Page 1 :
DIOod is affected., • Due to this, in an affected individual, a small cut, results in non-stop bleeding., • The heterozygous female (carrier) may transmit, the disease to sons. The possibility of a female, becoming a haemophilic is extremely rare, because mother of such a female has to be atleast, carrier and father should be haemophilic., (b) Normal parents give rise to a haemophilic child., So, the genotypes of them should be Father-XY, (normal) Mother, non-haemophilic), 2013), m to a normal, the family for, ot to blame the, ring from this, ropagate in the, (CBSE 2013), cross and state, Xx (carrier/heterozygous, (CBSE 2014), a categorized as, ptoms of these, inheritance in, Father, Mother, XY, xx, (CBSE 2015), rents producing, determined by, le gene. These, ext generation, ance and can be, utation may be, XX, xx, XY, Normal, Carrier, Normal Haemophilic, Daughter Daughter, Son, Son, MATCH THE COLUMN TYPE QUESTIONS, lers are colour, cystic fibrosis,, e, Alkaptonuria,, 1. Identify the correct match between scientists and their, contributions:, Scientists, Contributions, njugated protein, hain consists ofa, osomal inherited, ed synthesis of, Beta and alpha, ynthesis of B and, A Gregor Mendel, B W. Johannsen, C William Bateson, I Polygenic inheritance, 2 Term 'Genetics, 3 Fundamentals of heredity, DH. Nilsson-Ehle, 4 Term 'Gene', by a gene on, B globin chain is, is in deficiency of, of the other chain., emia (inability to, (a) A 1, B-3, C-2, D-4, (b) A 4, B-3, C=1, D-2, (c) A 3, B-4, C-2, D=1, (d) A- 4, B-2, C-1, D-3
Page 2 :
6. Match the column I with column II and find the correct, GRB New Era Biology: Class-XII, 258, 2. Match the following and choose the correct combination, from the options given:, (a) A = 3, B = 1, C= 2, D 4, (b) A 1, B= 3, C = 4, D 2, (c) A = 3, B = 4, C = 1, D = 2, (d) A = 4, B = 3, C = 2, D 1, Column II, Column I, 1 American geneticist, A J. B. S. Haldane, 2 Dutch botanist, answer:, B Gregor Mendel, Column II, 3 British geneticist, Column I, C Hugo de Vries, D T.H. Morgan, 1 2n-1, 4 Austrian monk, A Monoploidy, 2 2n+1, B Monosomy, (a) A = 3, B = 4, C= 2, D 1, (b) A = 4, B = 3, C 1, D 2, (c) A = 3, B = 4, C 1, D 2, (d) A = 2, B = 4, C= 1, D= 3, 3. Match the items given in column I with those listed in, column II. Choose the answer with correct combination, of alphabets of the two columns:, 3 2n+2, C Nullisomy, 4 2n-2, D Trisomy, E Tetrasomy, 5 n, (Kerala PMT 2009), (a) A = 5, B = 3, C= 4, D 2, E = 1, (b) A = 3, B = 1, C= 5, D= 4, E = 2, (c) A = 5, B = 1, C= 4, D = 2, E = 3, (d) A = 3, B = 1, C = 5, D= 2, E = 4, 7. Match the following in Drosophila with reference to sex, determination:, Column II, Colunın I, (Genotypes), 1 T and t, A Monohybrid cross, B Test cross, 2 TT, C Alleles, 3 TT x tt, Column Il, (Sex), Column I, D Homozygous tall, 4 Tt x tt, (X/A), (Karnataka CET 2003), A 0.5, 1 Metafemale, (a) A = 1, B = 4, C= 2, D = 3, (b) A = 4, B = 3, C= 1, D= 2, (c) A= 3, B = 4, C = 3, D= 2, (d) A 3, B= 4, C = 1, D= 2, 4. Match the following and choose the correct combination, from the options given:, B 1.0, 2 Metamale, C 1.5, 3 Male, D 0.33, 4 Intersex, E 0.67, 5 Female, (a) A = 3, B= 5, C = 1, D 2, E = 4, (b) A = 3, B = 1, C= 5, D 2, E = 4, (c) A = 4, B = 3, C = 5, D 2, E = 1, (d) A = 1, B = 3, C= 2, D= 5, E = 4, 8. Match the terms column I with column II and choose the, correct alternative:, Column I, Column II, A Rr x Rr, 11:1, B Rr x rr, 23:1, C RyYy x RrYy, D RrYy x rryy, 3 1:1: 1: 1, 4 9: 3: 3: 1, Column I, (a) A 4, B = 1, C=2, D 3, (b) A 2, B 1, C=4, D 3, (c) A 4, B= 1, C=2, D 3, (d) A 1, B= 3, C= 4, D 2, 5. Identify the correct match between inheritance and their, examples:, Column II, A Sickle-cell anaemia, 1 7th chromosome, B Phenylketonuria, 2 4th chromosome, C Cystic fibrosis, D Huntington's disease, E Colour blindness, 3 11th chromosome, 4 X- chromosome, Columa 1, 5 12th chromosome, A Complete dominance, B Multiple alleles, C Co-dominance, Column II, 1 Flower colour in snapdragon, (Kerala PMT 2007, 08), (a) A = 4, B= 3, C = 5, D 2, E= 1, (b) A = 3, B = 1, C 2, D 5, E= 4, (c) A= 3, B = 5, C 1, D 2, E= 4, (d) A = 1, B 3, C= 2, D 5, E = 4, 2 Colour coat of cattle, 3 Blood group inheritance, 4 Flower colour in pea, D Incomplete dominance
