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= 5.07 inches, Therefore, to make the scale on kilometer, the denominator is, 1 centimeter on the map, = 150,000 cm i.e. 1.5 km on the ground, will reveal 15 cm on the map, 15 * 15 = 22.5 kilometers on the ground, The nearest suitable number of 22.5 is 20, Hence, the length of the line representing 20 km will be, 22.5 km on the ground, = 15 cm, 20 kilometers on the ground, 15*20/22.5 on the map, =13.33 cm, Question 2, 1/31,680 Construct a comparative scale for a map on a representational fraction to read, distances up to one furlong and 1 hectometer., solution, 1 inch on the map, = 31,680 inches on the ground, 31,680/63,360=1/2 mile, 6 inches on the map, = 6*1/2=3 miles on the ground, A straight line 6 inches long, divided into three parts, each 1 part will represent a distance, of 1 mile, reveals 1 cm, =31,680 cm =31,680/100,000 km, will reveal 15 cm, 15*31680/100,000=4.75 cm, 4.75 cm The length of the scale as a whole number, 4.75 km appears, =15 cm, reveals 4 cm, =15*4/4.75=12.63 cm, , Question 3, 1/36 Construct a comparative scale for a map made on the representational fraction in, which distances can be read in yards-feet and meters-decimeters.

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solution, reveals 1 inch, = 36 inches = 1 yard, Reveals 5 inches = 5 yards, On dividing a 5 inch long line into 5 divisions, each part will reveal a distance of 1 yard, and on doing three divisions again in the first part, each subdivision shows a distance of, 1 foot., Meter — for the decimeter scale, the denominator fraction 1/36, Reveals 1 cm = 36 cm, reveals 15 cm, = 36*15/100=5.4 meters, Length of scale as rounded off to 5 as 5.4, Reveals 5.4 m = 15 cm, reveals 5 meters, 15*5/5.4=13.88 cm, So, dividing a 13.88 cm long line into 5 parts, each part will represent 1 metre., (II) Time Scale, Time scale is also called comparative scale of time and distance because by this, measure, along with reading the distance in the map, time can also be found to cover, those distances at a certain speed or speed, the composition of measuring time and, other The composition of the comparative scale is divided into two parts., 1 In contrast to the comparative scale showing distance in different units, the number of, primary and divisions showing the measure of time and distance are the same., 2 Different measurements are not made in measuring the opposite time of the, comparative scale, whereas both the time and distance are displayed on the same, graphical scale., Question 1, Construct a time measure for a map made on the fraction representing 1/100,00 for a, student moving at a speed of 3 km per hour, solution, Represents 1 cm = 100,000 cm = 1 kilometer, Reveals 15 centimeters = 15 kilometers, The time taken to cover a distance of 15 km is determined as follows, Covers a distance of 3 km = in 1 hour, will cover a distance of 15 kms, 15/3 = in 5 hours, A 15 cm long line will show a distance of 15 km or a time of 5 hours, dividing this line into, five easy parts, each part will represent a distance of 3 km or 1 hour, dividing the first part

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of the left and the left into three parts Each character part is the distance of a number or, the time of 20 minuteswill displayQuestion 2 A comparative scale of time and distance, has been made for a scout team moving at a speed of 1 mph, while the map's, representational fraction is an oblique 63,360. The distance to be covered in 4 hours 15, minutes during the scout team in the scale Display it., solution, Represents 1 inch =63360 inch = 1 mile, Will reveal at 6 inches = 6 miles, So 1 mile is covered, = in 1 hour, 6 miles covered = in 6 hours, A 6 inch long line will show a distance of 6 miles and a time of 6 hours, on dividing this, line into 6 parts, each part will reveal a mile or 1 hour, , Question 3, Construct a time measure for a scooter driver traveling at a speed of 30 kmph when the, map's representational fraction is 1/5000000. Show the distance covered by the, scooterist in 18 hours., according to the denominator fraction, Reveals a distance of 1 cm, = 5000000 centimeters i.e. 50 kilometers, will reveal at a distance of 15 cm, 15 * 50 = 750 kms, So the scooter driver goes 30 km = in 1 hour the scooter driver will go 750/30 = in 25, hours