3d, , IE1, , 2e, 2p6, , IE 3, , 2s 2p, e, , IE1, , 2s2, , 2s2 2p1, , IE 2, , 1, , Order of IE, Si, < P, < S, < Cl, 2, 2, 2, 3, 2, 4, 3s 3p 3s 3p 3s 3p, 3s23p5, Cl, , 1256, , P, , 1012, , S, , 999, , Si, , 786, e, IE 1, , 1s2 ,2s2 2p6, noble gas e, configuration, (most stable), , 44., , 1s2, 2s2, 2p6, 3s1, , 45., , IE I IE II IE III IE IV IE V IE VI IE VII, , IV period :, no. of orbital = 9, , 940, , (one orbital occupy 3electron), then no. of elements = 9 × 3 = 27, HS, , 4P, , Mg, 3s 2, , C, 2s2 2p2, e, , 2, , 8., , IE 2, , (iii) Al Ga, (size almost same due to transition contraction), Al < Ga (IE), , n 1 d np, 5d, , 3, , 2e, 3s 2 3p1, , (i) Group number of noble gas = zero group, (ii), , 3p 4, , (ii) P, , —, , If element can have four value of spin quantum, number so one orbital can contain 4 electrons., 7., , Cl, 3P 5 IE1, e, , 4, , 3p3, , A = 40, B = 57, C = 105, 4., , 5d e ––––––10, , La ––––– 80 Hg, , B, , 2080, , 3090, , 4140, , 7030, , 7870, , 16000, , e, IE2, , IE VIII, 9500, , so valence electron is 6 thus it belongs to gr. 16, , Your Target is to secure Good Rank in Pre-Medical 2021, , 1

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TARGET : PRE-MEDICAL 2021, 46., , Mg, , e, IE1, , e, IEII, , Mg, , M ( g2), , 2e, , Mg, , M( g ), , e, , Mg, , 68., , M(g)2, , INORGANIC CHEMISTRY, , Order of E.A., 2, , 1s 2s 2 2p6 3s 2 3p5 > 1s 2 2s 2 2p5 >1s2 2s2 2p6 3s1 > 1s2 2s2 2p3, Cl, , M, , 2, (g), , or M, , 2, , 70., , e, , P, , e, , 300, large jump, large jump, , R 118, S 176, T, , 56., , 497, , IE III, , 549, , 920, , 734, , 1100, , e, , 1, , 1 IA, , 1091, 347, , 1652, 848, , e, e, , 1, , 1 IA, 2 IIA, , 1500, , (Non metal), , large jump, , 947, , B, , C, , 2s2 2p1, , N, , 2s2 2p2, , Non metal, , 2, , O, , 2s2 2p 3, , C, , 8.3, , 11.3, , O, , 13.6, , N, , 14.5, , 60., , Atomic number of inert gas = Z, Second highest IE in a period = halogens (Z–1), , 61., , Na1, 3s, , Al, 2, 1, , 3s 3p, , Mg, , 786, , 737, , Al, , 575, , Na, 496, , 62., , Sequential order : Na > Mg > Be > Si > P, , 64., , IPI IPII IPIII IPIV, 14.3, , 34.5, , Cl, , IP EA, Kcal mole 1 ; X P, 125, , 76., , XP, , 95., , (a) Energy released, (P) S g, , S, , 275 86, 125, , (S) N, , g, , 2.8, , N, , (electron removal is an exothermic process, because electron addition is an endothermic, process in this option), (b)Energy obserbed, O2 (inter electronic repulsion), , (R) Sr Sr 2 (electron removal process of IP), (c) Inert gas configuration, O2 ; (R) Sr, 2p 6, 5s2, , (Q) O, 2p5, , Sr2, 4p6, , (d)Half filled configuration, , Si, , Sequential order, , 7.1, , E.A., , Si, 2, 2, , 3s 3p, , 3s2, , Process (II), , (Q) O, , 2s2 2p 4, , B, , Sequential order, , Mg, , —, , Cl, , [I.E. of process (II) = E.A. pf Process (I)], , IE II, , Q 99, , N, , Process (I), , 48 to 53, IE1, , Na, , Half filled, stability &, small size, , M(g), M, , F, , (S) N, 2P, , (T) Ge, , N, 4, , 2P, , 3, , P, , 2, , Ge, P3, , IP, , V, 162.2, , 46.8, , sudden large jump, , Valence electron for this element =4, [Ne] 3s23p 2, Si=, , 14, , sudden large jump, , 66., , (i) IE I Mg, 3s2, , (ii) IE I Na, 3s, 1, , (iii) IE2 Mg, 3s1, , Al, , penetration power, , 3s2 3p1, , Mg, , Zeff, , 3s2, , Na6, 2p, , inert gas, configuration, , 2, (iv) IE 3 Mg, 2, , Na12, 3s, , inert, gas, conf r, , 2, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 31., , I3– = sp3d, , 61., , (i) O = C = O (linear), , I, , :, , I, , :, , :, , Si, , bp =2, lp =3, , Si, , N C–C C–C N, , BCl4—, , ICl4—, , sp3, , sp3d2, , lp=0, , lp=2, , tetrahedral, , square planar, , 63., , Si, , SiF4, , F, , F, , 64., , sp3, F, , all bond lengths are equal, 38., , 42., , S, S, , S8 : S, , S, S, , S, S, , S, , oxidation state = 0, covalency =2, , 67., , All bond length in sp3d hybridisation are not, same., , 68., , Cl, , 51., , (I), , 1,3,5-trichlorobenzene, Cl, , 69., , Cl, , Cl, , O, O, , Si, , O, O, , Si, , 70., , X, O, , 71., , Cl, , 73., 75., , Cl, , S, , :, , X, , O, , Two-P -d, One P -P, , O, , 1,2,3,4-tetrachloro benzene, Cl, Cl, , 1, size of orbital, , X, M, , 4-B.P., 1-l.p., , Cl, Cl, , directional character, , In 'S' atom,, G.S. = no. of unpaired e– =2, (E.S)I = no. of unpaired e– =4, (E.S)II = no. of unpaired e– =6, In 'I' atom, G.S. = no. of unpaired e– =1, (E.S)I = no. of unpaired e– =3, (E.S)II = no. of unpaired e– =5, (E.S)III = no. of unpaired e– =7, Boron atom cannot form compound in ground, state, (i) ClO4– = sp3, ; ClO2–= sp3, (ii) SF4 = sp3d, ; CCl4=sp3, (iii) BF3 = sp3, ; NF3 = sp3, (iv) CO2 = SP, ; SO2 = sp2, In sp3d hybridisation s, px, py, pz and dz2 orbital, involved., X, , 1,2,4-trichlorobenzene, , (III), , sp3, , Si, , (iii) T I3 T + + I3–, Extent of overlapping, , Cl, , (II), , O, , Extent of overlapping, , F, , 34., , Si, , (Tetrahedral), , [four carbon atoms present linearly], 33., , O, , O, , I, , 32., , INORGANIC CHEMISTRY, , H2O+H+ H3O+ H O H5O2+ H O H7O3+, H-bond strength E.N. of atm, H-bond strength, In HF ---HF < F–---H–F, 2, , 2, , P-dichloro benzene, , (IV), Cl, , 76., , Dipolemnt moment order = III > II > I = IV, , symmetrical H-bond, KCl + H2O ion-dipole attraction, H3 C, , C, , CH3+CH3, , C, , N, , O, , dipole-dipole attraction, HCl + Cl2 dipole induced dipole attraction, 4, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , INORGANIC CHEMISTRY, , p-BLOCK, 2., , Si, , O, , 10., , > C–O (bond length), , back bonding, , Sodium dihydrogen, Na 2 H 2 P 2 O 7, O, , .., O, .., , H3C, , >, , CH3, , Back bonding is, not possible due to, absence of, vacant orbital, , .., O, .., , H3Si, , Na, , O, , Back Bonding, possible., (electron density, dispersed), , 11., , O, , P, OH, , O, , O, , S, , (Lonepair donation, possible easily), , O, , S, , OH, , So work as more, Lewis base, , (ii) HO, , (Lewis base strength), , O, , OH, , (i) H O, , -, , O, , P, , SiH3, , pyrophosphate, , Na, , O, , H, , OH, , O, , O, , S, , S, , OH, , O, H3C, , (iii), , H3C C, H3C, , .., O, .. H, , H3C, <, , H3C Si, H3C, , (Back bonding, not possible), , O, , H (acidic, nature), , O, , (iii) H, , (Back bonding possible), So conjugated is more, stable thus more, acidic in nature, , 3., , (i) N(SiH3)3, , N(Me)3, , Back bonding, , Back bonding, , is possible, , P, , O, , (iv) H4P2O6 : HO, , 12., , H2SO5 : HO, , O, , O, , H2S2O6 : HO, 19., , O, , Cl, O, , 8, , I2, , S, , S, , O, , O, , O, , O, , S, , S, , O, , O, , H, , OH, , Na2 S4O6, , bond =3, , No. of bond =2, , No. of, , PCl5 + H, , O, , [per oxi linkage absent], , S, O, , 22., , bond =4, , NaI, , sodium tetrahionate, , H, O, , OH No. of, , O, , O, , Per chloric acid – HClO4, O, , Na2 S2O 3, , O, , 21., 7., , OH, , O, , Back bonding possible so all, bond lengths are equal and, less than expected bond length, , S, , P, , O, , S, , H3Si H Si H3Si, 3, , O, , P, , O, , N, , S, , O, , O, , .., , O, , O, , O, , H2S2O5 : HO, , linear, , (iii), , P OH, , OH OH, , (pyramidal), , (ii) H3C–N=C=O back bonding not possible (bent), H3 Si–N=C=O back bonding present so shape is, , O, , O, , is not possible, , (planar), , 5., , O, , O, O, , H, , Cl, , S, , Cl, , O, (SO2Cl2), , When KI added into I 2 , KI 3 formed and, solubility of KI increase., , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 54., , order of bond energy - Cl2 > Br2 > F2 > I2, , 55., , In solid state, SO3 form trimer (S3O9), O, , O, O, O, , S, O, , INORGANIC CHEMISTRY, , S, , O, , O, S, , O, O, , 61., , H 2 SO 4 less volatile due to presence of Hbonding, , 62., , (i) Si+4 < Sn+4 < Pb+4 [due to inert pair effect], (ii) size of halogen ( ), = polarisiation ( ), = ionic character ( ), (iv) Liquification of nobel gases increases down, the group, due to increasing in London force., , 10, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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ORGANIC CHEMISTRY, , Race, No., , TOPIC NAME CONTENTS, , Page, No., , 01, , IUPAC SYSTEM, , 1, , 02, , STRUCTURAL ISOMERISM, , 3, , 03, , GEOMETRICAL ISOMERISM, , 5, , 04, , OPTICAL ISOMERISM, , 7, , 05, , ISOMERISM (COMPLETE), , 9, , 06, , ELECTRONIC DISPLACEMENT, , 11, , 07, , REACTION MECHANISM ( PART-II ), , 15, , 08, , REACTION MECHANISM ( PART-II ), , 17, , 09, , REACTION MECHANISM ( PART-II ), , 21, , 10, , HYDROCARBON, , 23, , 11, , HALOGEN, OXYGEN & NITROGEN, , 25, , CONTAINING COMPOUNDS, 12, , BASED ON CONVERSIONS, , 28, , 13, , NCERT CONVERSIONS, , 31, , 14, , NCERT CONVERSIONS, , 33