Page 3 :
Principles of Inheritance and Variation, A Match the column I with column II and choose the, correct option:, 16., is the chromosomal complement of an, organism., 17. Cri-du-chat syndrome is caused by a conspicuous, deletion in the short arm of one of the, 18. In Drosophila genes for maleness are carried on the, Column I, Column II, A Incomplete dominance, 1 Hershey and Chase, B Linkage, C Transforming principle, D Proved that DNA is the, genetic material, 2 Antirrhinum sp., those for femaleness on the, 3 Griffith, 19. Humans, like other mammals have a sex-determination, mechanism that depends on, 20., 4 Morgan, body was discovered by the Canadian, geneticists Murray L. Barr and E.G. Bertram (1949) in, the interphase nerve cell of female, 21., (Kerala PMT 2012), (a) A = 1, B = 4, C = 3, D = 2, (b) A = 4, B = 2, C= 3, D 1, (c) A 2, B 3, C= 4, D 1, (d) A 2, B = 4, C = 1, D= 3, (e) A 2, B 4, C= 3, D 1, is the sex chromatin present in the, (polymorphonuclear leucocyte) of 3 to 5%, cells in females, but not in males., 22. First X-linked gene was discovered by, (1910) for white eye mutation., 23. The recessive X-linked gene for haemophilia shows, characteristic, blindness., 24. Inheritance of A, B, AB and O blood types in man was, discovered by, 25. Sickle-Cell disease is a genetic disease due to a, molecular mutation of gene Hb^ on, ANSWERS, like the gene for colour, 1. (c), 6. (c), 2. (a), 3. (d), 4. (b), 5. (d), 7. (a), 8. (c), 9. (e), in 1925., MISCELLANEOUS QUESTIONS, O Fill in the blanks, ANSWERS, 1. multiple allele, 2. Joseph Kölreuter, 3. Pisum sativum,, 4. reciprocal cross, 5. Dihybrid cross, 6. Alfred H., Sturtevant, 7. polygenic effect, 8.'pleiotropy', 9.pachytene,, diplotene, 10. Transposon, 11. germplasm, 12. endosperm,, 13. Datura stramonium (Jimson weed), 14. T.H. Morgan,, 15. Nitrous acid, 16. Karyotype, 17.5th autosomes,, 18. autosomes, X chromosome, 19. Y chromosome, 20. Sex, chromatin, cats, 21. Drumstick, neutrophil, 22. T. H., Morgan, 23. criss-cross inheritance, 24. Bernstein,, 25. chromosome 11., 1. The ABO blood type system is also an example of a trait, that is controlled by a, 2., series., a, German botanist had conducted, hybridization experiments in tobacco plant., 3. Mendel had conducted hybridization experiments in, garden pea, 4. Two crosses between the same pair of genotypes or, phenotypes in which the sources of the gametes are, reversed in one cross, is known as, 5., is a cross involving two pairs of contrasting, characters., 6. The procedure for chromosome mapping was invented, by, 7. Human skin colour is controlled by, by three separate genes., 8. The ability of a gene to have multiple effects is known as, O True or False Statements, State whether the following statements are True (T), or False (F), 1. The number of characters studied by Mendel in pea plant, in 1911., at least, was six., 2. Back cross to the recessive parent is known as test cross., 3. When an allele fails to express itself in the presence of the, other, the former is said to dominant., 4. Genes that are present on the same chromosomes are, called syntenic., 5. A person with AaBbCc (i.e., heterozygous for all three, genes) will have an intermediate colour termed as, mulatto., 6. Beadle and Tatum proposed the "chromosome theory of, inheritance"., 7. William Bateson, E.R. Saunders and R.C. Punnett, (1905) working with Pisum sativum (garden pea) were, the first to discover linkage., 3. Crossing over takes place at 4-strand stage between, and, 10., is a DNA segment or genetic element moving, from one chromosome to another., . To be evolutionary successful, a mutation must occur in, DNA., 12. An example of triploid tissue is, of wheat., A. A.F. Blakeslee and John Belling (1924) reported 12, possible trisomics in, 14., reported the white eye mutation in the fruit, fly Drosophila melanogaster., 15., is a potent mutagen and causes deamination, of cytosine, creating uracil.
