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BRILLIANCE COLLEGE, Answers, 1) Answer: A, , or, x= 25/20= = 5/4, , According to the question,, , So, 200% of 5/4= 200/100× 5/4= 10/4= 2.5, , Let the required number be x, , Hence, the correct option is A., , 12.5% of x = 12.5×1.25, , 2) Answer: C, , or, 25x/2 = 25/2 × 25/20, , Let the number be X.

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According to the question,, , Hence, the correct option is A., , 75%x + x = 35%×200, , 5) Answer: D, , Or, 3x/4 +x = 7/20×200, , As we know that successive percentage of a and b = (a +, b + ab/100)%, , Or, 7x/4 = 70, Or, x = 70×4/7 = 40, Hence, the correct option is C., 3) Answer: A, As per the given data in question,, x% of y = z% of w, Or, x×y/100 = zw/100, Or, x×y = zw, Or, x= zw/y, Now,, 75%×x = zw/y, Or, 3/4×x = zw/y, Or, x = 4zw/3y, Hence, the correct option is A., 4) Answer: A, According to the question,, X= 33.33% =100/3 %, and Y = 6.75% = 25/4 %, By using the % change method = (x – y – xy/100), =( 100/3 - 25/4 - 100×25/1200), = ( 100/3 - 25/4 - 25/12), = (400 – 75 - 25/12), = 300/12 = 25% (increase), , According to the given data in the question,, Here, a =6.66% = 100/15= 20/3 and b= 3.33%= 10/3, Now,, (20/3+ 10/3 + 20×10/900)% = (20/3 + 10/3 + 2/9) %, = 92/9%, Hence, the correct option is D., 6) Answer: A, As per given data in the question,, 25% of (A + B) = 5/2(A – B), Or,1/4×(A + B) = 5/2(A – B), Or, A + B = 10(A – B), Or, 11B = 9A, Or, A/B = 11/9, So, Required % = (11 – 9)×100/9% = 200/9%, Hence, the correct option is A., 7) Answer: B, According to the question,, Successive change in % for a and b, = a + b + (ab/100), Here,, a = - 6.75% and b = -12.5%

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Now,, , 10) Answer: B, , -6.75 – 12.5 + 6.75×12.5/100, , According to the education total investment of Mohan on, all the things,, , = -19.25 + 84.375/100, = -19.25000 + 0.84375, , 15% on his food + 10% on cloth + 12% on the other, households + 18% on education and health, , = - 18 .40625% (Decrease), , = 55%, , Hence, the correct option is B., 8) Answerer: C, , Rest amount on the life insurance policy as a savings =, (100 – 55)% = 45%, , According to the question,, , Now,, , 25% of X is added to the 80% of X then the result, becomes to 30% of 70,, , Yearly or 12 months income of Mohan = 144,000, , 25% of x + 80 % of x = 30 % of 70, Or,x/4 +4 x/5 = 30×300/100 = 21, , Therefore, monthly savings, =12000×45% = 12000×9/20, = 5400, , Or,5x + 16x/20 = 21, , Hence, the correct option is B., , 21x = 21×20, , 11) Answer: A, , So, x = 20, , According to the question,, , Now,, , Required percentage =(x/(100-x))x100, , Value of 300% of 20 = 300×20/100 = 60., , =(37.5/(100 - 37.5))×100 = 60% more than X, , Hence, the correct option is C., , Hence, the correct option is A., , 9) Answer: D, , 12) Answer: C, , According to the question,, , As we know that if x % decreases with changes in the, price of any commodities then x/(100 - x) % increases, with changes it's consumption then there was no effect, on it., , (200 + 100)% of X = (100 – 75)%of Y, Or, 300% of X = 25% of Y, Or, 300X = 25Y, Or, 12X=Y, Hence, the correct option is D., , So, monthly income = 144,000/12= 12000, , So, Here x = 62.5%, Required increases in % = [62.5/(100 – 62.5)]x100, = (62.5 × 100/37.5) = 166.66%, Hence, the correct option is C.

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13) Answer: B, Let the basics, fixed price of kerosene = 100, According to the question,, Increased by 12.5% then decreased by 25% then again, decreased by 20%,, , The number of persons who take both coffee and tea (X), = 10% of 360 = 36, The number of persons who take either coffee or tea, = C + T - X = 108 + 72 – 36 = 146, Hence, the correct option is A., , 100×(1 + 25/200)(1 – 25/100)(1 – 20/100), , 16) Answer: A, , = 100×( 9/8)(3/4)(4/5), , In such cases, there is always decrease., , = 67.5%, , Given that, x=(common increase or decrease)=12%, , Overall, it becomes 67.5% from 100%., , According to the formula, , Hence, the correct option is A., , Decrease percentage=x2/100%, , 14) Answer: A, , =122/100%, , As we know that successive % of - a and b is [-a + b –, (a×b) /100)], , =1.44%, , According to the question,, Here, a= +22.5 & b= - 22.5, Now,, [22.5 – 22.5 - (22.5×22.5)/100] %, , 17) Answer: B, By the equating rule of, Passing marks or % is equal to, Passing marks or % because in both of the cases full, marks and pass mark are the same., Let, Full marks = 100%,, , = (0 - 506.25/100)%, , So, Passing marks for Rashmi = Passing marks for, Shyamali, , = - 5.0625%, , 32.5% + 20= 37.5% - 10, , Hence the correct option is A., , Or, 5% = 30, , 15) Answer: A, , Or, 1% = 6, , According to the question,, , Or, 100% = 600., , The number of persons who take only coffee(C) = 30%, of 360 = 108, , Hence, the correct option is B., , The number of persons who take only tea (T) = 20 % of, 360 = 72, , 18) Answer: B, According to the question,