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , STRUCTURAL ISOMERISM, 1., , RACE # 02, , Isomerism shown by the following compounds, , 5., , O, –C–O–, , (1) 2, C=C, H, , H, Cl, , 6., , (3) 4, , (4) 6, , How many amines are possible with the molecular, formula C4H11N (structural isomers only) :(1) 6, , (2) 7, , (3) 8, , (4) 9, , is :-, , –C–O–, , 7., , C=C, H, , H, , (2) 3, , &, , O, Cl, , Number of structural isomers possible for, dibromoderivative of an alkene with molar, mass 186 gm mol–1 is (atomic mass of Br = 80), , How many benzenoid isomers are possible for, M.F. C7H8O :(1) 3, , (2) 4, , (3) 5, , (4) 6, , (1) Functional group isomerism, (2) Geometrical isomerism, , 8., , (3) Metamerism, (4) Position isomerism, , How many total structural isomers of 3° amines, are possible with the molecular formula, C 6 H 15 N, (1) 4, , 2., , How many structural isomers are possible when, one H-atom of anthracene is replaced by, chlorine :(1) 3, , (2) 7, , Br, , (3) 4, , (4) 6, , 3., , and, , are :Br, , Br, , (1) Chain isomers, , Me, , OH, , Only two isomeric monochloro derivatives are, possible for (excluding stereo) :(1) n-Butane, , (2) 2,2-Dimethylpentane, , (3) Benzene, , (4) Neopentane, , Me, , How many alkenes (only structural isomers), are possible with the molecular formula C4H8, (1) 4, , (2) 3, , (3) 5, , Me, , (4) 6, , Which of the following is correct :(1), , O, , O, ,, , H, Functional group isomers, , Me, , Me, , O–Me, , 11., , (2), OH, , ;, Position isomers, , O–Et, , O, , O, (I), , (4) 5, , (2) Geometrical isomers, , Which of the following is not the correct, relationship :, Me, , 10., , COOH, , (3) Functional isomers(4) Position isomers, 4., , (3) 6, , COOH Br, , COOH, , HOOC, , 9., , (2) 7, , (II), , (III), , (1) I and IV are positional isomers, (2) I and II are functional isomers, (3) I and III are chain isomers, , (IV), , (3), , ;, NH2 H2N, , H, , Position and functional group isomers, (4) All of these, , (4) II & IV are metamers, E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 3

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TARGET : PRE-MEDICAL 2021, 12., , Minimum C-atom required for aliphatic, 2° amine to show chain isomerism are :(1) 4, (2) 6, (3) 3, (4) 5, , ORGANIC CHEMISTRY, , iii. CH3CH2CH2CHCH3 and CH3CH2CHCH2CH3, COOH, , COOH, O, , 13., , Isomerism shown by, O, –S–O–, , –Me & Me–, , O, , (1), (2), (3), (4), 14., , 15., , 16., , O, , iv., , O, , O, , and, , O, , –S–O–, O, , 17., , Chain isomerism, Positional isomerism, Metamerism, Functional group isomerism, , What is relation between following compounds, CH3 CH2 CH CH2 CHO & CH3 CH CH2 CH2 CHO, CN, , CN, , Branched chain isomer of a hydrocarbon, having molecular mass 72u gives only one, isomeric alkyl halide after monosubstitution., The hydrocarbon is :(1) neohexane, (2) t-butyl chloride, (3) neopentane, (4) isooctane, How many structural isomers are possible of, C5H12O :(1) 5, (2) 8, (3) 13, (4) 14, , 18., , (1) positional isomers (2) chain isomers, (3) optical isomers, (4) metamers, No. of structural isomeric alkenes (molecular, formula=C 6 H12 ) which all give n-hexane on, hydrogenation in presence of metal catalyst, , 19., , (1) 2, (2) 3, (3) 4, (4) 5, How many isomeric geminal dihalides are, possible for the compound having M.F. C3H6Cl2, , 20., , (1) 1, , (2) 2, , (3) 3, , (4) 4, , Which is the metamer of the compound P ?, , Find out relation between the following, compounds:, COOH, , O, O, , i., , and, , CH3, (1), O, , O, Cl, , ii., , OH, , (2) H C, 3, , OH, , CH 2CH 3, , C–Cl, , CH2CH3, , and, , OH, , (3), , (4), , ANSWER KEY, , 4, , Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , Ans, , 3, , 1, , 4, , 1, , 1, , 3, , 3, , 2, , 1, , 2, , Que., , 11, , 12, , 13, , 14, , 15, , 16, , Ans, , 2, , 4, , 3, , 3, , 4, , (i) F.G.I. (ii) F.G.I. (iii) C.I. (iv) F.G.I., , Que., Ans, , 17, 2, , 18, 2, , 19, 2, , 20, 4, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , GEOMETRICAL ISOMERISM, 1., , 2., , 3., , Which of the following compound have, minimum dipole moment :, (1) CH3 –CH2 –C CH, (2) CH3–C C–CH3, (3) CH3–CH=CH2, (4) CH3–C CH, , The compound CH3–C–Cl is :I–C–Br, , 7., , (1) trans, (2) cis, (3) Z, (4) E, How many geometrical isomers are possible for, the given compound, , Br, Cl, , (1), , CH3, C=C, H, , (2), , Cl, CH 3, C=C, Br, H, , (3), , Cl, CH3, C=C, Br, H, , (4), , H, CH3, C=C, CH3, H, , (1) 2, 8., , C=C, , CCl3, , H, , (1), (2), (3), (4), , C=C, , CCl3, , H, , Boiling, point, I > II, II > I, I > II, II > I, , Melting, point, II > I, II > I, I > II, I > II, , H, , Stability, I > II, II > I, I > II, I > II, , In which compound cis-trans nomenclature, cannot be used :, (1) CH3–CH=CH–COOH, (2) C6H5–CH=CH–C6H5, (3) C6H5–CH=CHD, (4) C6H5–CH=C, , CH3, Cl, , Cl, (1) 0, 9., , E, , CN, (2) E, E, (4) Z,Z, , Cl, , (2) 1, , (3) 2, , (4) 3, , Which of the following compounds can show, geometrical isomerism :, (i), Pent-3-en-1-yne, (ii) Acetaldoxime, (iii) Pent-1-ene, (iv) 1-chloropropene, (v) 2-Methylbut-2-ene, (vi) But-2-yne, (vii) 2-chlorobutane, (viii) Butenyne, (ix) CH3 – CH = CH – CH3, Cl, , (x), , Cl, C, , C, H, , H, , H, , COOH, , COOH, , (xi), , COOH, CH2OH, , (1) E, (3) E,Z, , (4) 8, , How many geometrical isomers are possible for, , H, , Assign configuration to the following, , CN, H 2N–H 2C, , (3) 6, , CCl3, , (II), , (I), , Dipole, moment, I > II, II > I, I > II, II > I, , (2) 4, , Cl, , Which is true for the following isomeric forms, I & II respectively :, H, , 5., , 6., , Which one of the following is a Z isomer ?, , CCl3, , 4., , RACE # 03, , (xii), , Your Target is to secure Good Rank in Pre-Medical 2021, , 5