Page 4 :
1. Conditions of a karyotype 2n + 1 and 2n 2 are called:, Principles of Inheritance and Variation, 1 Assertion (A) The presence of Y-chromosome, specifies maleness in human being., Regson (R) The X-chromosome carry a gene SRY, which directs the female sex differentiation,, U Assertion (A) In humans, red-green colour blindness is, due to an X-linked dominant gene,, Reason (R) The father transmits his gene for colour, blindness to a son not to a daughter., 15. Assertion (A): Persons suffering from haemophilia fail, to produce blood clotting factor VIII., Reason (R): Prothrombin producing platelets in such, persons are found in very low concentration., 261, 1In sickle cell anaemia, glutamic acid is replaced by, valine. Which one of the following triplets codes for, valine?, (a) GGG, (c) GAA, Person having genotype I1 would show the blood, group as AB. This is because of:, (a) Pleiotropy, (c) Co-dominance, Z/ZW type of sex determination is seen in:, O emplar), (b) A AG, (d) GUG, NERTEsemplar), (b) Segregation, (d) Incomplete dominance, IRIExemplar), (a) Snails, (c) Platypus, 6 Mendel's law of independent assortment holds good for, genes situated on the:, (a) non-homologous chromosomes, (b) extra nuclear genetic element, (c) homologous chromosomes, (d) same chromosome, Two genes 'A' and 'B' are linked. In a dihybrid cross, involving these two genes, the F heterozygote is crossed, with homozygous recessive parental type (aabb). What, would be the ratio of offspring in the next generation?, (b) Peacock, (d) Cockroach, (AUMS 200), 16. Assertion (A) A Turner syndrome individual would be, expected to have no Barr body., Reason (R) Her sex chromosome constitution is XO., 17. Assertion (A) Huntington's disease is a human disease, inherited as a Mendelian autosomal dominant., Reason (R) This disease is more common in males than, TRTEemplar), in females., 18. Assertion (A) The ABO blood series provides a good, example of co-dominance., Reason (R) In this the heterozygote exhibits the, phenotypes of both homozygotes., 19. Assertion (A) Deletion is a chromosomal mutation, involving the loss of a segment of a chromosome., Reason (R) : Down syndrome results from the deletion, of a part of human chromosome 21., 20. Assertion (A) Barr body is known as sex chromatin., Reason (R) : Sex chromatin is formed from the genetic, inactivation of human Y-chromosome., 21. Assertion (A): For a particular character in an, individual, each gamete gets only one allele., Reason (R) : Chromatids of a chromosome split, (separate) and move towards opposite poles during, anaphase of mitosis., INCERLEvemplar), (а) 3:1, (c) 1:1:1:1, 8 In the F, generation of a Mendelian dihybrid cross the, number of phenotypes and genotypes are:, (b) 1:1, (d) 9:3:3:1, (NCERIEsemplar), (a) phenotypes - 9; genotypes -4, (b) phenotypes -4; genotypes - 9, (c) phenotypes- 4; genotypes-8, (d) phenotypes-4; genotypes - 16, 9 Mother and father of a person with O' blood group have, "A' and 'B' blood group respectively. What would be the, genotype of both mother and father?, (karnataka CET 2014), INCERLEemplar), (a) Mother is homozygous for A' blood group and father, is heterozygous for 'B'., (b) Mother is heterozygous for A' blood group and, father is homozygous for 'B'., (c) Both mother and father are heterozygous for 'A' and, 'B' blood group, respectively., (d) Both mother and father are homozygous for 'A' and, 'B' blood group, respectively., 1 In a dihybrid cross between RRYY and ryy parents, the, number of RrYy genotypes in F2 generation will be:, ANSWERS, 4. (a), 9. (a), 14. (d), 19. (c), 5. (a), 10. (d), 15. (c), 3. (a), 8. (c), 1. (a), 2. (b), 7. (c), 6. (a), 13. (c), 18. (a), 11. (d), 12. (a), 20. (c), 16. (a), 17. (c), 21. (b), MULTIPLE CHOICE QUESTIONS, (IK MFE 2008), (NCERTEremplar), (b) Monosomy, (d) Allopolyploidy, (b) 1, d) 4, (a) Polyploidy, (c) Aneuploidy, *. If a genetic disease is transferred from a phenotypically, (a) 2, (c) 3, 11 A dihybrid test cross-yielding a result of 1:1:1:1 ratio, is indicative of:, (a) Homozygous condition of the F, dihybrid., (b) 4 different types of F, generation dihybrids., th ntaka (ET 2008), (NCERT Exemplar), progeny, the disease is:, (a) Autosomal dominant, (c) Sex-linked dominant, (b) Autosomal recessive, (d) Sex-linked recessive
