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Chemical Kinetics, , Codes, , A B G.D Ai?aiB G 43:D, (J3 4 Qi 1 (b) 3 4 1 2, ()4 3 Baio (d) 4 3 1 2, , 30 What function of [x] , plotted against time, will give, a straight line for a second-order reaction ?, (a) [x] (b) [x]?, , 1, (d) —, [x], , 31 For the first order reaction (A = Ape!) and, , Tyy =F) After two average lives, concentration of, the reactant is reduced to, , (a) 25%, , (c) log [x], , 100, , 0) 75% (Ry gq 1g,, e e, , 32 A first order reaction is 50% completed in, 1.26 x 10's. How much time would it take for, 100% completion? [NCERT Exemplar], (a) 1.26 x 10'5 5 (b) 2.52 x 10!4 s, (c) 2.52 x 1078 s (d) Infinite, , 33 Match order of the reaction (in Column I) with the, unit of rate constant (in Column Il),, , , , Column I Column II, (Order) (Unit), , A. Zeroth 1. LV? mol? gs, B. First 2. L mol7\3}!, C. Second 3. mol Ls"!, D. Third 4. s!, _ Codes, , AS MBuer Gar'D, AveleB keiGingD, 3 4 nf A (b) 3 4 1 2, , (4 3 ib til (d) 4 3 1 2, 34 A reaction of first order completed 90% in 90 min,, hence, it is completed 50% in approximately, (a) 50min (b) 54min (c) 27min (d) 62 min, 35 The rate constant for the reaction,, 2N,0,; —>4NO, +0,, is3x Ox 107° sl. If the rate at a given time is, 2.40x 107° mol L7! s~, then concentration of N20;, at that time is, (a) 1.4 (b) 1.2 (c) 0.04 (d) 0.8, 36 Rate constant of a first order reaction is, 0.0693 min™'. If we start with 20 mol La,, it is reduced to 2.5 mol L~! in, , (a) 10 min (b) 20 min, (c) 30 min (d) 40 min, , 37 For the reaction, A(g) —> B(g) + C(g), d[A], rate law is— —— =k [A, a di [A], At the start pressure is 100 mm and after 10 min,, pressure is 120 mm. Hence, rate constant (min™) is, 2.303, , , , 2.303 6, a) log— b), ~——.log 5, e 10 as ml 10 oe, 2.303 5 2.303 5, peermeons LEpe A) goes Ig, I 10 ey 7 10 8, , 38 T; (Half-life period) of first order reaction is 10 min., , Starting with 10 mol L™, rate after 20 min is, (a) 0.0693 min™! (b) 0.0693 x 2.5 min=!, (c) 0.0693 x 5 min! (d) 0.0693 x 10 min=!, 39 Rate constant of a reaction with a virus is, 3.3x 10 s~!, Time required for the virus to, become 75% inactivated is, (a) 35 min (b) 70 min, (c) 105 min (d) 17.5 min, 40 Match order of the reaction (in Column I) with the, corresponding rate constant (in Column II)., , Column I Column II, (Order) (Rate constant), Bes Ne 1, A. Zeroth ib atl(a-xe aw, , B. First, , C. Second 3, , , , D. Third 7% k= Hog. ( - ], t a-x, , EOE 9 BRND AIO DONATI, Codes, , AGB GeeD, (a3 4 Ziel, (b)3 4 12, (c),43288.0 =2\ ex, d)4. 3 14 12,, , 41 Consider the following statements., Statement I Order and molecularity are same., , Statement II Order is determined experimentally, and molecularity is the sum of the stoichiometric, coefficient of rate determining elementary step., Choose the correct option., , (a) Only statement I is correct, , (b) Only statement II is correct, , (c) Both the statements are correct, , (d) None of above statement are correct