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TARGET : PRE-MEDICAL 2021, 10., , Assign the configuration E/Z to the following, compounds., , 11., , Which of the following compounds have zero, dipole moment., (i), CCl4, , CH3, , H2N, C, , (i), , (ii), , CH3, H, , C, Cl, , NO2, , (iii), OCH3, , H2N, , ORGANIC CHEMISTRY, , H, C2H5, , C=C, , Cl, C=C, H, , H, Cl, , C, , (ii), , (iv) Cl, , C, HS-CH2, , Cl, , F, , 12., , C, , (iii), , Compare dipole moment of the following, , C, H, , (a) (i), , D, 14, , C, , 14, , MeO, , 13., , CH3, CH3, , C 2 H5, H3C, HC CH2, H3C, , C, , 14., , CH2-Cl, C, , I, , C, , D3C CH2, , CH2–CH3, , 15., F, , Br, Cl, , C, , (vii), , C, , H, , C=C, , (ii), , CH3, , H, Cl, F, , (ii), , C=C, , Cl, H, , C=C, , H, , (2), , (3) HO–N=N–OH, (4) (CH3)2 C=NOH, According to CIP sequence rules the correct, order of priority for the given groups is, (1) –COOH > –CH2OH > –OH > –CHO, (2) –COOH > –CHO > –CH2OH> –OH, (3) –OH > –CH2OH > –CHO> –COOH, (4) –OH > –COOH > –CHO> –CH2 OH, GI is shown by :, , CH(CH3)2, , F, H2C CH, , Cl, , (1) CH3 CH=NOH, , C, , (vi), , H, , C=C, , H, CH3, H, (c) (i) CH3–CH2–C CH (ii) CH3–C C–CH3, Which will not show G.I. ?, , C, , (iv), , Cl, , F, (b) (i), H, , CH3, , H3C, , (v), , Cl, , F, , (1), , Cl, , (2) CH3CH=C=CHCH3, OHC, C, , (viii), , CH2–OH, , (3), , C, NC, , C–OH, , (4) CH 3CH=C=C=CH2, , O, , ANSWER KEY, Que., , 1, , Ans, , 2, , 2, , 3, , 1, 4, 10, Que., Ans Z-i,ii, iii,- E- iv, v, vi, vii, viii, , 6, , 4, , 5, , 6, , 4, , 2, , 4, , 11, i & iii, iv, , 7, , 9, , 8, , 1, 3, 12, (a) i > ii (b) i < ii (c) i > ii, , Your Target is to secure Good Rank in Pre-Medical 2021, , i, ii, iv, ix, x, xi, xii, 13, 4, , 14, 4, , 15, 1, , E

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , OPTICAL ISOMERISM, 1., , RACE # 04, , Match Column - I with Column - II and select, the correct answer using the codes given below:, Column - I, (A) Meso, , 4., , Column - I, , Column - II, , (A) Constitutional, , (P) An equimolar, , compound, , Match Column - I with Column - II and select, the correct answer using the codes given below :, , mixture of, , Column - II, (P) Stereoisomers that, are not mirror, image isomer, , enantiomers, (B) Enantiomers, , (B) Stereoisomers, , (Q) Stereoisomers that, , (Q) Isomers that have, , are not mirror, , same constitution, , images, , but differ in the, , (C) Diastereomers, , (R) Non superimposable, mirror image, , (D) Racemates, (Racemic, mixture), , (S) An optically inactive, compound whose, molecule is achiral, , arrangement of their, atoms in space, (C) Enantiomers, , (R) Isomers that differ, in the order in which, their atoms are, , even though they, , connected, , contain chiral, , (D) Diastereoisomers (S) Stereoisomers that, , centres, , 2., , (1) A-S, B-R, C-Q, D-P, , object and its non, , (2) A-S, B-R, C-P, D-Q, , superimposable, , (3) A-R, B-S, C-Q, D-P, , mirror image, , (4) A-R, B-S, C-P, D-Q, , (1) A-P, B-Q, C-S, D-R, , The correct absolute configuration assigned for, compound (I) and (II) respectively is :, , (2) A-P, B-Q, C-R, D-S, , COOH, (I) H—–—NH2, , (1) R, R, , 5., , CH 2SH, , (2) R, S, , (3) S, S, , (4) S, R, , Which of the following cyclopentane, derivative is optically inactive ?, , (1), , OH, , H, , H, , OH, , (2), , OH, , (3), , CH3, , CH3, , H, , H, , H, , (4), , H, , HO, , OH, CH3, H, , The following structures respresent a pair of:, CH3, (I) H—–—Cl, Br, , Cl, (II) Br—–—CH3, , (1) enantiomers, , (2) diastereomers, , H, , (3) meso compounds (4) homomers, , 6., H, , E, , (3) A-R, B-Q, C-S, D-P, (4) A-R, B-Q, C-P, D-S, , COOH, (II) H—–—NH2, , CH3, , 3., , are related as an, , CH3, H—–—OH, Br—–—H, C2H5, , H, HO—–—CH3, H—–—C2H5, Br, , The molecules represented by the above two, structures are :, (1) identical, , (2) enantiomers, , (3) diastereomers, , (4) epimers, , Your Target is to secure Good Rank in Pre-Medical 2021, , 7

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TARGET : PRE-MEDICAL 2021, 7., , How many chiral centres are present in the, following compound :-, , 11., , ORGANIC CHEMISTRY, , Which has R-configuration, H, , O, , (1) CH3CH2, , Br, , O, , CH=CH2, , Cl, Me, (1) 4, 8., , CH=CH2, , (2) 5, , (3) 6, , CH2CH3, , (3), , Cl, , CH3, , H, , H, CH3, , (4), , H, CH2CH3, (4) CH2=CH, , Cl, H, , CH3, Cl, , 12., , CH3, , HS, SH, & H, H, , H, Cl, , In which of the following compound have, plane of symmetry ?, , CH3, CH3, are :C2H5, , Br, , (3), , (4), Cl, , Configurations of the two centres in the, following molecule are :, , C, I, , H, Cl, , Which of the following compound will not, show optical isomerism, CH3, , CH3, , COOH, Br, CN, OH, , Cl, , CH3, Cl, , 13., , (1) (2R, 3S), (3) (2S, 3S), , Cl, (2), , CH3, , Identical, Enantiomers, Diastereomers, Positional isomers, , H, H, , CH3, , (1), , Cl, , C2H5, , H, Br, , H, , CH3, , CH=CH2, , CH 3, CH 3, , Cl, , Cl, , (1), (2), (3), (4), , (3) Br, , H, (2), H, , Cl, CH3, , Cl, H, , CH2CH3, , Cl, , CH3, , 10., , H, , Which of the following structure does not, represent meso isomer :H, (1), H, , 9, , (2) Br, , (4) 7, , (1), , (2), , CH3, , CH3, , CH3, , (2) (2R, 3R), (4) (2S, 3R), , (3), , (4) all of these, CH3, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , Ans, , 1, , 2, , 3, , 3, , 4, , 1, , 3, , 1, , 1, , 1, , 1, , 1, , 2, , 8, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , ISOMERISM (COMPLETE), 1., , RACE # 05, , Which of the following is optically active :-, , 5., , Which of the following statements is true :-, , (1) 1,1–Dibromo-1-chloro propane, , (1) Racemic mixture is a resolvable mixture, , (2) 1,3-Dibromo-1-chloropropane, , (2) Meso isomer is optically inactive due to, internal compensation, , (3) 1,1-Dibromo-3-chloro propane, (4) 1,3-Dibromo-2-chloropropane, 2., , (3) Racemic mixture is optically inactive due, to external compensation, , Which is the highest energy conformation of, butane :-, , (4) All, 6., , Me, , (1), , unsymmetrical compound having 'n' no. of, , Me, , H, , chiral C-atoms :-, , (2), , (1) 2n–1, H, , H, , H, , 7., , Me, H, , (3) 2n/2, , (4) 2(n–1)/2, , O–CH 2–CH3, CH3, , ;, , O–CH3, C2H5, , Metamers, , (4), H, , Me, , H, , (2), 3., , (2) 2n, , Which of the following is incorrectly matched:-, , (1), , H, , (3), , How many racemic mixture are possible for an, , O–H, CH3, , Which conformer of the given compound is, most stable (rotation about C–C bond) :-, , CH2OH, ;, , Functional group isomers, , CH3, , HO–CH 2 –CH 2 –NO 2, (3), , (1) Staggered, , ;, , Chain isomers, , (2) Gauche, (3) Fully eclipsed, , (4) CH3–CH2, , ;, , CH2–CH3, , Metamers, , (4) Partially eclipsed, 4., , (1) Compound having chiral–C essentially, shows optical isomerism, (2) Compound having one chiral–C can not, have meso isomer, (3) Chiral molecule may or may not have, chiral–C, , CH2–CH2–CH3, , CH3, , Which of the following statement is true :8., , Sum of X, Y and Z is :(a) C4 H8 O, , No. of aldehydes = X, , (b) C5 H12, , No. of chain isomers=Y, , (c) C4H 8, , Maximum no. of alkenes=Z, , (1) 10, , (2) 7, , (3) 9, , (4) 8, , (4) All, E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 9