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Since, sales tax and profit can be calculated on, manufacturing cost,, Therefore single % change = 12.75% +12.25% = 25%,, Now,, Manufacturing cost×(1+25%), , A= 125×(100 – 20)/100 = 125×80/100 = 100, And C gets 20 % less marks than D, D= 100×100/80 = 125, Now,, , Manufacturing cost×1.25= 15675, , Ratio of marks of A: B: C: D = 100: 125: 100: 125 = 4:, 5: 4: 5, , Manufacturing cost=15675/1.25= 627×100 = Rs.62700, , A gets 420 marks out of 600;, , Hence, the correct option is B., , A = 4k and A = 420; k = 420/4 = 70, , 19) Answer: C, , Therefore, D = 5k = 5×70 = 350, , According to the question, , % marks getting by D = (Marks obtained by D/ Full, marks)×100, , Let, A person used to purchase x litre at price Rupees, 100/- before reduction. Then after reduction, he gets 13.5, litres more in added with x litres for the same price is, 100/-, , = 350×100/600 = 58.33%, Hence, the correct answer is A., , Now,, , 21) Answer: D, , A reduction of 27% in Rupees 100 that is Rupees 27/enables him to buy 13.5 litres more., , Let the total number of votes polled is x, , Therefore, the reduced price is Rupees 27/- for 13.5 litres, , (100 – 72)% of x = 28% of x, , So, the reduced price per litres = 27/13.5= 2 Rupees per, litre., , So, 72% of x - 28% of x = 880, , Now, according to the question;, , Or, 44% of x = 880, Hence, The correct option is C., Or, x = 880×100/44 = 2000, 20) Answer: A, Number of polled votes is 2000, Let the marks of C is 100., Hence, the correct option is D., According to the question,, 22) Answer: C, B gets 25% more marks than C, According to the question,, B= (100 + 25) = 125, A gets 20 % less marks than B, , As we all know that if the concept of % in removing the, % part from the whole and all times removing part of %

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is on the base of always new % on rest value of, remaining %, , Number of students who solve four questions = 30% of, 80 = 24%, , Then,, , Remaining = 80 – 40 = 40%, , Monthly, savings of Madhu can be,, , Number of students who solve two questions = 15%, , Value×{100 – a/100}×{100, c/100}×{100 – d/100}, , –, , b/100)}×{100, , –, , = 12000×{(100 – 22)/100}{(100 – 20)/100)}{(100 –, 30/100)}{(100 – 20/100)}, = 12000×(78/100)×(80/100)×(70/100)×(80/100), , Number of students who solve three questions = 40 – 15, = 25%, According to the question,, 25% = 400, 25×4% = 400×4, , =12000 × 78 × 8 × 7 × 8/100 = Rupees 4193.28 /- is, monthly savings of Madhu., , Or, 100% = 1600, , Hence, the correct option is C., , So, Number of students who solve total questions, , 23) Answer: D, , = 10% of 1600 = 160, , According to the question,, , Hence, the correct option is A., , The successive percentage value of x and y, , 25) Answer: A, , X + y + xy/100 = M, , Let that the value of both will be equal in "t" years., , Or, M – x – y = xy/100, , 34300(1 + 30/100)t = 29700(1 – 30/100)t,, , Or, M – x = y + xy/100, , Or, (13/10)t×(10/7)t = (219700/34300), , Or, M – x = y(1 + x/100) = y(100 + x)/100, , Or, (13/7)t = 2197/343 = 13×13×13/7×7×7 = (13/7)3, , Hence, the correct option is D., , Or, t = 3 years., , 24) Answer: A, , Hence, the correct option is A., , Number of students of total questions solved = 10%, , 26) Answer: B, , Number of students who can't do any questions = 10%, , Let the number = 100, , Remaining = 100 – 10 – 10 = 80%, , As per the question,, , Number of students who solve only one question = 20%, of 80 = 16%, , 700/6-600/7=(4900-3600)/42, =1300/42= 30.95%, Hence, the correct option is B.

