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Mathematics | 67 (F), , , , Ls, , , , B, Area of inner circle = rr?, = —. 616= am, Do,, 616=—x, = 7 Vi, Ke a 616x7 =196, 22, , =V196 =14 m, Radius of outer circle , =" +2, =14+2=16m, -. Area of circular path = Area of outer circle, — Area of inner circle, 2, ’ = my ~ 1h, cod mrp -K), , = Mh +h)(y-h), , i =F .(16+14)(16-14), , = Ze x30x2, 7, = 188-57 sq. m. Ans., Q. 3. The radius of a circular cricket ground is, 60m. Around the ground a7 m circular gallery is to, be built for spectators. What will be its area ?, Sol. Radius of outer circle = Radius of inner circle, + Width, =60+7=67m, , ee, , -. Area of circular gallery = oa of bigger circle, — Area of smaller circle, = (67) — 260)", ! = m{(67)” —(60)"], _= a{(67+60)(67 —60)], = 2x Dx], , = 2794 sq. m. Ans.