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TARGET : PRE-MEDICAL 2021, 9., , Which of the following is false for the given, molecules :CHO, H, , OH, , OH H, , CHO, CHO HO, , CH3, , (II), , C, , 11., , (4) All of these, , 13., , Number of stereoisomers of the given, compound is, , CH3 CH CH CH CH3, OH, 14., , (1) 2, (2) 3, (3) 4, (4) 6, Which of the following can show both, tautomerism and optical isomerism, O, OH, , (1), C, , C, , Me, O, , O, , (3), , CH3, Cl, , 15., , Cl, , Cl, H, , (2), , CH3, CH3, , Cl, , (3), , (4), , (3), , Cl, Cl, , Cl, (2), , (2), , (III), , Which of the following compounds can show, geometrical isomerism :(1), , (1), , H, , (1) Equimolecular mixture of I and II does not, show optical activity, (2) II and III have different behaviour towards, PPL, (3) II & III are identical, (4) I & II can not be separated by fractional, distillation method from their mixture., 10., , Which one of following isomer is meso :-, , CH3, , CH3, , (I), , 12., , ORGANIC CHEMISTRY, , (4), O, Which of the following compound can not, show tautomerism ?, (1), , C, , H, Which of following compound is chiral, , (2) CH 2=CH–OH, , CH3, Cl, Cl, , H, (2) H, , (1), , (3), , CH3, CH3, , Cl, (3), , (4), , (4), , Cl, Cl, , CH3, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 2, , 1, , 2, , 4, , 4, , 1, , 4, , 3, , 3, , 2, , 1, , 1, , 3, , 2, , 4, , 10, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 11., , HOOC, COOH ; HOOC, , (iii), (I), , Identify more stable canonical structure :, , (II), , O2 N, , (1), , H, , C, , F, (II), , 7., , 8., , 9., , 10., , (A), , (C), , (B), , CH2, , C, , (4) CH3, 12., , N, ••, , O, , (D), , CH3, , C, , O, , Acetic acid is considered as resonance hybrid, O, , O, , O, , CH3–C–O–H, (I), , CH3–C=O–H, (II), , CH3–C–O, –H, ••, (III), , 13., , ••, , NH2, , NH3, , (1), 14., , O, , ••, , CH3–C–O–H, (IV), , Which of the following order is correct for the, stability of four contributing structure :, (1) I > II > III > IV, (2) I > II > IV > III, (3) I > III > II > IV, (4) I > IV > III > II, In which of the following molecule group present, on ring is not involved in resonance :, , (2), , Cl, , OH, , (3), , (4), , In each of the following pairs of ions which ion, is more stable :, (i), , (I) C6H5 – CH2 and (II) CH2, , (ii), , (I) CH3 – CH2 and (II) CH2, , (iii), , (I), , (iv), , (I) CH –C–CH, 3, 3, , CH – CH 2, , CH, , ••, , N, H, , N, ••, , OH, , CH2=C=CH, , CH2, , COOH, , Which among the given acid has lowest pKa value, (1) Chloroacetic acid, (2) Bromoacetic acid, (3) Nitroacetic acid, (4) Cyanoacetic acid, Arrange the compounds in order of decreasing, acidity :, (I) ClCH2 – CH2 – OH, (II) Cl2CH – CH2 – OH, (III) Cl – CH2 – CH2 – CH2 – OH, (IV) CH 3 – CH2 – CH2 – OH, (1) I > II > III > IV, (2) IV > III > II > I, (3) II > I > IV > III, (4) II > I > III > IV, Consider the given compounds :, (1) CH3 – CH2 – NH2 (2) CH 3 – CH = NH, (3) CH 3 – C N, (4) C2H5 – NH – C2H5, Arrange basicity of these compounds in, decreasing order :, (1) 4 > 1 > 2 > 3, (2) 1 > 2 > 3 > 4, (3) 1 > 4 > 2 > 3, (4) 4 > 1 > 3 > 2, In which of the following cases lone-pair is, involved in resonance :, , C, , (3), , COOH, , HOOC, (III), , H, , OH, , (2) CH2–C CH, , COOH ;, , (I), , O, , O, , COOH, , HOOC –COOH, (III), (iv), , ORGANIC CHEMISTRY, , CH2, , CH2, , and (II), , ••, , N, H, , CH3–CH–CH3, , ••, , (E) CH2=CH–CH=NH, , and (II), , CH3–N–CH3, CH3–C–CH3, , ••, , (F) CH2=CH–O–CH=CH, 2, ••, , 15., , (G) CH2=CH–C N:, CH2, , (H), , 12, , ••, , O, ••, , Among the following compounds, the strongest, base is :, O, , (I), , ••, , O, ••, , NH, , (1) NH2–C–NH2, , (2) NH2–C–NH2, , (3) C6H5–NH2, , (4) CH3–NH–CH3, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 16., , The correct order of decreasing basic strengths of, x, y and z is :, (x), , (z), , (y), NH, , 21., , N–H, , N, , (2), , (1) x > y > z, (2) x > z > y, (3) y > x > z, (4) y > z > x, Consider the following compounds :, , ;, , (1), , (2), , NH2, , (4), , ;, NO2, , 22., , Compare C–C bond rotation in the following, molecules :-, , NH2, , ;, , (4), , CHO, , 18., , (3), , NH2, , NH2, , (3), , Which of the following is non-aromatic :, (1), , O, , 17., , ORGANIC CHEMISTRY, , CH3, , (1), , (2), , (3), , (4), , (II), , (I), , Arrange these compounds in decreasing order, of their basicity :, (1) 1 > 2 > 3 > 4, (2) 2 > 3 > 1 > 4, (3) 4 > 1 > 3 > 2, (4) 4 > 1 > 2 > 3, Which shows aromatic character :, 23., , (1) I > II, (2) II > I, (3) I = II, (4) can not be compared, What is the order of indicated bond length for, the following set of molecules :, O, , 19., , (a), , Among the following the aromatic compound is, (1), , (2), , (3), , (4), , O, , (I), , (II), , OH, , O, , NH2, , NH2, , 20., , Which of the following is anti-aromatic, species :, , (b) (I), , N, , (II), CHO, , (2), , (1), , :, , S, , NH2, , (III), (3), E, , (C–O bond), , (IV), , (III), , (IV) CH2=NH (C–N bond), , (4), , Your Target is to secure Good Rank in Pre-Medical 2021, , 13

