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Today’s Topic, ⚫, , Word Problems
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Worksheet 3, (Solve in Math Notebook), a) Find the perimeter of a rectangle whose length, is 12 cm and breadth is 8 cm., , Solution:, Length, , = 12 cm, , Breadth, , = 8 cm, , Perimeter of the rectangle = 2(Length + Breadth), , = 2(12cm + 8 cm), = 2 x 20 cm, = 40 cm
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Worksheet 3, (Solve in Math Notebook), b) Calculate the perimeter of the square whose, sides are given :, 1) 6 cm, , Solution:, Perimeter of the square = 4 x side, = 4 x 6 cm, , = 24 cm
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Worksheet 3, (Solve in Math Notebook), b) Calculate the perimeter of the square whose, sides are given :, 2) 11 metres, , Solution:, Perimeter of the square = 4 x side, = 4 x 11 metres, , = 44 metres, , 11 metres
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Worksheet 3, (Solve in Math Notebook), b) Calculate the perimeter of the square whose, sides are given :, 3) 26 cm, , Solution:, Perimeter of the square = 4 x side, = 4 x 26, , = 104 metres, , 26 cm
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Worksheet 3, (Solve in Math Notebook), c) The length of three sides of a triangle are 6 cm,, 8 cm and 10 cm. Find the perimeter., , Solution:, Perimeter of the triangle = Sum of the sides of the triangle, , = 6 cm + 8 cm + 10 cm, = 24 cm
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Worksheet 3, (Solve in Math Notebook), d) A boy runs around a rectangular field, the length of, which is 35 metres and the breadth is 20 metres., How much distance will he run?, , Solution:, Length, , = 35 metres, , Breadth, , =, , 20 metres, , Perimeter of the rectangle = 2(Length + Breadth), = 2(35 m + 20 m), , The boy will run 110 metres., , = 2 x 55 m, = 110 metres
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Worksheet 3, (Solve in Math Notebook), e) Sheela wants to fix ribbon along the border of, a painting. If the length and breadth of the painting, are 36 cm and 15 cm respectively, how much ribbon is, required by Sheela?, , Solution:, , Length of painting, , = 36 cm, , Breadth of painting, , = 15 cm, , Perimeter of painting, , = 2(Length + Breadth), , = 2(36 cm + 15 cm), = 2 x 51 cm, = 102 cm, , Sheela requires 102 cm of ribbon.
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Worksheet 3, (Solve in Math Notebook), f) Raju has to frame a square photo having one side, of length 12cm. How much material will Raju require for, this job?, , Solution:, Length of one side of a photo = 12 cm, Perimeter of the photo, , = 4 x side, = 4 x 12 cm, = 48 cm, , Raju will require 48 cm of material to frame the photo.
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Worksheet 3, (Solve in Math Notebook), g) A boy runs two times around a field, the length of, which is 62m and breadth is 40m. Find the distance, covered by him., , Solution:, , Length of the field, , = 62 m, , Breadth of the field, , = 40 m, , Perimeter of the field, , = 2(Length + Breadth), =, , 2(62m + 40 m), , =, =, , 2 x 102 m, 204 m, , Distance covered by the boy = 204 x 2 = 408 m
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Worksheet 3, (Solve in Math Notebook), , h) Tina ran around a rectangular garden of length 12 m, and breadth 8 m. Meena ran around a square field of side, 11 m. Who covered more distance and by how much?, , Solution:, , Length of the garden, , = 12 m, , Breadth of the garden, , =, , 8 m, , Perimeter of the garden = 2(Length + Breadth), , Tina covered 40 m, , =, , 2(12 m + 8 m), , =, =, , 2 x 20 m, 40 m
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Worksheet 3, (Solve in Math Notebook), Solution:, Length of one side of field = 11 m, Perimeter of the field = 4 x side, , = 4 x 11 m, = 44 m, Meena covered 44 m, , Meena covered more distance by 4 metres, ( 44m – 40m = 4 m)
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