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27) Answer: A, , Panchayat leader = 847, , Let the runs scored by Abhay = A and Ballu = B, , Hence, the correct option is C., , According to the question,, , 30) Answer: B, , 20% of A – 24% of B = 40% of B, , Let the Marked Price = 100, , Or, 0.2A – 0.24B = 0.4B, , Cost after 5% discount = 95, , Or, 0.2A = 0.4B + 0.24B, , Cost after 18% GST = 95+(18% of 95) = 112.1, , Or, 0.2A = 0.64B, , As per the question,, , Or, A/B = 64/20, , 112.1 : 100: : 3363 : Marked Price, , Or, A : B = 16 : 5, , Marked price = 3363×100/112.1 = 3000., , Hence, the correct option is A., , Hence, the correct option is B., , 28) Answer: A, , 31) Answer: D, , Total discount offered on the bag, , Percentage of Left out bananas = 100% - 37.5% = 62.5%, , = (15 + 18 - (15×18)/100)%, , As per the question,, , =(33 – 2.7)%, , 100/62.5×500 = 800 bananas, , =3 0.3%, , Hence, the correct option is D., , Hence, the correct option is A., , 32) Answer: C, , 29) Answer: C, , Let the original cost = 100, , Total number of voters = 2500 – 183 = 2317, , So,, , Let the third candidate got 100 votes, , 100 × 122/100 × 78/100 = 95.16, , So, the second candidate got 100 + (10% of 100) = 110, votes, , Cost after Diwali offer= 95.16, i.e. 100 – 95.16 = 4.84 less than the original, , So, first candidate (Panchayat leader) got 110 + (10%of, 110) = 121 votes, , Hence, the correct option is C., , Total votes = 100 + 110 + 121= 331, , 33) Answer: B, , 331 : 121 : : 2317: Panchayat leader, , According to the question,, , Or, 331/2317=121/ Panchayat leader, , Maximum marks = (220 + 25)×100/35 = 700

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Hence, the correct option is B., , Or, B = 3A×55.55%, , 34) Answer: B, , Hence, the correct option is C., , According to the question,, , 38) Answer: A, , Numbers having 3 or 7 in the unit digit = 3, 7, 13, 17, , The original fraction is 1/2 ×(100+50)/(100+20), , Percentage= 4/20×100 = 20%, , =1/2×150/120 = 5/8, , Hence, the correct option is B., , Hence, the correct option is A., , 35) Answer: A, , 39) Answer: B, , As we know that, if percentage population is increased, by a %, b% and c % then present population can be find, from last three years, , According to the question,, , =, Population, before, years×(100+a)/100×(100+b)/100×(100+c)/100, , Or, 100/3% × 69 + 28% × 25 = x% × 120, , three, , 33 1/3% of 69 + 28% of 25 = x% of 120, , Or, 23+7 = x% × 120, , So,, , Or, x=25, , 220000×104/100×105/100×105/100 =252252, , Hence, the correct option is B., , Hence, the correct option is A., , 40) Answer: B, , 36) Answer: D, , According to the question,, , According to the question,, 1/5: 1/4= 4/5= (4/5 )x100 = 80%, , Let 'x' kgs of dry peas are obtained from the 50 kgs of, fresh peas, , Hence, the correct option is D., , => 50×5/100 =35x/100, , 37) Answer: C, , => x = 7.14 kgs, , According to the question,, , Hence, the correct option is B., , A = 60% of B, , 41) Answer: A, , Or, A = 60/100 ×B, , According to the question,, , Or, 3A = 180/100× B, , (60% of 180) – (3/5 of 30), , Or, (3A×100)/180 = B, , = 108 – 18, , Or, B = 3A×100/180×100%, , = 90

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Hence, the correct option is A., , Hence, the correct option is C., , 42) Answer: B, , 46) Answer: C, , Required % = 100- (10+16+13) = 100-39 = 61%, according to the below mentioned Venn diagram., , According to the question,, √49/23 = 7/8×100% = 87.5%, Hence, the correct option is C., 47) Answer: C, According to the question,, 9/10 × 7/4x = 1008, , Hence, the correct option is B., 43) Answer: D, According to the question,, 62.5% of 800 + 17% of 5500 = ? + 773, 500 + 935 = ? +773, ? = 662, Hence, the correct option is D., 44) Answer: D, According to the question,, 14/35×100% = 40%, Hence, the correct option is D., 45) Answer: C, According to the question,, Let the total land = x, 25/100×1/7×x = 30000, Or, x = 8,40,000, Hence, 40% × 840000 = 336000, , Or, x = (1008 × 10 × 4)/(9×7) = 640, So,, 640 × 45% = 288, Hence, the correct option is C., 48) Answer: B, Let the number = x, According to the question,, 12.5% of x = 11, Or, 12.5/100×x = 11, Or, x = 88, Hence, the correct option is B., 49) Answer: C, Let the Marked Price of item = 100, Cost after 30% discount = 70, Cash back = 10% of 7 = 7, Total discount=30+7 = 37 or 37%, Hence, the correct option is C.

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50) Answer: D, , x is less than y = (difference/y)×100%, , According to the question,, , = 264/1111×100 = 23.76%, , Difference between y and x= 1111 – 847 = 264, , Hence, the correct option is D.