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TARGET : PRE-MEDICAL 2021, 24., , Product (A) will be :HOOC, , ORGANIC CHEMISTRY, , HOOC, OH, , OH, 2Moles NaNH2, , O2N, , (4), , A, , O2N, , CH, , C, , COOH, , COO, , HOOC, , 25., , O, , Which of the following represents the correct, order of stability of the given carbocations ?, , (1), , CH2, , O2N, CH, COO, , I, OOC, , (1) III > I > II, (3) III > II > I, , OH, , (2), , 26., , O2N, , III, (2) I > III > II, (4) II > III > I, , Which of the following group has maximum, hyperconjugation effect but minimum inductive, effect, (1) –CH3, (2) –CH2–CH3, (3) –CD3, , C, COOH, OOC, OH, , (3), , II, , (4), O2N, , CH3, C CH3, CH3, , CH, COO, , ANSWER KEY, Que., , 1, , 2, , 3, , Ans, , 3, , 1, , I > II > IV > III, , 5, , 4, , (i) I > II > IV > III, , (i) III > II > I (ii) I > II > III, , Que., , 6, , 7, , 8, , 9, , Ans, , (i) I > II > III > IV (ii) I > II > III (iii) III > II > I (iv) I > III > II, , 3, , 4, , 1, , Que., , 10, , 11, , 12, , 13, , Ans, , B,D,F,I, , (1) I > II (2) II > I (3) I > II (4) II > I, , 1, , 2, , Que., , 14, , 15, , 16, , 17, , 18, , 19, , Ans, , (i) I > II (ii) I > II (iii) II > I (iv) II > I, , 2, , 2, , 3, , 2, , 1, , Que., , 20, , 21, , 22, , 23, , 24, , 25, , 26, , Ans, , 4, , 2, , 1, , (a) IV > I > II > III (b) III > II > I > IV, , 3, , 1, , 1, , 14, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 11., , Which carbonyl group of the given compound, is most reactive for hydration :-, , ORGANIC CHEMISTRY, , CH2–CH=CH–CH3, NBS, , 15., , (A) ., Major, , I, , 12., , (1) 3, (2) 1, (3) 2, (4) All have equal reactivity, Select the chain propagation steps in the free, radical chlorination of methane :., (a) Cl2, 2Cl, ., ., (b) Cl+CH4, CH3Cl+H, ., ., (c) Cl+CH4, CH3+HCl, ., ., (d) H+Cl 2, HCl+Cl, ., ., (e) CH3+Cl 2, CH3–Cl+Cl, , Compound (A) is :, (1) Ph–CH2–CH=CH–CH2Br, Br, , (2) Ph–CH–CH=CH–CH3, (3) Ph–CH2–CH 2–CH–CH 3, , Br, (4) Ph–CH2–CH–CH2–CH3, , Br, 16., , (1) b, c, e, , Match column-I and column-II and select the, answer :, Column-I, , (2) a, c, e, , Column-II, , (a) CH3 –CH=CH2, , ?, , C H 3 –C H – C H 3 (p) HBr followed, , (3) c, e, , Br, , (4) b, c, d, 13., , A hydrocarbon X(V.D.=35) forms only one, monochloro substitution product, X is :-, , (b) CH3 –CH=CH2, , ?, , CH 2–CH=CH2 (q) Br2 /CCl4, Br, , (1) Neopentane, , Br, , (2) Cyclopentane, , (c) CH3 –CH=CH2, , ?, , C H 3 – C H – C H 2 (r) NBS, , (3) Pent-1-ene, , Br, , (4) n-pentane, 14., , by hydrolysis, , Toluene reacts with Cl2 in the presence of light, , (d) CH3 –CH=CH2, , ?, , C H 3 – C H – C H 3 (s) HBr, OH, , to give :–, , (1) (a-s), (b-r), (c-q), (d-p), , (1) Benzyl chloride, , (2) (a-p), (b-r), (c-q), (d-s), , (2) Benzoyl chloride, , (3) (a-s), (b-q), (c-r), (d-p), , (3) p–chlorotoluene, , (4) (a-q), (b-r), (c-s), (d-p), , (4) o–chlorotoluene, , ANSWER KEY, Que. 1, 3, Ans, Que. 16, 1, Ans, 16, , 2, 2, , 3, 2, , 4, 3, , 5, 2, , 6, 1, , 7, 4, , 8, 4, , 9, 3, , 10, 2, , 11, 3, , Your Target is to secure Good Rank in Pre-Medical 2021, , 12, 3, , 13, 2, , 14, 1, , 15, 2, , E

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TARGET : PRE-MEDICAL 2021, 8., , Among the bromides given below, the order of, reactivity of S 1 reaction is N, , 12., , O, , O, , (I), , (II), Br, , Under identical conditions, solvolysis of which of, the following substrate would lead to maximum, racemisation :-, , CH3, , (III), Br, , (1) H, , Br, , Br, , (2) III > II > I, , CH3, H, , (4) II > I > III, , (I), , Br, , (2), , Compare rate of S, , I, , 1, , N, I, , :-, , OCH3, , I, , (II), , CH3, , (III), , (1) II > III > I, (3) I > II > III, 10., , D, , (1) III > I > II, , (3) II > III > I, 9., , ORGANIC CHEMISTRY, , (3) Br, H, , (2) II > I > III, (4) III > II > I, , Br, (4) C6H 5, , Reactivity order for SN1 reaction, Cl, , Cl, , (I), , NO2, , D, CH3, , 13., , Which of the following alcohols is most reactive, towards substitution with HBr ?, , (II), , C H 2O H, , (1), , CH3, , Cl, , Cl, , C H 2O H, , (2), (III), CH2CH3, , 11., , (2) II > III > IV > I, , (3) IV > III > II > I, , (4) III > IV > II > I, , Which of the following undergoes fastest, reaction with aqueous NaOH solution, (1) C6H5 CH, Cl, , OMe, , (2) C6H5 CH, Cl, , CH3, , (3) C6H5 CH, Cl, , CH2CH3, , C6H5 CH, Cl, , C H 2O H, , HC CH3, CH3, , (1) I > II > III > IV, , (4), 18, , O 2N, , (IV), (3), , C H 3O, , C H 2O H, , (4), Br, , 14., , Consider the following bromides :-, , Me, , Me, , Br, Br, A, , B, , Me, , Me, Br, C, , The correct order of SN1 reactivity is, (1) A > B > C, (2) B > C > A, C6H5, , (3) B > A > C, (4) C > B > A, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 15., , Of the following statements which are true for S, , ORGANIC CHEMISTRY, , 1, , N, , 17., , reaction., , ., , (a) Tertiary alkyl halides react faster than, secondary., Compound A is, , (b) The absolute confuguration of the product, is opposite to that of the reactant when an, , SH, , optical active substrate is used., (1), , (c) The reaction shows first order kinetics., , CH2SH, , (d) The rate of reaction depends markedly on, the nucleophilicity of the nucleophile., SH, , (e) The mechanism is two step., , (2), CH2Br, , (f) Carbocations are intermediate., (g) Rate, , [Alkyl halides], , (h) The rate of the reaction depends on the, , Br, , nature of the leaving group., , (3), , CH2SH, , CH3, , 16., , H, H, , Br, D, , NaOH,DMSO, , Product., , CH3, , (4), , Product .................is :18., , CH3, , Which of the following reaction is feasible ?, , OH, D, , H, (1) H, CH3, , Cl, , –, , + AlCl4, , (1), , AlCl3, , CH3, HO, (2) H, , H, D, CH3, , Cl, (2), Cl, , CH3, , Cl, Cl, , Br, OH, , H, (3) H, , Cl, AlCl3, , (3), , –, , CH3, , Cl, , CH3, , Cl, D, OH, , H, (4) H, , –, , + AlCl4, , AlCl3, , (4), , + AlCl4, , –, , + AlCl4, AlCl3, , CH3, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 19