Page 5 :
(b) all organism possessing same type of chromosomes, blind woman will produce which of the following types, 22. A marriage between normal visioned man and colour, GRB New Era Biology: Class-X, 262, (e) monoploidy, (c) 4 different typesiof gametes produced by the parent., (d) 4 different types of gametes produced by the F, dihybrid., of offspring?, (a) Normal sons and carrier daughters, (b) Colour-blind sons and carrier daughters, (c) Colour-blind sons and 50% carrier daughters, (d) 50% colour-blind sons and 50% daughters, 23. Excessive growth of hair on the pinna is a feature found, only in males because:, (a) The female sex hormone estrogen suppresses the, (CPMT 2008), 12. When a dihybrid cross is fit into a Punnett square with 16, boxes, the maximum number of different phenotypes, available are:, (Kerala PMT 2008), (b) 4, (d) 12, (a) 2, (c) 8, (e) 16, 13. How many types of gametes are obtained from a plant of, genotype TTRr?, (a) 2, (c) 4, 14. In F, generation, quantitative inheritance 1: 4: 6: 4: 1 is, (Karnataka CET 2008), (VITEEE 2008), (c) 1, (d) many, character in females., (b) The gene responsible for the character is present on, the Y chromosome only., (c) The gene responsible for the character is recessive in, females and dominant only in males., (d) The character is induced in males as males produce, obtained instead of:, (a) 9:3:3:1, (c) 7:4:1:4, 15. A true breeding plant producing red flowers is crossed, with a pure plant producing white flowers. Allele for red, colour of flower is dominant. After selfing the plants of, first filial generation, the proportion of plants producing, white flowers in the progeny would be:, (DPMT 2008), (b) 8:6:4:1, (d) 6:6:4:7, testosterone., 24. Inheritance of blood group is a condition of:, (Kerala PMT 2008, 09; JKCMEE 2008), (B) Incomplete dominance, (D)Multiple gene, (b) В, D, (d) A, D, (A) Co-dominance, (C)Multiple allelism, (a) A, B, (c) В, С, (е) А, С, 25. A man of 'A' blood group marries a woman of 'AB, blood group. Which type of progeny would indicate that, man is heterozygous?, (a) O, (c) A, 26. In gynandromorphs:, (a) all cells have XX genotype, (b) all cells have XY genotype, (c) all cells with genotype XXY, (d) some cells of body contain XX and some cells wi, genotype XY, (Karnataka CET 2009), (b) 1/2, (d) 1/4, (а) 1/3, (c) 3/4, 16. In which one of the following, complementary gene, interaction ratio of 9:7 is observed?, (Kerala PMT 2009), (b) Four 'O' clock plant, (d) Feather colour in fowl, (a) Flower colour in pea, (c) Coat colour in mouse, (e) Fruit shape in Shepherd's purse, 17. The distance between the genes a, b, c and d in mapping, units are a -d= 3.5; b-c 1; a-b 6; c-d 1.5; a-c 5., Find out the sequence of arrangement of these genes:, (JIPMER 2008), (b) В, (d) AB, (ВСЕСЕ 2008), (Kerala PMT 2008), (а) аcdb, (c) adcb, (e) adbc, 18. What name has been assigned to the genus produced by a, cross between cabbage and radish?, (b) abcd, (d) acbd, 27. Persons suffering from sickle-cell anaemia normally, not suffer from:, (a) cholera, (c) malaria, 28. Sex chromosomes of a female bird are represented, (WB-JEE 2015), (Uttarakhand PMT 2008), (b) Bursa pastoris, (d) Raphano brassica, (b) hepatitis, (d) high blood pressure, (a) Secale, (c) Lysogenicophyll, 19. Which of the following shows triploid nature in, flowering plants?, (a) Embryo, (c) Endosperm, 20. A mutation which substitutes one purine base with, another purine base is called:, (a) transition, (c) transduction, 21. Down's syndrome is an example of:, (Kerala PMT 2008), (a) XO, (c) XY, (e) ZW, 29. In a pedigree analysis, -CO represents:, (b) XX, (d) ZZ, (Odisha JEE 2008), (b) Megaspore, (d) Microspore, (Kerala PMT 2008), (b) affected parents, (d) non-identical twins, (VITEEE 2008), (a) siblings, (c) unrelated mating, (e) consanguineous mating, 30. Karyotype is:, (a) division of nucleus, (b) transversion, (d) transfection, (СРМТ 2009), (a) triploidy, (c) polyploidy, (Kerala PMT 2008), (b) polyteny, (d) aneuploidy
