Page 1 : CHAPTER 9: COORDINATION COMPOUNDS, 1) With the help of VBT explain the hybridisation, magnetic property, and geometrical shape of (a) Hexa ammine cobalt (III) ion [Co(NH3)6 ]3+, The outer shell electron configuration of Co3+ ion is represented as, follows: [Ar] 3d6 4s0, , When strong field ligand NH3 approaches Co3+ ion, electron pairing takes, place:, 2, , d sp hybrid, , xx, , xx, , xx, , xx, , 2) Hexafluoridocobaltate (III) ion [CoF6]3-:, The outer shell electron configuration of Co3+ ion is represented as, follows: [Ar] 3d6 4s0, , When weak field ligand F- approaches Co3+ ion, electrons pairing does, not takes place, Now Co3+ ion under goes sp3d2 hybridisation forming 6 hybrid orbitals, and geometry of the complex is octahedral, , 3d, , xx, , xx, , xx, , dsp2, , 3d, [Ni(CN)4], , 2-, , xx, , xx, , xx, , xx, -, , Six pairs of electrons from six F molecules, , 4d, , In these hybridized orbitals 6 pair of electrons from 6 F- ions occupy, forming paramagnetic compound., i) Hybridisation: sp3d2, ii) Magnetic property: Paramagnetic, iii) Geometrical shape: Octahedral, 5) Which set of d-orbitals of metal ion/atom experience more, repulsion in octahedral field created by the ligand?, Ans: eg set or set of dx2- y2 and dz2 orbitals, , Ni, , 10) Write cis and trans form of [Co(NH3)4Cl2]+, , 4p, xx, , (4) Tetrachlorido(II)ion [NiCl4]2-:, Nickel is in +2 oxidation state and has electronic configuration 3d8., 3d, , Six pairs of electrons from six NH 3 molecules, , xx, , 4p, , 1. HClO:, Ni 3d, Hypoclorous, When strong ligand CN- approaches Ni2+, electronacid, pairing takes, 2, place: The vacant orbitals involve in dsp hybridisation., Cl-OH, In these hybridized orbitals 4 pair of electrons from 4 CN- ions occupy, , 2+, , 9) Write cis and trans form of [Pt(NH3)2Cl2], complex, , 8, , xx, , In these hybridized orbitals 6 pair of electrons from 6 NH3 molecules, occupies forming diamagnetic compound., i) Hybridisation: d2sp3, ii) Magnetic property: Diamagnetic, iii) Geometrical shape: Octahedral, , xx, , 4s, , 3d, , 2+, , i) Hybridisation: dsp2, ii) Magnetic property: Diamagnetic, iii) Geometrical shape: Square planar, , 3, , Now Co3+ ion under goes d2sp3 hybridisation forming 6 hybrid orbitals, and geometry of the complex is octahedral., xx, , (3) Tetracyanidonickelate(II) ion [Ni(CN)4]2-:, Nickel is in +2 oxidation state and has electronic configuration 3d8., , 4s, , 11) Write Geometrical isomers (cis and trans), of [CoCl2(en)2], , 4p, , 8, , 3d, , When weak ligand Cl- approaches Ni2+, electron pairing does not take, place: The vacand orbitals involve in sp3 hybridisation., [NiCl4], , xx, , xx, , trans, , 12) Write Optical isomers (d and l) of [Co(en) 3]3+, , sp3, , 2-, , Cis, , xx, , xx, , sp3, , i) Hybridisation: sp3, ii) Magnetic property: Paramagnetic, iii) Geometrical shape: Tetrahedral, 6) What is linkage isomerism? Give an example., Ans: Coordination compounds with same molecular formula but, differ with ligating atom attached to central metal. (This type of 13) State any three postulates of Werner’s, isomerism arises when ambidentate ligands are present), theory of Coordination compounds., Ex: [Co(NH3)5(NO2)]Cl2 and [Co(NH3)5(ONO)]Cl2, Ans: 1. In coordination compounds metals show, two types of linkages (or valences)-primary and, 7) What is ionisation isomerism? Give an example., secondary., Ans: Coordination compounds with same molecular formula but 2. The primary valences are normally ionisable, produce different ions in water., and are satisfied by negative ions., Ex; [Co(NH3)5SO4]Br and [Co(NH3)5Br]SO4, 3. The secondary valences are non ionisable., These are satisfied by neutral molecules or, 8) What is hydrate or solvate isomerism? Give an example., negative ions present as ligands, Ans: Coordination compounds with same molecular formula but 4. The secondary valence is equal to the, differ with number of water molecules present as ligand., coordination number, Ex; [Cr(H2O)6]Cl3 and [Cr(H2O)5Cl]Cl2.H2O, 5. The secondary valences are responsible for, definite geometry of the complex.