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TARGET : PRE-MEDICAL 2021, 19., , Which reaction is least feasible, Cl, OH, , 22., , Which of the following on heating with, aqueous KOH, produces acetaldehyde ?, (1) CH2ClCH2Cl, , NaOH, high temp, , (1), , ORGANIC CHEMISTRY, , Cl, , (2) CH3CHCl 2, , OH, , (3) CH 3COCl, (4) CH3CH2Cl, , NaOH, , (2), NO2, , NO2, , Cl, OMe, , 24., , R–OH, , OMe, NaOH, , Cl, , OH, NO2, , NO2, NaOH, , (4), NO2, , 21., , Reagent, R–OH, R–Cl, Which of the following reagents can be used, for this reaction., (a) HCl/ZnCl2, (b) NaCl, (c) PCl3, (d) PCl5, (e) SOCl 2, (1) a, c, d, e, (2) a, b, c, d, (3) a, b, d, e, (4) All of the above, , OH, , (3), , 20., , 23., , NO2, , Arrange the following in order of their leaving, group tendency?, O, Br, Ph-O, H3C C O, (I), (IV), (II), (1) I > II > III > IV, (2) I >III > II > IV, (3) I > II > IV > III, (4) I > IV > III > II, The structure of the major product formed in, the following reaction is :, Cl, , SOCl2, Pyridine, , R–Cl + SO2 + HCl, , This reaction follows which of the following, mechanisms ?, (1) SN1, (2) SN2, (3) E1, (4) E2, , 25., , NaCN, DMF, , I, CN, , F, , (1), , A and B are :(1) Identical structure, (2) Position isomers, (3) Geometrical isomers, (4) None of the above, , (2), CN, , CN, , CN, , Cl, , (3), , (4), CN, , I, , ANS W E R KE Y, Q ue., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , Ans, , 4, , 3, , 1, , 4, , 3, , 4, , 1, , 1, , 2, , 2, , 1, , 2, , 3, , Q ue., Ans, Q ue., Ans, , 14, 2, 23, 1, , 16, 2, , 17, 3, , 18, 3, , 19, 3, , 20, 3, , 21, 4, , 22, 2, , 20, , 15, a-T ,b-F,c-T ,d-F,e -T ,f-T ,g-T ,h-T, 24, 25, 2, 2, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 7., , Cl, , 8., , 10., , Given reaction mainly proceeds through –, CH 3ONa in, CH 3OH/, , (1) E1, (2)SN1, (3) SN2, (4) E2, Match the column-I and column-II and select, the correct answer :, Column-I, Column-II, , 11., , Cl, a q. K O H, , (a), , (p) E 1, , In E 2 elimination some compounds follow, Hoffmann rule which means, (1) The double bond goes to the most, substituted position, (2) The compound is resistant to elimination, (3) No double bond is formed, (4) The double bond goes mainly toward the, least substituted carbon., Identify the set of reagents/reaction conditions, 'X' and 'Y' in the following set of, transformations :Y, , Product, a lc . K O H, , (b), , H 2O, , Br, , (1) X = dilute aqueous NaOH, 20°C,, Y= Br2/acetic acid, 20°C, (2) X = concentrated alcoholic NaOH, 80°C;, Y = HBr/CHCl3, 20°C, (3) X = dilute aqueous NaOH 20°,, Y = Br2/CHCl3, 0°C, (4) X = concentrated alcoholic NaOH, 80°C;, Y = Br2/CHCl3, 0°C, , (r) S N2, , OH, H /, , (d), , CH 3–CH–CH3, , (q) S N1, , Cl, (c), , X, , CH3–CH 2–CH 2Br, , Cl, , (s) E 2, , (1) (a-s); (b-r); (c-p); (d-q), , 12., , Maximum dehydration takes place that of O, , (2) (a-r); (b-s); (c-q); (d-p), , OH, , (3) (a-r); (b-s); (c-p); (d-q), , (1), , (4) (a-q); (b-p); (c-r); (d-s), 9., , ORGANIC CHEMISTRY, , O, , In the given reaction, (2), OH, , O, , Product (Major), (3), The product will be, , OH, CH2, , (1) Cis-2-butene, (2) Trans-2-butene, (4), , (3) 2-butyne, , OH, , (4) Buta-1, 3-diene, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , Ans, , 2, , 4, , 3, , 3, , 4, , 4, , 4, , 2, , 2, , 4, , 2, , 2, , 22, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 9., , Identify the hydrocarbon which on ozonolysis, gives :(a) Only acetone, (b) 1 equivalent of glyoxal + 1 equivalent of, propanedial, (c) 1 equivalent of CO 2 + 2 equivalent of, formaldehyde, (d) 1 equivalent of acetone + 1 equivalent of, acetaldehyde, , 12., , 13., , ORGANIC CHEMISTRY, , Among the following, the compound which has, highest boiling point is :(1), , (2), , (3), , (4), , Which of the following will react with 1-butyne ?, (1) AgNO3 + NH4 OH, (2) Cu2 Cl2 + NH4 OH, (3) Na, (4) All of them, , 10., 14., , ?, , The compound A is :(1) Benzene, (2) Duetero benzene, (3) Duetero toluene (4) Both (2) & (3), 11., , Cl2, CCl4, , Ph–CH=CH–Ph, H2 Pd, BaSO4, , 2 NaNH 2, , X, , Y, , (1), , (2), , (3), , (4), , Z, , Product Z is, , Ph, (1), , (3), , H, , H, , Ph, , Ph, , H, , H, , (2), , Ph, , Ph C CH2, Ph, , (4) Ph–C C–Ph, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 10, , 11, , 12, , 13, , Ans, Que., Ans, , 2, 14, 3, , 3, , 3, , 2, , 4, , 4, , 2, , 2, , 2, , 3, , 4, , 8., , (a) 2HCHO, , (b) CH3–C=O+HCHO, CH3, , (h) CH3–C–C–H+H–C–C–H+CH3–C–C–CH3, O O, , O O, , O O, , CH3, , (i) CH3–C=O + CO 2, (c) 2CH 3–C–OH, , (j) 2 CH3–C–OH, , (d), , O, O, , O, , OH OH, , O, , 9., , (a) CH3–C = C–CH 3, , (b), , CH 3 CH3, , (e) 2CH3 – CHO + CO2 (f), , O+HCHO, , (c) CH2=C=CH2, (g) 3, 24, , CHO, CHO, , (d) CH3–C=CH–CH 3, CH3, , (Glyoxal), , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 18., , The major product of the reaction is, , 22., , The presence of primary amine can be confirmed by these reactions with except :(1) HNO2, , Major Product, , NH2 OH, , ORGANIC CHEMISTRY, , (2) CHCl3+KOH, (1), , (2), , (3), , H, , (4) H2 SO4, , N, , (4), , O, , (3) CS2 and HgCl2, , OH, , H, 19., , Which of the following compound can form, hydrazone and will give iodoform test but will not, give Tollen's test ?, O, C, , (1), , 20., , 23., , The major product formed in this reaction :CH2 CH3, , (2) H3C C CH2 CH3, O, (3) H3C C CH2 CHO, O, (4) CH3 –CH 2 –OH., , (1), , Which one of the following compounds will, not be soluble in sodium bicarbonate ?, , (2), , (1) Benzene sulphonic acid, (2) Benzoic acid, (3) o-Nitrophenol, , (3), , (4) 2,4,6-Trinitrophenol, 21., , Find out correct sequence of reagent for, following conversion :, 24., , (4) None of these, Match the following :, , a Phenol + Neutral FeCl3, , p No reaction, , (1) PCl5, CH3MgBr, , b Phenol + Br2 (aq.), , q Violet colour, , (2) CH2N2, NaBH4, , c Phenol + NaHCO 3, , r White ppt., , (3) SOCl2, H2/Pd,BaSO4, , d Picric acid + NaHCO 3, , s CO 2 gas is evolved, , (4) All of the above, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , Ans, , 3, , 4, , 3, , 3, , 4, , 4, , 1, , 3, , 3, , 4, , 4, , 1, , 2, , Que., Ans, , 14, 4, , 15, 2, , 16, 2, , 17, 3, , 18, 3, , 19, 2, , 20, 3, , 21, 3, , 22, 4, , 23, 1, , E, , Your Target is to secure Good Rank in Pre-Medical 2021, , 24, a-q, b-r, c-p, d-s, , 27

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , BASED ON CONVERSIONS, , RACE # 12, , (i) B H 3 , T H F, , 1., , CH3 – CH = CH2, , P C l5, , X, , (ii) H 2O 2/O H, , 5., , HBr, , CH3 –C CH, , X, , a q. K O H, , Z n -H g, , Y, , Z, , HCl, , Which of the following is true regarding Z ?, , Y; Y is, , (1) Its all carbon atoms are sp 3 hybridised, , (1) CH3 – CH2 – CH2 – Cl, , (2) It can be obtained in good yield by Wurtz, reaction., , (2) C H 3 – C H – C H 3, Cl, , (3) It shows isomerisation reaction with, HCl/AlCl3 ., , Cl, , (3) C H 3 – C H 2 – C H, , (4) All, , Cl, 6., , Cl, , CH2=CH2, , Baeyer 's, reagent, , PCl 5, , P, , Q, , NaNH 2, 1mole, , R., , Which of the following statement is true, regarding R?, , (4) CH3 – C – CH3, , Cl, , (1) Has more dipolemoment than ethylchloride., 2., , O z o n o ly si s, , CH 3 – CH = CH – CH 3, , X, , (2) Has more C-X bond length than, ethylchloride, , (i) alc. K O H, , P C l5, , Y, , Z; Z is, , (ii) N aN H 2, , (3) Is less reactive than ethylchloride for SN reaction., , (2) C H 3 – C H, , (1) CH 3 – CH = O, (3) CH2 = CH – Cl, , (4) HC, , Cl, , (4) All., , Cl, 7., , CH, , C H 3– C H – C H 3, , alc. KOH, , X, , HBr, R 2O 2, , Y, , KI, A c eton e, , Z, , I, (P ), , N a O H /C a O, , O, 3., , P, , Initial compound (P) and the last product Z, are :-, , R;, , CH 3 – C – OH, (i) A g O H, (ii) B r 2/C C l 4, , X, , (1) Chain isomers, , (2) Position isomers, , (3) Homologues., , (4) Identical., , Reagent R can not be:, , KCN, , (1) LiAlH4, , (2) Na + (C2 H5)2 O, , (3) Zn + HCl, , (4) All, , 8., , CH3 – CH3, , B r2, h, , AgCN, , 4., , CH3 – C H – CH = CH2, (P ), , R, , PC l 3, , (A lco h o l), , S, , C H 3O N a, , T, , ., , (A lk y lch lo r id e) (E th er), , Which of the following should be used as Q to, get ether (T) in good yield ?, (1) H3O, (2) (i) (CH3COO)2 Hg, H2O (ii) NaBH 4, (3) (i) BH3, THF (ii) H2 O2 / OH, (4) All, 28, , H 3O, , S, , P, , CH3, Q, , Q, , R, , H 3O, , T, , The products S & T can be obtained by, ozonolysis of :, (1) CH 3 – CH2 – C, (2) CH 3 – C, , CH, , (3) CH 3 – CH2 – C, (4) CH 3 – C, , C – CH2 – CH3, CH, , C – CH3, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, 1. O3, 2.Zn,H2 O, , 16., , (A), , 1. OH /, , (P), , 2. H, , ORGANIC CHEMISTRY, Mg, Dry ether, , 18., , Product 'P' will be :-, , NaHCO3, , (1) CHO, , (A), , (i) 14 CO2, ii H / H 2 O, , (B), , (C) gas, product C is :-, , (1) CO, , COOH, , (2), , (2) CH2OH, , 14, , CO2, , (3) CO2, , COOH, , (4) A mixture of, , (3) CH2–OH, 19., , CH2–OH, , 14, , CO2 and CO2, , (P) and (Q) in the following reaction is, , (4) COOH, COOH, , 17., , Identify major product of following sequence of, reaction :, OH ,, , (1), , OH, , O, , O, , (2), , (3), , (1), (4), 20., , (2), , In the given reaction sequence, , C6H5NO2 Sn/HCl P NaNO2/HCl Q CuCN/HCN R H2O/H S, , which one statement is not correct ?, , (3), , (1) P is C6H5 NH2, (2) Q is C6H5 – N, (4), , N Cl, , (3) R is C 6H 5CH 2CN, (4) S is C6H5COOH, , ANSWER KEY, Que., , 1, , 2, , 3, , 4, , 5, , 6, , 7, , 8, , 9, , 10, , 11, , 12, , 13, , 14, , 15, , Ans, , 1, , 4, , 2, , 3, , 1, , 3, , 2, , 3, , 3, , 2, , 2, , 2, , 2, , 2, , 2, , 17, 3, , 18, 3, , 19, 4, , 20, 3, , Que. 16, 2, Ans, 30, , Your Target is to secure Good Rank in Pre-Medical 2021, , E

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TARGET : PRE-MEDICAL 2021, O, , 5, 4, , 16., , 2, 3, , ORGANIC CHEMISTRY, , OH, , 1, , O O, , 23., , 3-Formyl-4-methyl-5-oxopentanoicacid, , Cyclohexane-1,2-dicarboxylicanhydride, , 17., 24., 2,3-Epoxypentane, 3-Ethylcyclohexanecarbonitrile, CONH2, , 18., , 1, , 5, 4, , 2, 3, , 25., , Cyclopentanecarboxamide, , 2, , 1-Ethyl-6,6-dimethyl-1-cyclohexene, , Cl, , 5, , 19., Br, , 3, , 1, , 26., , Br, , 3, , 6, , 2, , 4, , 1, , Hex-4-en-1-yne, 1,3-Dibromo-2-chlorocycloprop-1-ene, , 5, , 27., , CH3 CH 3, , 3, , 6, , 2, , 4, , 1, , 7, , 1, , 4-Methylhept-5-en-2-ol, , 20., 3, , CH2CH3, , 2, , 28., 4, , 3, , 2, , 1, , Ethyl-4-cyanobutanoate, , 2-Ethyl-1,1-dimethylcyclopropane, Br, Cl, , 21., , Br, , 2, , 3, , 1, , 29., , Br, , 4, 6, , 5, , Cl, , 2-Chlorobutanoylchloride, , Cl, , 2, , 1,2,4-Tribromo-3,5,6-trichlorocyclohexane, , CH3, 22., , CH3, , 3, , 4, , 30., 1, , 1, , N–CHO, , 2-Ethyl-4-oxobutanenitrile, , N,N-Dimethylmethanamide, , 2, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 14., , ORGANIC CHEMISTRY, , Molecular mass of hydrocarbon = 72, 14n + 2 = 72 (Alkane), (n=5), n = number of carbon in branched chain isomer, of hydrocarbon, , 4 monochloro derivative possible (excluding, stereoisomer), 10., , C4 H8, , CH 3, , CH3–CH 2–CH=CH2 (1-butene), , CH 3–C–CH3 (Only one monochloro derivative), , CH3–CH=CH–CH3 (2-Butene), , CH3, Neopentane, , CH 3–C=CH2 (Isobutene), CH 3, , 15., , Represent either alcohol or ether), , (3 structural isomers), O, , 11., , 1. Alcohol :, , O, ;, , C5H12 O :, , C5H11–OH : 8 alcohol, 2. Ether :, , H, , are not isomer (Molecular formula differ), , H3C–O–C4H9 : 4, H5C2–O–C3H7 : 2, , O, , O, , [Total : 8 + 6 = 14], [Note : Refer solution of Q.6], , H, , NH2 ; H2N, , are functional isomer (Not position isomer), , 16., , Relation between the following compounds:, O, , ;, (2,3-Dimethylpentane) (2,4-Dimethylpentane), , 12., , 6, , COOH, O, , i., , and, , (Acid), , are position isomers, , (Ester), , CH3–NH–CH2CH2CH2CH3 ;, , isomers., , CH3–NH–CH2–CH–CH 3, , are functional, , O, , O, , C–Cl, , Cl, , CH3, ii., (Both are chain isomer with minimum number of, carbon in 2°-amine), , and, (Ketone), , are functional, (Acid chloride), , isomers., , 13., , 5, , O, –S–O–, , 4, , 3, , O, –Me, , 2, , 4, , 3, , 2, , iii. CH3CH2CH2CHCH3 and CH3CH2CHCH2CH3, , Different, Me–, , COOH, 1, , –S–O–, , O, , O, , 1, , are chain isomers., O, , Different, , Different group/substituent attached to polyvalent, functional group :- Metamerism., , COOH, , O, , iv., , and, , are functional, , (Ester), , isomers., 4, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , GEOMETRICAL ISOMERISM, 1., , CH3–C C–CH3, , RACE # 03, , ( = 0), 6., , 2., Highest priority (H.P) at opposite side :- E, H.P. : Higher priority according to CIP rule, 7., , Cl, 3C, , 3., , H, , C=C, (I), , H, CCl3, ( =0), , CCl3, H, , C=C, (II) (, , No. of GI = 2n (For unsymmetrical alkene), n = no. of double bond, across which molecule, show GI., , CCl3, H, 0), , Dipole moment :, II > I (Additive moment vector in II), Boiling moment :, II > I (II is more polar), Melting point :, I > II (I is symmetrical, more packing), Stability :, I > II (In I, less steric repulsion), , 21, , 2 Cis, , Trans, Cl, , 8., Cl, , Cl, , (only two different configurational GI), , 4., , If across double, each sp2 carbon should have, at least one identical group, then show cis-trans, isomerism. (Note: For GI, each sp 2 carbon, should have two different group), 5., , In both condition, highest priority (H.P.) at, opposite side :- E, 6, , 9., , The comp. which can show GI are :Note :(I), To show GI in alkene ; each sp2 carbon, should have two different group., (II) To show GI in cycloalkane ; At least two, different carbon atom of cycle should, have two different group., GI, (i), CH3 –CH=CH–C CH, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , (ii), (iii), (iv), , CH3–CH2–CH2–CH=CH2 ×, CH3–CH=CHCl, , (v), , ×, , (vi) CH3 –C, (vii), , C–CH3, , (viii) CH2 =CH–C CH, (ix) CH3 – CH = CH – CH3, Cl, , (x), , (v), , × (Linear), × (No, restricted, system), ×, , (vi), , (vii), , Cl, C, , H, , C, H, , H, , H, , COOH, , COOH, , (xi), (viii), , Z :- (i), (ii), (iii), , (xii), , E :- (iv) , (v) , (vi) , (vii) , (viii), 11., 10., , E/Z configuration :, Note : Each sp 2 carbon should have two, different group to show GI., , (i), , (I) High priority (HP) gp. at opposite side :- E, (II) High priority (HP) gp. at same side :- Z, (ii), , (i), , (ii), (iii), , (iii), , (iv), , (iv), , ((i), (iii), (iv) show zero dipole moment), HS, , Your Target is to secure Good Rank in Pre-Medical 2021, , 7

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TARGET : PRE-MEDICAL 2021, 12., , (a) (i), , (ii), , (i) > (ii), , ORGANIC CHEMISTRY, , 14., , [Priority according to CIP rule], 15., (b) (i), , (c) (i), , (ii), , (ii) > (i), , (ii), , (i) >, , H 3C, H, H, H 3C, , CH2, , Across this, bond show G.I., , (ii), 13., (Not show G.I.), (sp2 carbon should have two different groups.), , 8, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 8., , ORGANIC CHEMISTRY, ••, , Acidic strength (AS) order :, , (F) CH2=CH–O–CH=CH, (delocalised p), 2, ••, (localised p), , (G), CH2, , (H), , (localised p), , ••, , O, ••, , OR, (I), , (delocalised p), , ••, , O, ••, , Delocalised p (B, D, F, I) takes part in resonance., (Which are alternate to -bond), O, , O, , 11., , (1), , H, , C, , OH, , H, , C, , OH, , I, II, (Nonpolar RS) (Polar RS), , I > II, , (2) CH2–C CH, CH2=C=CH, I, II, II > I, complete octet, complete octet, (–ve on less EN), (–ve on more EN), , Stability of conjugate base II > I > III > IV, AS Stability of conjugate base, so AS :- II > I > III > IV, , (3), , 9., , I > II, CH2, , CH2, , I, II, (Aromatic RS) (Antiaromatic RS), (4) CH3 C O, Incomplete octet, , CH3 C O II > I, Complete octet, , 12., Basic strength (BS), , EDG (electron donating gp), , 1, EWG (electron withdrawing gp), (I), , 1, EN, 10., , (A), , (B), , N, ••, , (localised p), (C), , (delocalised p), (D), , N, ••, , (localised p), , N, ••, , Nonplar, RS, , (II), , Polar RS with, Complete octet, , III and IV :[Polar RS with incomplete octet], (a) +ve on less EN and –ve on more EN atom more, stable., (b) +ve on more EN and –ve on less EN atom less, stable., Order :I > II > III > IV, (stablity), , (delocalised p), ••, , (E) CH2=CH–CH=NH (localised p), 14, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, 13., , 16., , ORGANIC CHEMISTRY, , Basic strength :, , x, , z, , y, , basic strength, , No resonance effect of, 14., , NH 3 group., , 17., , Stability order :-, , (i), , (ii), Basic strength, , EDG, , EWG, 18., (iii), , ·, ·, ·, ·, , (iv), , cyclic, planar, cyclic resonance, follow Huckel's Rule, [(4n + ) e– system; n = 0, 1, 2, ---], 4n + 2 = 6, 4n = 4 : n 1, , · Aromatic, 19., ·, ·, ·, ·, , 15., Due to + M of – NH2 and less EN of 'N' than 'O',, more basic as compare to (1), Note :*Conjugate acid show equivalent resonating, structure, more stable conjugate acid., HS, , cyclic, planar, cyclic resonance, follow Huckel's Rule, [(4n + ) e– system; n = 0, 1, 2 --- ], 4n+2 = 2; n, , 0, , · Aromatic, , Your Target is to secure Good Rank in Pre-Medical 2021, , 15

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TARGET : PRE-MEDICAL 2021, 20., , ·, ·, ·, ·, , cyclic, planar, cyclic resonance, follow, [(4n ) e– system; n = 1, 2, 3 --- ], , ORGANIC CHEMISTRY, , (a), , C-O bond length :, , (b), , C-N bond length :, , 24., , The more acidic group give fast acid-base reaction, followed by less acidic group., , 4n = 4 n 1, · Antiaromatic, , This is non aromatic., (Tub shaped, non planar)., 21., · cyclic, · Nonplanar (sp3 carbon), · Non aromatic, , Since only 2 moles of NaNH2 is taken so the most, acidic -COOH group (two in number) only give, acid-base reaction., , 22., , 25., , (I > II), , 23., , 16, , Bond length :, [Single bond > partial double bond > double bond, > triple bond ], * Resonance increases double bond character in, single bond and single bond character in double, bond., , 26., , –CH3 show maximum hyperconjugation effect but, minimum inductive inductive effect., For Hyperconjugation :- C–H bond energy, should be low (more –H more hyper conjugation, with less C–H bond energy), For Inductive Effect :- no. of carbon and, branching increases inductive effect., , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , REACTION MECHANISM ( PART-II ), 1. Rate of EAS, , RACE # 08, , Nucleophilicity of aromatic ring, EDG (electron donating group), *, , 1, EWG (electron withdrawing group), , 4., +M :NH, Me, , (c), , (d), , (b), , (a), , 2., , O, –M, , NH, Me, , due to +M of –NH–, this ring is activated, for ESR (ortho/para, directing), , Br2, Fe, , O, Me, , Me, , Br, , 5., , –CH3 is ortho/para directing and ring activating group., 3., 1., , E attack in most activated ring at most, activated site, and at the place where minimum, 6., 2., , steric hinderance., If alkyl group is same, then rate of SN2 is directly, proportional to leaving tendency of halide, attached to alkyl group., R – I > R – Br > R – Cl > R – F, (minimum, bond energy), , 7., 3., , Reactivity towards SN1 stability of intermediate, carbocation., , reactivity order : 1 > 4 > 3 > 2, , 4., , HS, , Your Target is to secure Good Rank in Pre-Medical 2021, , 19

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TARGET : PRE-MEDICAL 2021, OH, , Cl, 8., , aq. KOH, , (a), , 12., , Dehydration reaction is reversible controlled by, thermodynamics, so more stable product is, major (alkene), , SN2, (r), , OH, , ORGANIC CHEMISTRY, , (2°halide), Cl, A c. KOH, , (b), , from (1) and (2), , same product formed,, , E2, (s), , (2°halide), Cl, H2O, (PPS), , (c), , so now compare stability of carbocation, , OH, , formed., , SN 1, (q), , (3°halide), OH, , <, H, , (Stability), , E1, , (d), , (p), , 3°alcohal, , 9., , (1), , CH3, H, , Br, , H, , Br, CH3, (Meso), , 10., , Zn, ether/, Dehalogenating, reagent, (anti elimination), , H, C, , < (2), , (Reactivity), , CH3, , C, H3C, H, [Trans-2-butene], , Hofmann's rule :- The double bond goes mainly, towards the least substituted carbon., , 11., , HS, , Your Target is to secure Good Rank in Pre-Medical 2021, , 23

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TARGET : PRE-MEDICAL 2021, HYDROCARBON, ELECTRONIC, DISPLACEMENT, 1., , RACE # 06, 10, 6., , Read P+ HI is strong reducing agent :- Final, product is alkane., , 7., , Decolourisation of cold, dilute alkaline KMnO4, (Bayer's reagent) is a test of unsaturation., Benzene doesn't give test of unsaturation, (Aromaticity loss), C6H12 (alkene) give test of unsaturation., Product of following rxn, , 2., 8., (a), , 3., , ORGANIC CHEMISTRY, , (b), , (c), 4., , acid sensitive group, so can't use Zn-Hg/HCl, Red P + HI convert molecule to alkane, So here prefered NH2NH2 / C2H5ONa, (Wolff-Kishner reduction) (alkaline medium), 5., , R–X+2Na+X-R, , Dry ether, , R–R+2NaX, , (d), , (Symmetrical product), (if single type RX taken), (e), this product obtained from, ; single alkyl halide in Wurtz reaction., (f), , 24, , Your Target is to secure Good Rank in Pre-Medical 2021, , HS

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TARGET : PRE-MEDICAL 2021, , ORGANIC CHEMISTRY, , 9., Back product determination., (a), CH3, CH3, CH3, (g), , C=O O=C, CH3, , CH3, C=C, , CH3, , remove 'O' CH3, and join double, bond, , CH3, , (h), (b), , (c), (d), , 10., +, , Mg Br, , –, Note :Total 3 types of product, 2, +3, (Reductive Ozonolysis), , +1, , D, , + –, + D–O–D, , (Grignard, reagent), , (Active, hydrogen), (deuterium), , Acid-Base, Reaction, , (Deuterobenzene), , Br, , Note:- Zerewitinoff's determination of active or acidic, hydrogen., 11., , Cl2, CCl 4, , Ph–CH=CH–Ph, , (Antiaddition), , (i), , 12., (j), , OD, + Mg, , Boiling point Van der Waals force of attraction, force, (Van der Waals attraction force molecular mass), , Molecular mass, HS, , Your Target is to secure Good Rank in Pre-Medical 2021, , 25